TSTP Solution File: SYN350+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN350+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n001.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:20 EDT 2023

% Result   : Theorem 3.58s 3.75s
% Output   : Proof 3.58s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYN350+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n001.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 17:25:46 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.58/3.75  SZS status Theorem for theBenchmark.p
% 3.58/3.75  SZS output start Proof for theBenchmark.p
% 3.58/3.75  Clause #0 (by assumption #[]): Eq
% 3.58/3.75    (Not
% 3.58/3.75      (∀ (X : Iota),
% 3.58/3.75        Exists fun Y1 =>
% 3.58/3.75          Exists fun Y2 =>
% 3.58/3.75            ∀ (Z : Iota), Iff (big_f X Z) (big_f Z X) → Iff (big_f X Z) (And (big_f Y2 Z) (big_f Y1 Z → big_f Y1 Y2))))
% 3.58/3.75    True
% 3.58/3.75  Clause #1 (by clausification #[0]): Eq
% 3.58/3.75    (∀ (X : Iota),
% 3.58/3.75      Exists fun Y1 =>
% 3.58/3.75        Exists fun Y2 =>
% 3.58/3.75          ∀ (Z : Iota), Iff (big_f X Z) (big_f Z X) → Iff (big_f X Z) (And (big_f Y2 Z) (big_f Y1 Z → big_f Y1 Y2)))
% 3.58/3.75    False
% 3.58/3.75  Clause #2 (by clausification #[1]): ∀ (a : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (Not
% 3.58/3.75        (Exists fun Y1 =>
% 3.58/3.75          Exists fun Y2 =>
% 3.58/3.75            ∀ (Z : Iota),
% 3.58/3.75              Iff (big_f (skS.0 0 a) Z) (big_f Z (skS.0 0 a)) →
% 3.58/3.75                Iff (big_f (skS.0 0 a) Z) (And (big_f Y2 Z) (big_f Y1 Z → big_f Y1 Y2))))
% 3.58/3.75      True
% 3.58/3.75  Clause #3 (by clausification #[2]): ∀ (a : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (Exists fun Y1 =>
% 3.58/3.75        Exists fun Y2 =>
% 3.58/3.75          ∀ (Z : Iota),
% 3.58/3.75            Iff (big_f (skS.0 0 a) Z) (big_f Z (skS.0 0 a)) →
% 3.58/3.75              Iff (big_f (skS.0 0 a) Z) (And (big_f Y2 Z) (big_f Y1 Z → big_f Y1 Y2)))
% 3.58/3.75      False
% 3.58/3.75  Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (Exists fun Y2 =>
% 3.58/3.75        ∀ (Z : Iota),
% 3.58/3.75          Iff (big_f (skS.0 0 a) Z) (big_f Z (skS.0 0 a)) →
% 3.58/3.75            Iff (big_f (skS.0 0 a) Z) (And (big_f Y2 Z) (big_f a_1 Z → big_f a_1 Y2)))
% 3.58/3.75      False
% 3.58/3.75  Clause #5 (by clausification #[4]): ∀ (a a_1 a_2 : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (∀ (Z : Iota),
% 3.58/3.75        Iff (big_f (skS.0 0 a) Z) (big_f Z (skS.0 0 a)) →
% 3.58/3.75          Iff (big_f (skS.0 0 a) Z) (And (big_f a_1 Z) (big_f a_2 Z → big_f a_2 a_1)))
% 3.58/3.75      False
% 3.58/3.75  Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (Not
% 3.58/3.75        (Iff (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) (big_f (skS.0 1 a a_1 a_2 a_3) (skS.0 0 a)) →
% 3.58/3.75          Iff (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3))
% 3.58/3.75            (And (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) (big_f a_2 (skS.0 1 a a_1 a_2 a_3) → big_f a_2 a_1))))
% 3.58/3.75      True
% 3.58/3.75  Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (Iff (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) (big_f (skS.0 1 a a_1 a_2 a_3) (skS.0 0 a)) →
% 3.58/3.75        Iff (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3))
% 3.58/3.75          (And (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) (big_f a_2 (skS.0 1 a a_1 a_2 a_3) → big_f a_2 a_1)))
% 3.58/3.75      False
% 3.58/3.75  Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Eq (Iff (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) (big_f (skS.0 1 a a_1 a_2 a_3) (skS.0 0 a))) True
% 3.58/3.75  Clause #9 (by clausification #[7]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Eq
% 3.58/3.75      (Iff (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3))
% 3.58/3.75        (And (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) (big_f a_2 (skS.0 1 a a_1 a_2 a_3) → big_f a_2 a_1)))
% 3.58/3.75      False
% 3.58/3.75  Clause #11 (by clausification #[8]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) False) (Eq (big_f (skS.0 1 a a_1 a_2 a_3) (skS.0 0 a)) True)
% 3.58/3.75  Clause #12 (by clausification #[9]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) False)
% 3.58/3.75      (Eq (And (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) (big_f a_2 (skS.0 1 a a_1 a_2 a_3) → big_f a_2 a_1)) False)
% 3.58/3.75  Clause #13 (by clausification #[9]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) True)
% 3.58/3.75      (Eq (And (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) (big_f a_2 (skS.0 1 a a_1 a_2 a_3) → big_f a_2 a_1)) True)
% 3.58/3.75  Clause #14 (by clausification #[12]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) False)
% 3.58/3.75      (Or (Eq (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) False) (Eq (big_f a_2 (skS.0 1 a a_1 a_2 a_3) → big_f a_2 a_1) False))
% 3.58/3.75  Clause #16 (by clausification #[14]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) False)
% 3.58/3.75      (Or (Eq (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) False) (Eq (big_f a_2 a_1) False))
% 3.58/3.75  Clause #18 (by clausification #[13]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.58/3.75    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a a_1 a_2 a_3)) True) (Eq (big_f a_1 (skS.0 1 a a_1 a_2 a_3)) True)
% 3.58/3.75  Clause #24 (by equality factoring #[18]): ∀ (a a_1 a_2 : Iota), Or (Ne True True) (Eq (big_f (skS.0 0 a) (skS.0 1 a (skS.0 0 a) a_1 a_2)) True)
% 3.58/3.76  Clause #26 (by clausification #[24]): ∀ (a a_1 a_2 : Iota),
% 3.58/3.76    Or (Eq (big_f (skS.0 0 a) (skS.0 1 a (skS.0 0 a) a_1 a_2)) True) (Or (Eq True False) (Eq True False))
% 3.58/3.76  Clause #28 (by clausification #[26]): ∀ (a a_1 a_2 : Iota), Or (Eq (big_f (skS.0 0 a) (skS.0 1 a (skS.0 0 a) a_1 a_2)) True) (Eq True False)
% 3.58/3.76  Clause #29 (by clausification #[28]): ∀ (a a_1 a_2 : Iota), Eq (big_f (skS.0 0 a) (skS.0 1 a (skS.0 0 a) a_1 a_2)) True
% 3.58/3.76  Clause #31 (by superposition #[29, 16]): ∀ (a a_1 : Iota), Or (Eq True False) (Or (Eq True False) (Eq (big_f a (skS.0 0 a_1)) False))
% 3.58/3.76  Clause #32 (by superposition #[29, 11]): ∀ (a a_1 a_2 : Iota), Or (Eq True False) (Eq (big_f (skS.0 1 a (skS.0 0 a) a_1 a_2) (skS.0 0 a)) True)
% 3.58/3.76  Clause #33 (by clausification #[31]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (big_f a (skS.0 0 a_1)) False)
% 3.58/3.76  Clause #34 (by clausification #[33]): ∀ (a a_1 : Iota), Eq (big_f a (skS.0 0 a_1)) False
% 3.58/3.76  Clause #42 (by clausification #[32]): ∀ (a a_1 a_2 : Iota), Eq (big_f (skS.0 1 a (skS.0 0 a) a_1 a_2) (skS.0 0 a)) True
% 3.58/3.76  Clause #43 (by superposition #[42, 34]): Eq True False
% 3.58/3.76  Clause #45 (by clausification #[43]): False
% 3.58/3.76  SZS output end Proof for theBenchmark.p
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