TSTP Solution File: SYN395+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : SYN395+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 06:10:40 EDT 2022
% Result : Theorem 0.13s 0.36s
% Output : CNFRefutation 0.13s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 1
% Syntax : Number of formulae : 8 ( 4 unt; 0 def)
% Number of atoms : 18 ( 0 equ)
% Maximal formula atoms : 4 ( 2 avg)
% Number of connectives : 16 ( 6 ~; 2 |; 2 &)
% ( 0 <=>; 6 =>; 0 <=; 0 <~>)
% Maximal formula depth : 6 ( 3 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-1 aty)
% Number of functors : 1 ( 1 usr; 1 con; 0-0 aty)
% Number of variables : 11 ( 2 sgn 4 !; 4 ?)
% Comments :
%------------------------------------------------------------------------------
fof(kalish202,conjecture,
( ! [X1] :
( f(X1)
=> g(X1) )
=> ( ? [X2] : f(X2)
=> ? [X3] : g(X3) ) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',kalish202) ).
fof(c_0_1,negated_conjecture,
~ ( ! [X1] :
( f(X1)
=> g(X1) )
=> ( ? [X2] : f(X2)
=> ? [X3] : g(X3) ) ),
inference(assume_negation,[status(cth)],[kalish202]) ).
fof(c_0_2,negated_conjecture,
! [X4,X6] :
( ( ~ f(X4)
| g(X4) )
& f(esk1_0)
& ~ g(X6) ),
inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_1])])])]) ).
cnf(c_0_3,negated_conjecture,
( g(X1)
| ~ f(X1) ),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_4,negated_conjecture,
~ g(X1),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_5,negated_conjecture,
f(esk1_0),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_6,negated_conjecture,
~ f(X1),
inference(sr,[status(thm)],[c_0_3,c_0_4]) ).
cnf(c_0_7,negated_conjecture,
$false,
inference(sr,[status(thm)],[c_0_5,c_0_6]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYN395+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.33 % Computer : n018.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Mon Jul 11 13:24:14 EDT 2022
% 0.13/0.33 % CPUTime :
% 0.13/0.36 # No SInE strategy applied
% 0.13/0.36 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.13/0.36 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.13/0.36 #
% 0.13/0.36 # Presaturation interreduction done
% 0.13/0.36
% 0.13/0.36 # Proof found!
% 0.13/0.36 # SZS status Theorem
% 0.13/0.36 # SZS output start CNFRefutation
% See solution above
% 0.13/0.36 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------