TSTP Solution File: SYN383+1 by SnakeForV---1.0
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%------------------------------------------------------------------------------
% File : SnakeForV---1.0
% Problem : SYN383+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% Computer : n004.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 31 19:26:27 EDT 2022
% Result : Theorem 0.20s 0.48s
% Output : Refutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 2
% Syntax : Number of formulae : 9 ( 3 unt; 0 def)
% Number of atoms : 31 ( 0 equ)
% Maximal formula atoms : 8 ( 3 avg)
% Number of connectives : 34 ( 12 ~; 2 |; 17 &)
% ( 0 <=>; 3 =>; 0 <=; 0 <~>)
% Maximal formula depth : 8 ( 5 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-1 aty)
% Number of functors : 1 ( 1 usr; 0 con; 1-1 aty)
% Number of variables : 13 ( 8 !; 5 ?)
% Comments :
%------------------------------------------------------------------------------
fof(f11,plain,
$false,
inference(unit_resulting_resolution,[],[f10,f7]) ).
fof(f7,plain,
! [X0] : ~ big_p(sK0(X0)),
inference(cnf_transformation,[],[f6]) ).
fof(f6,plain,
! [X0] :
( big_p(X0)
& ~ big_q(X0)
& big_q(sK0(X0))
& ~ big_p(sK0(X0)) ),
inference(skolemisation,[status(esa),new_symbols(skolem,[sK0])],[f4,f5]) ).
fof(f5,plain,
! [X0] :
( ? [X1] :
( big_p(X0)
& ~ big_q(X0)
& big_q(X1)
& ~ big_p(X1) )
=> ( big_p(X0)
& ~ big_q(X0)
& big_q(sK0(X0))
& ~ big_p(sK0(X0)) ) ),
introduced(choice_axiom,[]) ).
fof(f4,plain,
! [X0] :
? [X1] :
( big_p(X0)
& ~ big_q(X0)
& big_q(X1)
& ~ big_p(X1) ),
inference(flattening,[],[f3]) ).
fof(f3,plain,
! [X0] :
? [X1] :
( ~ big_p(X1)
& ~ big_q(X0)
& big_p(X0)
& big_q(X1) ),
inference(ennf_transformation,[],[f2]) ).
fof(f2,negated_conjecture,
~ ? [X0] :
! [X1] :
( ( big_p(X0)
& big_q(X1) )
=> ( big_p(X1)
| big_q(X0) ) ),
inference(negated_conjecture,[],[f1]) ).
fof(f1,conjecture,
? [X0] :
! [X1] :
( ( big_p(X0)
& big_q(X1) )
=> ( big_p(X1)
| big_q(X0) ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',x2135) ).
fof(f10,plain,
! [X0] : big_p(X0),
inference(cnf_transformation,[],[f6]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYN383+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.12 % Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% 0.13/0.33 % Computer : n004.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Tue Aug 30 21:46:34 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.20/0.48 % (12330)lrs+10_1:2_br=off:nm=4:ss=included:urr=on:i=7:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/7Mi)
% 0.20/0.48 % (12330)First to succeed.
% 0.20/0.48 % (12319)dis+1002_1:12_drc=off:fd=preordered:tgt=full:i=99978:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/99978Mi)
% 0.20/0.48 % (12319)Also succeeded, but the first one will report.
% 0.20/0.48 % (12330)Refutation found. Thanks to Tanya!
% 0.20/0.48 % SZS status Theorem for theBenchmark
% 0.20/0.48 % SZS output start Proof for theBenchmark
% See solution above
% 0.20/0.48 % (12330)------------------------------
% 0.20/0.48 % (12330)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.20/0.48 % (12330)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.20/0.48 % (12330)Termination reason: Refutation
% 0.20/0.48
% 0.20/0.48 % (12330)Memory used [KB]: 5884
% 0.20/0.48 % (12330)Time elapsed: 0.089 s
% 0.20/0.48 % (12330)Instructions burned: 1 (million)
% 0.20/0.48 % (12330)------------------------------
% 0.20/0.48 % (12330)------------------------------
% 0.20/0.48 % (12318)Success in time 0.14 s
%------------------------------------------------------------------------------