%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN400+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:38 EDT 2023

% Result   : Theorem 3.32s 3.69s
% Output   : Proof 3.32s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.10  % Problem    : SYN400+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.11  % Command    : duper %s
% 0.13/0.30  % Computer : n032.cluster.edu
% 0.13/0.30  % Model    : x86_64 x86_64
% 0.13/0.30  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.30  % Memory   : 8042.1875MB
% 0.13/0.30  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.30  % CPULimit   : 300
% 0.13/0.30  % WCLimit    : 300
% 0.13/0.30  % DateTime   : Sat Aug 26 20:34:44 EDT 2023
% 0.13/0.31  % CPUTime    : 
% 3.32/3.69  SZS status Theorem for theBenchmark.p
% 3.32/3.69  SZS output start Proof for theBenchmark.p
% 3.32/3.69  Clause #0 (by assumption #[]): Eq (Not (Iff (Iota → p) p)) True
% 3.32/3.69  Clause #1 (by clausification #[0]): Eq (Iff (Iota → p) p) False
% 3.32/3.69  Clause #2 (by clausification #[1]): Or (Eq (Iota → p) False) (Eq p False)
% 3.32/3.69  Clause #3 (by clausification #[1]): Or (Eq (Iota → p) True) (Eq p True)
% 3.32/3.69  Clause #4 (by clausification #[2]): Iota → Or (Eq p False) (Eq (Not p) True)
% 3.32/3.69  Clause #5 (by clausification #[4]): Or (Eq p False) (Eq p False)
% 3.32/3.69  Clause #6 (by eliminate duplicate literals #[5]): Eq p False
% 3.32/3.69  Clause #7 (by clausification #[3]): Iota → Or (Eq p True) (Eq p True)
% 3.32/3.69  Clause #8 (by eliminate duplicate literals #[7]): Eq p True
% 3.32/3.69  Clause #9 (by superposition #[8, 6]): Eq True False
% 3.32/3.69  Clause #10 (by clausification #[9]): False
% 3.32/3.69  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------