TSTP Solution File: SYN356+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN356+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n031.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:11:23 EDT 2023
% Result : Theorem 3.44s 3.69s
% Output : Proof 3.44s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : SYN356+1 : TPTP v8.1.2. Released v2.0.0.
% 0.12/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n031.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 20:56:08 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.44/3.69 SZS status Theorem for theBenchmark.p
% 3.44/3.69 SZS output start Proof for theBenchmark.p
% 3.44/3.69 Clause #0 (by assumption #[]): Eq
% 3.44/3.69 (Not
% 3.44/3.69 (And (And (big_r a b) (∀ (X Y : Iota), big_r X Y → And (big_r Y X) (big_q X Y)))
% 3.44/3.69 (∀ (U V : Iota), big_q U V → big_q U U) →
% 3.44/3.69 And (big_q a a) (big_q b b)))
% 3.44/3.69 True
% 3.44/3.69 Clause #1 (by clausification #[0]): Eq
% 3.44/3.69 (And (And (big_r a b) (∀ (X Y : Iota), big_r X Y → And (big_r Y X) (big_q X Y)))
% 3.44/3.69 (∀ (U V : Iota), big_q U V → big_q U U) →
% 3.44/3.69 And (big_q a a) (big_q b b))
% 3.44/3.69 False
% 3.44/3.69 Clause #2 (by clausification #[1]): Eq
% 3.44/3.69 (And (And (big_r a b) (∀ (X Y : Iota), big_r X Y → And (big_r Y X) (big_q X Y)))
% 3.44/3.69 (∀ (U V : Iota), big_q U V → big_q U U))
% 3.44/3.69 True
% 3.44/3.69 Clause #3 (by clausification #[1]): Eq (And (big_q a a) (big_q b b)) False
% 3.44/3.69 Clause #4 (by clausification #[2]): Eq (∀ (U V : Iota), big_q U V → big_q U U) True
% 3.44/3.69 Clause #5 (by clausification #[2]): Eq (And (big_r a b) (∀ (X Y : Iota), big_r X Y → And (big_r Y X) (big_q X Y))) True
% 3.44/3.69 Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (∀ (V : Iota), big_q a V → big_q a a) True
% 3.44/3.69 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (big_q a a_1 → big_q a a) True
% 3.44/3.69 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (big_q a a_1) False) (Eq (big_q a a) True)
% 3.44/3.69 Clause #9 (by clausification #[3]): Or (Eq (big_q a a) False) (Eq (big_q b b) False)
% 3.44/3.69 Clause #10 (by clausification #[5]): Eq (∀ (X Y : Iota), big_r X Y → And (big_r Y X) (big_q X Y)) True
% 3.44/3.69 Clause #11 (by clausification #[5]): Eq (big_r a b) True
% 3.44/3.69 Clause #12 (by clausification #[10]): ∀ (a : Iota), Eq (∀ (Y : Iota), big_r a Y → And (big_r Y a) (big_q a Y)) True
% 3.44/3.69 Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Eq (big_r a a_1 → And (big_r a_1 a) (big_q a a_1)) True
% 3.44/3.69 Clause #14 (by clausification #[13]): ∀ (a a_1 : Iota), Or (Eq (big_r a a_1) False) (Eq (And (big_r a_1 a) (big_q a a_1)) True)
% 3.44/3.69 Clause #15 (by clausification #[14]): ∀ (a a_1 : Iota), Or (Eq (big_r a a_1) False) (Eq (big_q a a_1) True)
% 3.44/3.69 Clause #16 (by clausification #[14]): ∀ (a a_1 : Iota), Or (Eq (big_r a a_1) False) (Eq (big_r a_1 a) True)
% 3.44/3.69 Clause #17 (by superposition #[11, 15]): Or (Eq (big_q a b) True) (Eq False True)
% 3.44/3.69 Clause #18 (by clausification #[17]): Eq (big_q a b) True
% 3.44/3.69 Clause #19 (by superposition #[18, 8]): Or (Eq True False) (Eq (big_q a a) True)
% 3.44/3.69 Clause #20 (by superposition #[16, 11]): Or (Eq (big_r b a) True) (Eq False True)
% 3.44/3.69 Clause #21 (by clausification #[20]): Eq (big_r b a) True
% 3.44/3.69 Clause #22 (by superposition #[21, 15]): Or (Eq True False) (Eq (big_q b a) True)
% 3.44/3.69 Clause #24 (by clausification #[22]): Eq (big_q b a) True
% 3.44/3.69 Clause #25 (by superposition #[24, 8]): Or (Eq True False) (Eq (big_q b b) True)
% 3.44/3.69 Clause #26 (by clausification #[25]): Eq (big_q b b) True
% 3.44/3.69 Clause #27 (by backward demodulation #[26, 9]): Or (Eq (big_q a a) False) (Eq True False)
% 3.44/3.69 Clause #28 (by clausification #[27]): Eq (big_q a a) False
% 3.44/3.69 Clause #29 (by clausification #[19]): Eq (big_q a a) True
% 3.44/3.69 Clause #30 (by superposition #[29, 28]): Eq True False
% 3.44/3.69 Clause #31 (by clausification #[30]): False
% 3.44/3.69 SZS output end Proof for theBenchmark.p
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