TSTP Solution File: SYN387+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SYN387+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Thu Jul 21 02:50:15 EDT 2022

% Result   : Theorem 0.42s 1.06s
% Output   : Refutation 0.42s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYN387+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12  % Command  : bliksem %s
% 0.12/0.33  % Computer : n024.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % DateTime : Tue Jul 12 02:36:13 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.42/1.06  *** allocated 10000 integers for termspace/termends
% 0.42/1.06  *** allocated 10000 integers for clauses
% 0.42/1.06  *** allocated 10000 integers for justifications
% 0.42/1.06  Bliksem 1.12
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Automatic Strategy Selection
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Clauses:
% 0.42/1.06  
% 0.42/1.06  { ! p }.
% 0.42/1.06  { p }.
% 0.42/1.06  
% 0.42/1.06  percentage equality = 0.000000, percentage horn = 1.000000
% 0.42/1.06  This is a near-Horn, non-equality  problem
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Options Used:
% 0.42/1.06  
% 0.42/1.06  useres =            1
% 0.42/1.06  useparamod =        0
% 0.42/1.06  useeqrefl =         0
% 0.42/1.06  useeqfact =         0
% 0.42/1.06  usefactor =         1
% 0.42/1.06  usesimpsplitting =  0
% 0.42/1.06  usesimpdemod =      0
% 0.42/1.06  usesimpres =        4
% 0.42/1.06  
% 0.42/1.06  resimpinuse      =  1000
% 0.42/1.06  resimpclauses =     20000
% 0.42/1.06  substype =          standard
% 0.42/1.06  backwardsubs =      1
% 0.42/1.06  selectoldest =      5
% 0.42/1.06  
% 0.42/1.06  litorderings [0] =  split
% 0.42/1.06  litorderings [1] =  liftord
% 0.42/1.06  
% 0.42/1.06  termordering =      none
% 0.42/1.06  
% 0.42/1.06  litapriori =        1
% 0.42/1.06  termapriori =       0
% 0.42/1.06  litaposteriori =    0
% 0.42/1.06  termaposteriori =   0
% 0.42/1.06  demodaposteriori =  0
% 0.42/1.06  ordereqreflfact =   0
% 0.42/1.06  
% 0.42/1.06  litselect =         negative
% 0.42/1.06  
% 0.42/1.06  maxweight =         30000
% 0.42/1.06  maxdepth =          30000
% 0.42/1.06  maxlength =         115
% 0.42/1.06  maxnrvars =         195
% 0.42/1.06  excuselevel =       0
% 0.42/1.06  increasemaxweight = 0
% 0.42/1.06  
% 0.42/1.06  maxselected =       10000000
% 0.42/1.06  maxnrclauses =      10000000
% 0.42/1.06  
% 0.42/1.06  showgenerated =    0
% 0.42/1.06  showkept =         0
% 0.42/1.06  showselected =     0
% 0.42/1.06  showdeleted =      0
% 0.42/1.06  showresimp =       1
% 0.42/1.06  showstatus =       2000
% 0.42/1.06  
% 0.42/1.06  prologoutput =     0
% 0.42/1.06  nrgoals =          5000000
% 0.42/1.06  totalproof =       1
% 0.42/1.06  
% 0.42/1.06  Symbols occurring in the translation:
% 0.42/1.06  
% 0.42/1.06  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.42/1.06  .  [1, 2]      (w:1, o:12, a:1, s:1, b:0), 
% 0.42/1.06  !  [4, 1]      (w:1, o:7, a:1, s:1, b:0), 
% 0.42/1.06  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.42/1.06  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.42/1.06  p  [35, 0]      (w:1, o:6, a:1, s:1, b:0).
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Starting Search:
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Bliksems!, er is een bewijs:
% 0.42/1.06  % SZS status Theorem
% 0.42/1.06  % SZS output start Refutation
% 0.42/1.06  
% 0.42/1.06  (0) {G0,W2,D1,L1,V0,M1} I { ! p }.
% 0.42/1.06  (1) {G1,W0,D0,L0,V0,M0} I;r(0) {  }.
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  % SZS output end Refutation
% 0.42/1.06  found a proof!
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Unprocessed initial clauses:
% 0.42/1.06  
% 0.42/1.06  (3) {G0,W2,D1,L1,V0,M1}  { ! p }.
% 0.42/1.06  (4) {G0,W1,D1,L1,V0,M1}  { p }.
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Total Proof:
% 0.42/1.06  
% 0.42/1.06  subsumption: (0) {G0,W2,D1,L1,V0,M1} I { ! p }.
% 0.42/1.06  parent0: (3) {G0,W2,D1,L1,V0,M1}  { ! p }.
% 0.42/1.06  substitution0:
% 0.42/1.06  end
% 0.42/1.06  permutation0:
% 0.42/1.06     0 ==> 0
% 0.42/1.06  end
% 0.42/1.06  
% 0.42/1.06  resolution: (5) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.42/1.06  parent0[0]: (0) {G0,W2,D1,L1,V0,M1} I { ! p }.
% 0.42/1.06  parent1[0]: (4) {G0,W1,D1,L1,V0,M1}  { p }.
% 0.42/1.06  substitution0:
% 0.42/1.06  end
% 0.42/1.06  substitution1:
% 0.42/1.06  end
% 0.42/1.06  
% 0.42/1.06  subsumption: (1) {G1,W0,D0,L0,V0,M0} I;r(0) {  }.
% 0.42/1.06  parent0: (5) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.42/1.06  substitution0:
% 0.42/1.06  end
% 0.42/1.06  permutation0:
% 0.42/1.06  end
% 0.42/1.06  
% 0.42/1.06  Proof check complete!
% 0.42/1.06  
% 0.42/1.06  Memory use:
% 0.42/1.06  
% 0.42/1.06  space for terms:        15
% 0.42/1.06  space for clauses:      65
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  clauses generated:      2
% 0.42/1.06  clauses kept:           2
% 0.42/1.06  clauses selected:       0
% 0.42/1.06  clauses deleted:        0
% 0.42/1.06  clauses inuse deleted:  0
% 0.42/1.06  
% 0.42/1.06  subsentry:          0
% 0.42/1.06  literals s-matched: 0
% 0.42/1.06  literals matched:   0
% 0.42/1.06  full subsumption:   0
% 0.42/1.06  
% 0.42/1.06  checksum:           -344
% 0.42/1.06  
% 0.42/1.06  
% 0.42/1.06  Bliksem ended
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