TSTP Solution File: SYN372+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYN372+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:28 EDT 2023

% Result   : Theorem 3.39s 3.71s
% Output   : Proof 3.39s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYN372+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.17/0.34  % Computer : n008.cluster.edu
% 0.17/0.34  % Model    : x86_64 x86_64
% 0.17/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.17/0.34  % Memory   : 8042.1875MB
% 0.17/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.17/0.34  % CPULimit   : 300
% 0.17/0.34  % WCLimit    : 300
% 0.17/0.34  % DateTime   : Sat Aug 26 18:46:17 EDT 2023
% 0.17/0.35  % CPUTime    : 
% 3.39/3.71  SZS status Theorem for theBenchmark.p
% 3.39/3.71  SZS output start Proof for theBenchmark.p
% 3.39/3.71  Clause #0 (by assumption #[]): Eq (Not (∀ (X : Iota), (Exists fun Y => big_p Y → big_q X) → Exists fun Y => big_p Y → big_q Y)) True
% 3.39/3.71  Clause #1 (by clausification #[0]): Eq (∀ (X : Iota), (Exists fun Y => big_p Y → big_q X) → Exists fun Y => big_p Y → big_q Y) False
% 3.39/3.71  Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (Not ((Exists fun Y => big_p Y → big_q (skS.0 0 a)) → Exists fun Y => big_p Y → big_q Y)) True
% 3.39/3.71  Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq ((Exists fun Y => big_p Y → big_q (skS.0 0 a)) → Exists fun Y => big_p Y → big_q Y) False
% 3.39/3.71  Clause #4 (by clausification #[3]): ∀ (a : Iota), Eq (Exists fun Y => big_p Y → big_q (skS.0 0 a)) True
% 3.39/3.71  Clause #5 (by clausification #[3]): Eq (Exists fun Y => big_p Y → big_q Y) False
% 3.39/3.71  Clause #6 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (big_p (skS.0 1 a a_1) → big_q (skS.0 0 a)) True
% 3.39/3.71  Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (big_p (skS.0 1 a a_1)) False) (Eq (big_q (skS.0 0 a)) True)
% 3.39/3.71  Clause #8 (by clausification #[5]): ∀ (a : Iota), Eq (big_p a → big_q a) False
% 3.39/3.71  Clause #9 (by clausification #[8]): ∀ (a : Iota), Eq (big_p a) True
% 3.39/3.71  Clause #10 (by clausification #[8]): ∀ (a : Iota), Eq (big_q a) False
% 3.39/3.71  Clause #11 (by superposition #[9, 7]): ∀ (a : Iota), Or (Eq True False) (Eq (big_q (skS.0 0 a)) True)
% 3.39/3.71  Clause #13 (by clausification #[11]): ∀ (a : Iota), Eq (big_q (skS.0 0 a)) True
% 3.39/3.71  Clause #14 (by superposition #[13, 10]): Eq True False
% 3.39/3.71  Clause #15 (by clausification #[14]): False
% 3.39/3.71  SZS output end Proof for theBenchmark.p
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