TSTP Solution File: SYN355+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN355+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:11:22 EDT 2023
% Result : Theorem 3.33s 3.58s
% Output : Proof 3.33s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN355+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n025.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 21:47:38 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.33/3.58 SZS status Theorem for theBenchmark.p
% 3.33/3.58 SZS output start Proof for theBenchmark.p
% 3.33/3.58 Clause #0 (by assumption #[]): Eq
% 3.33/3.58 (Not
% 3.33/3.58 (And (∀ (X : Iota), big_r X → big_p X) (∀ (X : Iota), Not (big_q X) → big_r X) →
% 3.33/3.58 ∀ (X : Iota), Or (big_p X) (big_q X)))
% 3.33/3.58 True
% 3.33/3.58 Clause #1 (by clausification #[0]): Eq
% 3.33/3.58 (And (∀ (X : Iota), big_r X → big_p X) (∀ (X : Iota), Not (big_q X) → big_r X) → ∀ (X : Iota), Or (big_p X) (big_q X))
% 3.33/3.58 False
% 3.33/3.58 Clause #2 (by clausification #[1]): Eq (And (∀ (X : Iota), big_r X → big_p X) (∀ (X : Iota), Not (big_q X) → big_r X)) True
% 3.33/3.58 Clause #3 (by clausification #[1]): Eq (∀ (X : Iota), Or (big_p X) (big_q X)) False
% 3.33/3.58 Clause #4 (by clausification #[2]): Eq (∀ (X : Iota), Not (big_q X) → big_r X) True
% 3.33/3.58 Clause #5 (by clausification #[2]): Eq (∀ (X : Iota), big_r X → big_p X) True
% 3.33/3.58 Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (Not (big_q a) → big_r a) True
% 3.33/3.58 Clause #7 (by clausification #[6]): ∀ (a : Iota), Or (Eq (Not (big_q a)) False) (Eq (big_r a) True)
% 3.33/3.58 Clause #8 (by clausification #[7]): ∀ (a : Iota), Or (Eq (big_r a) True) (Eq (big_q a) True)
% 3.33/3.58 Clause #9 (by clausification #[5]): ∀ (a : Iota), Eq (big_r a → big_p a) True
% 3.33/3.58 Clause #10 (by clausification #[9]): ∀ (a : Iota), Or (Eq (big_r a) False) (Eq (big_p a) True)
% 3.33/3.58 Clause #11 (by clausification #[3]): ∀ (a : Iota), Eq (Not (Or (big_p (skS.0 0 a)) (big_q (skS.0 0 a)))) True
% 3.33/3.58 Clause #12 (by clausification #[11]): ∀ (a : Iota), Eq (Or (big_p (skS.0 0 a)) (big_q (skS.0 0 a))) False
% 3.33/3.58 Clause #13 (by clausification #[12]): ∀ (a : Iota), Eq (big_q (skS.0 0 a)) False
% 3.33/3.58 Clause #14 (by clausification #[12]): ∀ (a : Iota), Eq (big_p (skS.0 0 a)) False
% 3.33/3.58 Clause #15 (by superposition #[13, 8]): ∀ (a : Iota), Or (Eq (big_r (skS.0 0 a)) True) (Eq False True)
% 3.33/3.58 Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (big_r (skS.0 0 a)) True
% 3.33/3.58 Clause #17 (by superposition #[16, 10]): ∀ (a : Iota), Or (Eq True False) (Eq (big_p (skS.0 0 a)) True)
% 3.33/3.58 Clause #18 (by clausification #[17]): ∀ (a : Iota), Eq (big_p (skS.0 0 a)) True
% 3.33/3.58 Clause #19 (by superposition #[18, 14]): Eq True False
% 3.33/3.58 Clause #20 (by clausification #[19]): False
% 3.33/3.58 SZS output end Proof for theBenchmark.p
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