TSTP Solution File: SYN345-1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN345-1 : TPTP v8.1.0. Released v1.2.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:20:34 EDT 2022

% Result   : Unsatisfiable 0.12s 0.40s
% Output   : Refutation 0.12s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11  % Problem  : SYN345-1 : TPTP v8.1.0. Released v1.2.0.
% 0.11/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n014.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jul 11 19:35:04 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.40  
% 0.12/0.40  SPASS V 3.9 
% 0.12/0.40  SPASS beiseite: Proof found.
% 0.12/0.40  % SZS status Theorem
% 0.12/0.40  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.12/0.40  SPASS derived 7 clauses, backtracked 13 clauses, performed 2 splits and kept 21 clauses.
% 0.12/0.40  SPASS allocated 63092 KBytes.
% 0.12/0.40  SPASS spent	0:00:00.05 on the problem.
% 0.12/0.40  		0:00:00.03 for the input.
% 0.12/0.40  		0:00:00.00 for the FLOTTER CNF translation.
% 0.12/0.40  		0:00:00.00 for inferences.
% 0.12/0.40  		0:00:00.00 for the backtracking.
% 0.12/0.40  		0:00:00.00 for the reduction.
% 0.12/0.40  
% 0.12/0.40  
% 0.12/0.40  Here is a proof with depth 1, length 28 :
% 0.12/0.40  % SZS output start Refutation
% 0.12/0.40  1[0:Inp] || f(a,a,b)* -> f(a,b,u)* f(a,b,b).
% 0.12/0.40  3[0:Inp] || f(a,b,b) -> f(b,u,v)* f(a,a,b)*.
% 0.12/0.40  4[0:Inp] || f(u,z__dfg(u,v),z__dfg(u,v))* f(a,b,b) -> f(a,a,b).
% 0.12/0.40  5[0:Inp] ||  -> f(u,v,z__dfg(u,v))* f(a,a,b) f(a,b,b).
% 0.12/0.40  6[0:Inp] || f(a,a,b) f(a,b,b) -> f(u,v,z__dfg(u,v))*.
% 0.12/0.40  7[0:Inp] || f(b,b,u)* -> f(a,a,b)* f(a,b,b).
% 0.12/0.40  8[0:Inp] || f(b,b,u)* f(a,a,b)* f(a,b,b) -> .
% 0.12/0.40  9[0:Con:1.1] || f(a,a,b)* -> f(a,b,b).
% 0.12/0.40  10[0:MRR:7.1,9.0] || f(b,b,u)*+ -> f(a,b,b)*.
% 0.12/0.40  11[0:MRR:5.1,9.0] ||  -> f(u,v,z__dfg(u,v))* f(a,b,b).
% 0.12/0.40  12[0:MRR:8.2,10.1] || f(b,b,u)* f(a,a,b)* -> .
% 0.12/0.40  13[0:MRR:6.1,11.1] || f(a,a,b) -> f(u,v,z__dfg(u,v))*.
% 0.12/0.40  14[1:Spt:9.0] || f(a,a,b)* -> .
% 0.12/0.40  15[1:MRR:3.2,14.0] || f(a,b,b)* -> f(b,u,v)*.
% 0.12/0.40  16[1:MRR:4.2,14.0] || f(u,z__dfg(u,v),z__dfg(u,v))* f(a,b,b) -> .
% 0.12/0.40  17[2:Spt:10.1] ||  -> f(a,b,b)*.
% 0.12/0.40  18[2:MRR:15.0,17.0] ||  -> f(b,u,v)*.
% 0.12/0.40  19[2:MRR:16.1,17.0] || f(u,z__dfg(u,v),z__dfg(u,v))* -> .
% 0.12/0.40  20[2:UnC:19.0,18.0] ||  -> .
% 0.12/0.40  21[2:Spt:20.0,10.1,17.0] || f(a,b,b)* -> .
% 0.12/0.40  22[2:Spt:20.0,10.0] || f(b,b,u)* -> .
% 0.12/0.40  23[2:MRR:11.1,21.0] ||  -> f(u,v,z__dfg(u,v))*.
% 0.12/0.40  24[2:UnC:23.0,22.0] ||  -> .
% 0.12/0.40  25[1:Spt:24.0,9.0,14.0] ||  -> f(a,a,b)*.
% 0.12/0.40  26[1:Spt:24.0,9.1] ||  -> f(a,b,b)*.
% 0.12/0.40  27[1:MRR:12.1,25.0] || f(b,b,u)* -> .
% 0.12/0.40  28[1:MRR:13.0,25.0] ||  -> f(u,v,z__dfg(u,v))*.
% 0.12/0.40  29[1:UnC:28.0,27.0] ||  -> .
% 0.12/0.40  % SZS output end Refutation
% 0.12/0.40  Formulae used in the proof : clause1 clause3 clause4 clause5 clause6 clause7 clause8
% 0.12/0.40  
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