TSTP Solution File: SYN387+1 by CSE---1.6
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : CSE---1.6
% Problem : SYN387+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : java -jar /export/starexec/sandbox2/solver/bin/mcs_scs.jar %s %d
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 01:45:33 EDT 2023
% Result : Theorem 0.20s 0.65s
% Output : CNFRefutation 0.20s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN387+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.13 % Command : java -jar /export/starexec/sandbox2/solver/bin/mcs_scs.jar %s %d
% 0.15/0.34 % Computer : n019.cluster.edu
% 0.15/0.34 % Model : x86_64 x86_64
% 0.15/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.34 % Memory : 8042.1875MB
% 0.15/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.34 % CPULimit : 300
% 0.15/0.34 % WCLimit : 300
% 0.15/0.34 % DateTime : Sat Aug 26 20:23:13 EDT 2023
% 0.15/0.34 % CPUTime :
% 0.20/0.60 start to proof:theBenchmark
% 0.20/0.64 %-------------------------------------------
% 0.20/0.64 % File :CSE---1.6
% 0.20/0.64 % Problem :theBenchmark
% 0.20/0.64 % Transform :cnf
% 0.20/0.64 % Format :tptp:raw
% 0.20/0.64 % Command :java -jar mcs_scs.jar %d %s
% 0.20/0.64
% 0.20/0.64 % Result :Theorem 0.000000s
% 0.20/0.64 % Output :CNFRefutation 0.000000s
% 0.20/0.64 %-------------------------------------------
% 0.20/0.65 %--------------------------------------------------------------------------
% 0.20/0.65 % File : SYN387+1 : TPTP v8.1.2. Released v2.0.0.
% 0.20/0.65 % Domain : Syntactic
% 0.20/0.65 % Problem : The Law of Excluded Middle
% 0.20/0.65 % Version : Especial.
% 0.20/0.65 % Theorem formulation : 1 proposition.
% 0.20/0.65 % English : The Law of Excluded Middle: can be quite difficult for
% 0.20/0.65 % 'natural' systems.
% 0.20/0.65
% 0.20/0.65 % Refs : [NS72] Newell & Simon (1972), Human Problem Solving
% 0.20/0.65 % : [Pel86] Pelletier (1986), Seventy-five Problems for Testing Au
% 0.20/0.65 % : [Hah94] Haehnle (1994), Email to G. Sutcliffe
% 0.20/0.65 % Source : [Hah94]
% 0.20/0.65 % Names : Pelletier 6 [Pel86]
% 0.20/0.65
% 0.20/0.65 % Status : Theorem
% 0.20/0.65 % Rating : 0.00 v2.1.0
% 0.20/0.65 % Syntax : Number of formulae : 1 ( 0 unt; 0 def)
% 0.20/0.65 % Number of atoms : 2 ( 0 equ)
% 0.20/0.65 % Maximal formula atoms : 2 ( 2 avg)
% 0.20/0.65 % Number of connectives : 2 ( 1 ~; 1 |; 0 &)
% 0.20/0.65 % ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% 0.20/0.65 % Maximal formula depth : 3 ( 3 avg)
% 0.20/0.65 % Maximal term depth : 0 ( 0 avg)
% 0.20/0.65 % Number of predicates : 1 ( 1 usr; 1 prp; 0-0 aty)
% 0.20/0.65 % Number of functors : 0 ( 0 usr; 0 con; --- aty)
% 0.20/0.65 % Number of variables : 0 ( 0 !; 0 ?)
% 0.20/0.65 % SPC : FOF_THM_PRP
% 0.20/0.65
% 0.20/0.65 % Comments : The clausal form of this problem is the same as SYN001+1.p.
% 0.20/0.65 %--------------------------------------------------------------------------
% 0.20/0.65 fof(pel6,conjecture,
% 0.20/0.65 ( p
% 0.20/0.65 | ~ p ) ).
% 0.20/0.65
% 0.20/0.65 %--------------------------------------------------------------------------
% 0.20/0.65 %-------------------------------------------
% 0.20/0.65 % Proof found
% 0.20/0.65 % SZS status Theorem for theBenchmark
% 0.20/0.65 % SZS output start Proof
% 0.20/0.65 %ClaNum:2(EqnAxiom:0)
% 0.20/0.65 %VarNum:0(SingletonVarNum:0)
% 0.20/0.65 %MaxLitNum:1
% 0.20/0.65 %MaxfuncDepth:0
% 0.20/0.65 %SharedTerms:3
% 0.20/0.65 %goalClause: 1 2
% 0.20/0.65 %singleGoalClaCount:2
% 0.20/0.65 [1]P1(a500)
% 0.20/0.65 [2]~P1(a500)
% 0.20/0.65 %EqnAxiom
% 0.20/0.65
% 0.20/0.65 %-------------------------------------------
% 0.20/0.65 cnf(3,plain,
% 0.20/0.65 ($false),
% 0.20/0.65 inference(scs_inference,[],[1,2]),
% 0.20/0.65 ['proof']).
% 0.20/0.65 % SZS output end Proof
% 0.20/0.65 % Total time :0.000000s
%------------------------------------------------------------------------------