TSTP Solution File: SYN354+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN354+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:20:41 EDT 2022

% Result   : Theorem 0.20s 0.43s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :    4
% Syntax   : Number of clauses     :   11 (   3 unt;   4 nHn;  11 RR)
%            Number of literals    :   28 (   0 equ;  13 neg)
%            Maximal clause size   :    4 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   4 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(2,axiom,
    big(skc3,skc2),
    file('SYN354+1.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ big(u,v)
    | ~ big(skc3,u)
    | ~ big(skc2,u) ),
    file('SYN354+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ big(u,v)
    | big_g(v,skf1(u,v))
    | big(skc2,v)
    | big_g(skc2,skf1(u,v)) ),
    file('SYN354+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ big(u,v)
    | ~ big_g(v,skf1(u,v))
    | ~ big_g(skc2,skf1(u,v))
    | big(skc2,v) ),
    file('SYN354+1.p',unknown),
    [] ).

cnf(9,plain,
    ( big_g(skc2,skf1(skc3,skc2))
    | big(skc2,skc2)
    | big_g(skc2,skf1(skc3,skc2)) ),
    inference(res,[status(thm),theory(equality)],[2,6]),
    [iquote('0:Res:2.0,6.0')] ).

cnf(10,plain,
    ( big(skc2,skc2)
    | big_g(skc2,skf1(skc3,skc2)) ),
    inference(obv,[status(thm),theory(equality)],[9]),
    [iquote('0:Obv:9.0')] ).

cnf(13,plain,
    ( ~ big(skc3,skc2)
    | ~ big_g(skc2,skf1(skc3,skc2))
    | big(skc2,skc2)
    | big(skc2,skc2) ),
    inference(res,[status(thm),theory(equality)],[10,7]),
    [iquote('0:Res:10.1,7.1')] ).

cnf(14,plain,
    ( ~ big(skc3,skc2)
    | ~ big_g(skc2,skf1(skc3,skc2))
    | big(skc2,skc2) ),
    inference(obv,[status(thm),theory(equality)],[13]),
    [iquote('0:Obv:13.2')] ).

cnf(15,plain,
    big(skc2,skc2),
    inference(mrr,[status(thm)],[14,2,10]),
    [iquote('0:MRR:14.0,14.1,2.0,10.1')] ).

cnf(17,plain,
    ( ~ big(skc3,skc2)
    | ~ big(skc2,skc2) ),
    inference(res,[status(thm),theory(equality)],[15,5]),
    [iquote('0:Res:15.0,5.0')] ).

cnf(18,plain,
    $false,
    inference(mrr,[status(thm)],[17,2,15]),
    [iquote('0:MRR:17.0,17.1,2.0,15.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYN354+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n028.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jul 12 07:23:14 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.20/0.43  
% 0.20/0.43  SPASS V 3.9 
% 0.20/0.43  SPASS beiseite: Proof found.
% 0.20/0.43  % SZS status Theorem
% 0.20/0.43  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.43  SPASS derived 7 clauses, backtracked 0 clauses, performed 0 splits and kept 12 clauses.
% 0.20/0.43  SPASS allocated 85070 KBytes.
% 0.20/0.43  SPASS spent	0:00:00.08 on the problem.
% 0.20/0.43  		0:00:00.03 for the input.
% 0.20/0.43  		0:00:00.02 for the FLOTTER CNF translation.
% 0.20/0.43  		0:00:00.00 for inferences.
% 0.20/0.43  		0:00:00.00 for the backtracking.
% 0.20/0.43  		0:00:00.00 for the reduction.
% 0.20/0.43  
% 0.20/0.43  
% 0.20/0.43  Here is a proof with depth 3, length 11 :
% 0.20/0.43  % SZS output start Refutation
% See solution above
% 0.20/0.43  Formulae used in the proof : church_46_20_1
% 0.20/0.43  
%------------------------------------------------------------------------------