TSTP Solution File: SYN382+1 by Bliksem---1.12
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%------------------------------------------------------------------------------
% File : Bliksem---1.12
% Problem : SYN382+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : bliksem %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Thu Jul 21 02:50:13 EDT 2022
% Result : Theorem 0.41s 1.05s
% Output : Refutation 0.41s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : SYN382+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12 % Command : bliksem %s
% 0.12/0.33 % Computer : n021.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Mon Jul 11 17:19:38 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.41/1.05 *** allocated 10000 integers for termspace/termends
% 0.41/1.05 *** allocated 10000 integers for clauses
% 0.41/1.05 *** allocated 10000 integers for justifications
% 0.41/1.05 Bliksem 1.12
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Automatic Strategy Selection
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Clauses:
% 0.41/1.05
% 0.41/1.05 { big_p( skol1( X ), Y ), big_q( skol1( X ), X ) }.
% 0.41/1.05 { ! big_p( X, skol2 ) }.
% 0.41/1.05 { ! big_q( X, skol2 ) }.
% 0.41/1.05
% 0.41/1.05 percentage equality = 0.000000, percentage horn = 0.666667
% 0.41/1.05 This a non-horn, non-equality problem
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Options Used:
% 0.41/1.05
% 0.41/1.05 useres = 1
% 0.41/1.05 useparamod = 0
% 0.41/1.05 useeqrefl = 0
% 0.41/1.05 useeqfact = 0
% 0.41/1.05 usefactor = 1
% 0.41/1.05 usesimpsplitting = 0
% 0.41/1.05 usesimpdemod = 0
% 0.41/1.05 usesimpres = 3
% 0.41/1.05
% 0.41/1.05 resimpinuse = 1000
% 0.41/1.05 resimpclauses = 20000
% 0.41/1.05 substype = standard
% 0.41/1.05 backwardsubs = 1
% 0.41/1.05 selectoldest = 5
% 0.41/1.05
% 0.41/1.05 litorderings [0] = split
% 0.41/1.05 litorderings [1] = liftord
% 0.41/1.05
% 0.41/1.05 termordering = none
% 0.41/1.05
% 0.41/1.05 litapriori = 1
% 0.41/1.05 termapriori = 0
% 0.41/1.05 litaposteriori = 0
% 0.41/1.05 termaposteriori = 0
% 0.41/1.05 demodaposteriori = 0
% 0.41/1.05 ordereqreflfact = 0
% 0.41/1.05
% 0.41/1.05 litselect = none
% 0.41/1.05
% 0.41/1.05 maxweight = 15
% 0.41/1.05 maxdepth = 30000
% 0.41/1.05 maxlength = 115
% 0.41/1.05 maxnrvars = 195
% 0.41/1.05 excuselevel = 1
% 0.41/1.05 increasemaxweight = 1
% 0.41/1.05
% 0.41/1.05 maxselected = 10000000
% 0.41/1.05 maxnrclauses = 10000000
% 0.41/1.05
% 0.41/1.05 showgenerated = 0
% 0.41/1.05 showkept = 0
% 0.41/1.05 showselected = 0
% 0.41/1.05 showdeleted = 0
% 0.41/1.05 showresimp = 1
% 0.41/1.05 showstatus = 2000
% 0.41/1.05
% 0.41/1.05 prologoutput = 0
% 0.41/1.05 nrgoals = 5000000
% 0.41/1.05 totalproof = 1
% 0.41/1.05
% 0.41/1.05 Symbols occurring in the translation:
% 0.41/1.05
% 0.41/1.05 {} [0, 0] (w:1, o:2, a:1, s:1, b:0),
% 0.41/1.05 . [1, 2] (w:1, o:16, a:1, s:1, b:0),
% 0.41/1.05 ! [4, 1] (w:0, o:10, a:1, s:1, b:0),
% 0.41/1.05 = [13, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.41/1.05 ==> [14, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.41/1.05 big_p [38, 2] (w:1, o:40, a:1, s:1, b:0),
% 0.41/1.05 big_q [39, 2] (w:1, o:41, a:1, s:1, b:0),
% 0.41/1.05 skol1 [40, 1] (w:1, o:15, a:1, s:1, b:0),
% 0.41/1.05 skol2 [41, 0] (w:1, o:9, a:1, s:1, b:0).
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Starting Search:
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Bliksems!, er is een bewijs:
% 0.41/1.05 % SZS status Theorem
% 0.41/1.05 % SZS output start Refutation
% 0.41/1.05
% 0.41/1.05 (0) {G0,W8,D3,L2,V2,M1} I { big_p( skol1( X ), Y ), big_q( skol1( X ), X )
% 0.41/1.05 }.
% 0.41/1.05 (1) {G0,W3,D2,L1,V1,M1} I { ! big_p( X, skol2 ) }.
% 0.41/1.05 (2) {G0,W3,D2,L1,V1,M1} I { ! big_q( X, skol2 ) }.
% 0.41/1.05 (3) {G1,W4,D3,L1,V1,M1} R(0,2) { big_p( skol1( skol2 ), X ) }.
% 0.41/1.05 (4) {G2,W0,D0,L0,V0,M0} R(3,1) { }.
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 % SZS output end Refutation
% 0.41/1.05 found a proof!
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Unprocessed initial clauses:
% 0.41/1.05
% 0.41/1.05 (6) {G0,W8,D3,L2,V2,M2} { big_p( skol1( X ), Y ), big_q( skol1( X ), X )
% 0.41/1.05 }.
% 0.41/1.05 (7) {G0,W3,D2,L1,V1,M1} { ! big_p( X, skol2 ) }.
% 0.41/1.05 (8) {G0,W3,D2,L1,V1,M1} { ! big_q( X, skol2 ) }.
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Total Proof:
% 0.41/1.05
% 0.41/1.05 subsumption: (0) {G0,W8,D3,L2,V2,M1} I { big_p( skol1( X ), Y ), big_q(
% 0.41/1.05 skol1( X ), X ) }.
% 0.41/1.05 parent0: (6) {G0,W8,D3,L2,V2,M2} { big_p( skol1( X ), Y ), big_q( skol1( X
% 0.41/1.05 ), X ) }.
% 0.41/1.05 substitution0:
% 0.41/1.05 X := X
% 0.41/1.05 Y := Y
% 0.41/1.05 end
% 0.41/1.05 permutation0:
% 0.41/1.05 0 ==> 0
% 0.41/1.05 1 ==> 1
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 subsumption: (1) {G0,W3,D2,L1,V1,M1} I { ! big_p( X, skol2 ) }.
% 0.41/1.05 parent0: (7) {G0,W3,D2,L1,V1,M1} { ! big_p( X, skol2 ) }.
% 0.41/1.05 substitution0:
% 0.41/1.05 X := X
% 0.41/1.05 end
% 0.41/1.05 permutation0:
% 0.41/1.05 0 ==> 0
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 subsumption: (2) {G0,W3,D2,L1,V1,M1} I { ! big_q( X, skol2 ) }.
% 0.41/1.05 parent0: (8) {G0,W3,D2,L1,V1,M1} { ! big_q( X, skol2 ) }.
% 0.41/1.05 substitution0:
% 0.41/1.05 X := X
% 0.41/1.05 end
% 0.41/1.05 permutation0:
% 0.41/1.05 0 ==> 0
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 resolution: (9) {G1,W4,D3,L1,V1,M1} { big_p( skol1( skol2 ), X ) }.
% 0.41/1.05 parent0[0]: (2) {G0,W3,D2,L1,V1,M1} I { ! big_q( X, skol2 ) }.
% 0.41/1.05 parent1[1]: (0) {G0,W8,D3,L2,V2,M1} I { big_p( skol1( X ), Y ), big_q(
% 0.41/1.05 skol1( X ), X ) }.
% 0.41/1.05 substitution0:
% 0.41/1.05 X := skol1( skol2 )
% 0.41/1.05 end
% 0.41/1.05 substitution1:
% 0.41/1.05 X := skol2
% 0.41/1.05 Y := X
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 subsumption: (3) {G1,W4,D3,L1,V1,M1} R(0,2) { big_p( skol1( skol2 ), X )
% 0.41/1.05 }.
% 0.41/1.05 parent0: (9) {G1,W4,D3,L1,V1,M1} { big_p( skol1( skol2 ), X ) }.
% 0.41/1.05 substitution0:
% 0.41/1.05 X := X
% 0.41/1.05 end
% 0.41/1.05 permutation0:
% 0.41/1.05 0 ==> 0
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 resolution: (10) {G1,W0,D0,L0,V0,M0} { }.
% 0.41/1.05 parent0[0]: (1) {G0,W3,D2,L1,V1,M1} I { ! big_p( X, skol2 ) }.
% 0.41/1.05 parent1[0]: (3) {G1,W4,D3,L1,V1,M1} R(0,2) { big_p( skol1( skol2 ), X ) }.
% 0.41/1.05 substitution0:
% 0.41/1.05 X := skol1( skol2 )
% 0.41/1.05 end
% 0.41/1.05 substitution1:
% 0.41/1.05 X := skol2
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 subsumption: (4) {G2,W0,D0,L0,V0,M0} R(3,1) { }.
% 0.41/1.05 parent0: (10) {G1,W0,D0,L0,V0,M0} { }.
% 0.41/1.05 substitution0:
% 0.41/1.05 end
% 0.41/1.05 permutation0:
% 0.41/1.05 end
% 0.41/1.05
% 0.41/1.05 Proof check complete!
% 0.41/1.05
% 0.41/1.05 Memory use:
% 0.41/1.05
% 0.41/1.05 space for terms: 70
% 0.41/1.05 space for clauses: 266
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 clauses generated: 5
% 0.41/1.05 clauses kept: 5
% 0.41/1.05 clauses selected: 4
% 0.41/1.05 clauses deleted: 0
% 0.41/1.05 clauses inuse deleted: 0
% 0.41/1.05
% 0.41/1.05 subsentry: 0
% 0.41/1.05 literals s-matched: 0
% 0.41/1.05 literals matched: 0
% 0.41/1.05 full subsumption: 0
% 0.41/1.05
% 0.41/1.05 checksum: -134221201
% 0.41/1.05
% 0.41/1.05
% 0.41/1.05 Bliksem ended
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