TSTP Solution File: SYN391+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYN391+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:35 EDT 2023

% Result   : Theorem 3.49s 3.74s
% Output   : Proof 3.49s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYN391+1 : TPTP v8.1.2. Released v2.0.0.
% 0.13/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n013.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 18:55:47 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.49/3.74  SZS status Theorem for theBenchmark.p
% 3.49/3.74  SZS output start Proof for theBenchmark.p
% 3.49/3.74  Clause #0 (by assumption #[]): Eq (Not (And (And (Or p1 p2) (Or (Not p1) p2)) (Or p1 (Not p2)) → Not (Or (Not p1) (Not p2)))) True
% 3.49/3.74  Clause #1 (by clausification #[0]): Eq (And (And (Or p1 p2) (Or (Not p1) p2)) (Or p1 (Not p2)) → Not (Or (Not p1) (Not p2))) False
% 3.49/3.74  Clause #2 (by clausification #[1]): Eq (And (And (Or p1 p2) (Or (Not p1) p2)) (Or p1 (Not p2))) True
% 3.49/3.74  Clause #3 (by clausification #[1]): Eq (Not (Or (Not p1) (Not p2))) False
% 3.49/3.74  Clause #4 (by clausification #[2]): Eq (Or p1 (Not p2)) True
% 3.49/3.74  Clause #5 (by clausification #[2]): Eq (And (Or p1 p2) (Or (Not p1) p2)) True
% 3.49/3.74  Clause #6 (by clausification #[4]): Or (Eq p1 True) (Eq (Not p2) True)
% 3.49/3.74  Clause #7 (by clausification #[6]): Or (Eq p1 True) (Eq p2 False)
% 3.49/3.74  Clause #8 (by clausification #[3]): Eq (Or (Not p1) (Not p2)) True
% 3.49/3.74  Clause #9 (by clausification #[8]): Or (Eq (Not p1) True) (Eq (Not p2) True)
% 3.49/3.74  Clause #10 (by clausification #[9]): Or (Eq (Not p2) True) (Eq p1 False)
% 3.49/3.74  Clause #11 (by clausification #[10]): Or (Eq p1 False) (Eq p2 False)
% 3.49/3.74  Clause #12 (by clausification #[5]): Eq (Or (Not p1) p2) True
% 3.49/3.74  Clause #13 (by clausification #[5]): Eq (Or p1 p2) True
% 3.49/3.74  Clause #14 (by clausification #[12]): Or (Eq (Not p1) True) (Eq p2 True)
% 3.49/3.74  Clause #15 (by clausification #[14]): Or (Eq p2 True) (Eq p1 False)
% 3.49/3.74  Clause #16 (by clausification #[13]): Or (Eq p1 True) (Eq p2 True)
% 3.49/3.74  Clause #17 (by superposition #[16, 7]): Or (Eq p1 True) (Or (Eq p1 True) (Eq True False))
% 3.49/3.74  Clause #18 (by clausification #[17]): Or (Eq p1 True) (Eq p1 True)
% 3.49/3.74  Clause #19 (by eliminate duplicate literals #[18]): Eq p1 True
% 3.49/3.74  Clause #21 (by backward demodulation #[19, 11]): Or (Eq True False) (Eq p2 False)
% 3.49/3.74  Clause #22 (by backward demodulation #[19, 15]): Or (Eq p2 True) (Eq True False)
% 3.49/3.74  Clause #24 (by clausification #[22]): Eq p2 True
% 3.49/3.74  Clause #25 (by clausification #[21]): Eq p2 False
% 3.49/3.74  Clause #26 (by superposition #[25, 24]): Eq False True
% 3.49/3.74  Clause #27 (by clausification #[26]): False
% 3.49/3.74  SZS output end Proof for theBenchmark.p
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