TSTP Solution File: SYN371+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN371+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:11:28 EDT 2023
% Result : Theorem 3.54s 3.79s
% Output : Proof 3.54s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN371+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n001.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 19:24:01 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.54/3.79 SZS status Theorem for theBenchmark.p
% 3.54/3.79 SZS output start Proof for theBenchmark.p
% 3.54/3.79 Clause #0 (by assumption #[]): Eq (Not (((Exists fun X => big_r X X) → ∀ (Y : Iota), big_r Y Y) → Exists fun U => ∀ (V : Iota), big_r U U → big_r V V))
% 3.54/3.79 True
% 3.54/3.79 Clause #1 (by clausification #[0]): Eq (((Exists fun X => big_r X X) → ∀ (Y : Iota), big_r Y Y) → Exists fun U => ∀ (V : Iota), big_r U U → big_r V V) False
% 3.54/3.79 Clause #3 (by clausification #[1]): Eq (Exists fun U => ∀ (V : Iota), big_r U U → big_r V V) False
% 3.54/3.79 Clause #7 (by clausification #[3]): ∀ (a : Iota), Eq (∀ (V : Iota), big_r a a → big_r V V) False
% 3.54/3.79 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (Not (big_r a a → big_r (skS.0 0 a a_1) (skS.0 0 a a_1))) True
% 3.54/3.79 Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Eq (big_r a a → big_r (skS.0 0 a a_1) (skS.0 0 a a_1)) False
% 3.54/3.79 Clause #10 (by clausification #[9]): ∀ (a : Iota), Eq (big_r a a) True
% 3.54/3.79 Clause #11 (by clausification #[9]): ∀ (a a_1 : Iota), Eq (big_r (skS.0 0 a a_1) (skS.0 0 a a_1)) False
% 3.54/3.79 Clause #12 (by superposition #[11, 10]): Eq False True
% 3.54/3.79 Clause #13 (by clausification #[12]): False
% 3.54/3.79 SZS output end Proof for theBenchmark.p
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