TSTP Solution File: SYN379+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN379+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:31 EDT 2023

% Result   : Theorem 3.46s 3.76s
% Output   : Proof 3.46s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYN379+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n029.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 20:58:10 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.46/3.76  SZS status Theorem for theBenchmark.p
% 3.46/3.76  SZS output start Proof for theBenchmark.p
% 3.46/3.76  Clause #0 (by assumption #[]): Eq
% 3.46/3.76    (Not
% 3.46/3.76      ((∀ (X : Iota), big_p X) →
% 3.46/3.76        Exists fun Y => (∀ (X Z : Iota), big_q X Y Z) → Not (∀ (Z : Iota), And (big_p Z) (Not (big_q Y Y Z)))))
% 3.46/3.76    True
% 3.46/3.76  Clause #1 (by clausification #[0]): Eq
% 3.46/3.76    ((∀ (X : Iota), big_p X) →
% 3.46/3.76      Exists fun Y => (∀ (X Z : Iota), big_q X Y Z) → Not (∀ (Z : Iota), And (big_p Z) (Not (big_q Y Y Z))))
% 3.46/3.76    False
% 3.46/3.76  Clause #3 (by clausification #[1]): Eq (Exists fun Y => (∀ (X Z : Iota), big_q X Y Z) → Not (∀ (Z : Iota), And (big_p Z) (Not (big_q Y Y Z)))) False
% 3.46/3.76  Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq ((∀ (X Z : Iota), big_q X a Z) → Not (∀ (Z : Iota), And (big_p Z) (Not (big_q a a Z)))) False
% 3.46/3.76  Clause #6 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (X Z : Iota), big_q X a Z) True
% 3.46/3.76  Clause #7 (by clausification #[5]): ∀ (a : Iota), Eq (Not (∀ (Z : Iota), And (big_p Z) (Not (big_q a a Z)))) False
% 3.46/3.76  Clause #8 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (∀ (Z : Iota), big_q a a_1 Z) True
% 3.46/3.76  Clause #9 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Eq (big_q a a_1 a_2) True
% 3.46/3.76  Clause #10 (by clausification #[7]): ∀ (a : Iota), Eq (∀ (Z : Iota), And (big_p Z) (Not (big_q a a Z))) True
% 3.46/3.76  Clause #11 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (And (big_p a) (Not (big_q a_1 a_1 a))) True
% 3.46/3.76  Clause #12 (by clausification #[11]): ∀ (a a_1 : Iota), Eq (Not (big_q a a a_1)) True
% 3.46/3.76  Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Eq (big_q a a a_1) False
% 3.46/3.76  Clause #14 (by superposition #[13, 9]): Eq False True
% 3.46/3.76  Clause #15 (by clausification #[14]): False
% 3.46/3.76  SZS output end Proof for theBenchmark.p
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