TSTP Solution File: SYN352+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SYN352+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:12:06 EDT 2022

% Result   : Theorem 0.20s 0.43s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.13  % Problem  : SYN352+1 : TPTP v8.1.0. Released v2.0.0.
% 0.08/0.13  % Command  : sos-script %s
% 0.13/0.35  % Computer : n027.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Mon Jul 11 17:02:04 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.13/0.37  ----- Otter 3.2, August 2001 -----
% 0.13/0.37  The process was started by sandbox2 on n027.cluster.edu,
% 0.13/0.37  Mon Jul 11 17:02:04 2022
% 0.13/0.37  The command was "./sos".  The process ID is 22725.
% 0.13/0.37  
% 0.13/0.37  set(prolog_style_variables).
% 0.13/0.37  set(auto).
% 0.13/0.37     dependent: set(auto1).
% 0.13/0.37     dependent: set(process_input).
% 0.13/0.37     dependent: clear(print_kept).
% 0.13/0.37     dependent: clear(print_new_demod).
% 0.13/0.37     dependent: clear(print_back_demod).
% 0.13/0.37     dependent: clear(print_back_sub).
% 0.13/0.37     dependent: set(control_memory).
% 0.13/0.37     dependent: assign(max_mem, 12000).
% 0.13/0.37     dependent: assign(pick_given_ratio, 4).
% 0.13/0.37     dependent: assign(stats_level, 1).
% 0.13/0.37     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.37     dependent: assign(sos_limit, 5000).
% 0.13/0.37     dependent: assign(max_weight, 60).
% 0.13/0.37  clear(print_given).
% 0.13/0.37  
% 0.13/0.37  formula_list(usable).
% 0.13/0.37  
% 0.13/0.37  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=3.
% 0.13/0.37  
% 0.13/0.37  This is a non-Horn set without equality.  The strategy
% 0.13/0.37  will be ordered hyper_res, ur_res, unit deletion, and
% 0.13/0.37  factoring, with satellites in sos and nuclei in usable.
% 0.13/0.37  
% 0.13/0.37     dependent: set(hyper_res).
% 0.13/0.37     dependent: set(factor).
% 0.13/0.37     dependent: set(unit_deletion).
% 0.13/0.37  
% 0.13/0.37  ------------> process usable:
% 0.13/0.37  
% 0.13/0.37  ------------> process sos:
% 0.13/0.37  
% 0.13/0.37  ======= end of input processing =======
% 0.20/0.40  
% 0.20/0.40  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.40  
% 0.20/0.40  Stopped by limit on number of solutions
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  -------------- Softie stats --------------
% 0.20/0.40  
% 0.20/0.40  UPDATE_STOP: 300
% 0.20/0.40  SFINDER_TIME_LIMIT: 2
% 0.20/0.40  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.40  number of clauses in intial UL: 8
% 0.20/0.40  number of clauses initially in problem: 12
% 0.20/0.40  percentage of clauses intially in UL: 66
% 0.20/0.40  percentage of distinct symbols occuring in initial UL: 75
% 0.20/0.40  percent of all initial clauses that are short: 100
% 0.20/0.40  absolute distinct symbol count: 4
% 0.20/0.40     distinct predicate count: 1
% 0.20/0.40     distinct function count: 1
% 0.20/0.40     distinct constant count: 2
% 0.20/0.40  
% 0.20/0.40  ---------- no more Softie stats ----------
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.40  
% 0.20/0.40  Stopped by limit on number of solutions
% 0.20/0.40  
% 0.20/0.40  =========== start of search ===========
% 0.20/0.43  
% 0.20/0.43  -------- PROOF -------- 
% 0.20/0.43  % SZS status Theorem
% 0.20/0.43  % SZS output start Refutation
% 0.20/0.43  
% 0.20/0.43  Model 3 [ 12 0 365 ] (0.00 seconds, 761 Inserts)
% 0.20/0.43  
% 0.20/0.43  -----> EMPTY CLAUSE at   0.04 sec ----> 46 [hyper,30,8,26] {-} $F.
% 0.20/0.43  
% 0.20/0.43  Length of proof is 6.  Level of proof is 3.
% 0.20/0.43  
% 0.20/0.43  ---------------- PROOF ----------------
% 0.20/0.43  % SZS status Theorem
% 0.20/0.43  % SZS output start Refutation
% 0.20/0.43  
% 0.20/0.43  2 [] {+} -big_f($c1,$f1(A,B))| -big_f(A,$f1(A,B))|big_f($f1(A,B),$f1(A,B)).
% 0.20/0.43  3 [] {+} -big_f(A,B)|big_f(A,$f1(A,B))|big_f(B,$f1(A,B)).
% 0.20/0.43  4 [] {+} -big_f(A,B)| -big_f(A,$f1(A,B))| -big_f(B,$f1(A,B)).
% 0.20/0.43  6 [factor,2.1.2] {+} -big_f($c1,$f1($c1,A))|big_f($f1($c1,A),$f1($c1,A)).
% 0.20/0.43  7 [factor,3.2.3] {+} -big_f(A,A)|big_f(A,$f1(A,A)).
% 0.20/0.43  8 [factor,4.2.3] {+} -big_f(A,A)| -big_f(A,$f1(A,A)).
% 0.20/0.43  11 [] {-} big_f($c1,$f1(A,B))|big_f(A,$f1(A,B))|big_f($f1(A,B),$f1(A,B)).
% 0.20/0.43  12 [factor,11.1.2] {-} big_f($c1,$f1($c1,A))|big_f($f1($c1,A),$f1($c1,A)).
% 0.20/0.43  26 [hyper,12,6,factor_simp] {-} big_f($f1($c1,A),$f1($c1,A)).
% 0.20/0.43  30 [hyper,26,7] {+} big_f($f1($c1,A),$f1($f1($c1,A),$f1($c1,A))).
% 0.20/0.43  46 [hyper,30,8,26] {-} $F.
% 0.20/0.43  
% 0.20/0.43  % SZS output end Refutation
% 0.20/0.43  ------------ end of proof -------------
% 0.20/0.43  
% 0.20/0.43  
% 0.20/0.43  Search stopped by max_proofs option.
% 0.20/0.43  
% 0.20/0.43  
% 0.20/0.43  Search stopped by max_proofs option.
% 0.20/0.43  
% 0.20/0.43  ============ end of search ============
% 0.20/0.43  
% 0.20/0.43  ----------- soft-scott stats ----------
% 0.20/0.43  
% 0.20/0.43  true clauses given           1      (14.3%)
% 0.20/0.43  false clauses given          6
% 0.20/0.43  
% 0.20/0.43        FALSE     TRUE
% 0.20/0.43    11  1         0
% 0.20/0.43    12  3         0
% 0.20/0.43    14  1         0
% 0.20/0.43    16  0         1
% 0.20/0.43    17  2         0
% 0.20/0.43    18  1         0
% 0.20/0.43    21  1         0
% 0.20/0.43    23  2         0
% 0.20/0.43    26  1         0
% 0.20/0.43    28  3         0
% 0.20/0.43    29  1         0
% 0.20/0.43    33  1         0
% 0.20/0.43    46  1         0
% 0.20/0.43  tot:  18        1      (5.3% true)
% 0.20/0.43  
% 0.20/0.43  
% 0.20/0.43  Model 3 [ 12 0 365 ] (0.00 seconds, 761 Inserts)
% 0.20/0.43  
% 0.20/0.43  That finishes the proof of the theorem.
% 0.20/0.43  
% 0.20/0.43  Process 22725 finished Mon Jul 11 17:02:04 2022
%------------------------------------------------------------------------------