%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : SYN399+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 06:10:41 EDT 2022

% Result   : Theorem 0.21s 0.38s
% Output   : CNFRefutation 0.21s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    1
% Syntax   : Number of formulae    :   11 (   4 unt;   0 def)
%            Number of atoms       :   28 (   0 equ)
%            Maximal formula atoms :    8 (   2 avg)
%            Number of connectives :   27 (  10   ~;   8   |;   3   &)
%                                         (   4 <=>;   2  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    8 (   3 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   2 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   1 con; 0-0 aty)
%            Number of variables   :   10 (   4 sgn   6   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(kalish223,conjecture,
    ( ! [X1] :
        ( f(X1)
      <=> p )
   => ( ! [X2] : f(X2)
    <=> p ) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',kalish223) ).

fof(c_0_1,negated_conjecture,
    ~ ( ! [X1] :
          ( f(X1)
        <=> p )
     => ( ! [X2] : f(X2)
      <=> p ) ),
    inference(assume_negation,[status(cth)],[kalish223]) ).

fof(c_0_2,negated_conjecture,
    ! [X3,X5] :
      ( ( ~ f(X3)
        | p )
      & ( ~ p
        | f(X3) )
      & ( ~ f(esk1_0)
        | ~ p )
      & ( f(X5)
        | p ) ),
    inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_1])])])]) ).

cnf(c_0_3,negated_conjecture,
    ( f(X1)
    | p ),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_4,negated_conjecture,
    ( p
    | ~ f(X1) ),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_5,negated_conjecture,
    ( ~ f(esk1_0)
    | ~ p ),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_6,negated_conjecture,
    p,
    inference(csr,[status(thm)],[c_0_3,c_0_4]) ).

cnf(c_0_7,negated_conjecture,
    ( f(X1)
    | ~ p ),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_8,negated_conjecture,
    ~ f(esk1_0),
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_5,c_0_6])]) ).

cnf(c_0_9,negated_conjecture,
    f(X1),
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_7,c_0_6])]) ).

cnf(c_0_10,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_8,c_0_9])]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13  % Problem  : SYN399+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.14/0.35  % Computer : n020.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % WCLimit  : 600
% 0.14/0.35  % DateTime : Mon Jul 11 14:02:28 EDT 2022
% 0.14/0.35  % CPUTime  : 
% 0.21/0.38  # No SInE strategy applied
% 0.21/0.38  # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.21/0.38  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.21/0.38  #
% 0.21/0.38  # Presaturation interreduction done
% 0.21/0.38  
% 0.21/0.38  # Proof found!
% 0.21/0.38  # SZS status Theorem
% 0.21/0.38  # SZS output start CNFRefutation
% See solution above
% 0.21/0.38  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------