TSTP Solution File: SYN345+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN345+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:20:34 EDT 2022

% Result   : Theorem 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : SYN345+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.14  % Command  : run_spass %d %s
% 0.14/0.35  % Computer : n012.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % WCLimit  : 600
% 0.14/0.35  % DateTime : Mon Jul 11 18:40:13 EDT 2022
% 0.14/0.35  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 6 clauses, backtracked 10 clauses, performed 2 splits and kept 17 clauses.
% 0.20/0.45  SPASS allocated 85069 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.09 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.00 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 1, length 22 :
% 0.20/0.45  % SZS output start Refutation
% 0.20/0.45  1[0:Inp] ||  -> big_f(u,v,skf1(v,u))*.
% 0.20/0.45  2[0:Inp] || big_f(skc2,skc2,skc3)* -> big_f(skc2,skc3,skc3).
% 0.20/0.45  3[0:Inp] || big_f(skc2,skc3,skc3) -> big_f(skc3,u,v)* big_f(skc2,skc2,skc3)*.
% 0.20/0.45  4[0:Inp] || big_f(skc3,skc3,u)* -> big_f(skc2,skc2,skc3)* big_f(skc2,skc3,skc3).
% 0.20/0.45  5[0:Inp] || big_f(skc2,skc2,skc3)* big_f(skc2,skc3,skc3) big_f(skc3,skc3,u)* -> .
% 0.20/0.45  6[0:Inp] || big_f(u,skf1(v,u),skf1(v,u))* big_f(skc2,skc3,skc3) -> big_f(skc2,skc2,skc3).
% 0.20/0.45  7[0:MRR:4.1,2.0] || big_f(skc3,skc3,u)*+ -> big_f(skc2,skc3,skc3)*.
% 0.20/0.45  8[0:MRR:5.1,7.1] || big_f(skc3,skc3,u)* big_f(skc2,skc2,skc3)* -> .
% 0.20/0.45  9[1:Spt:2.0] || big_f(skc2,skc2,skc3)* -> .
% 0.20/0.45  10[1:MRR:3.2,9.0] || big_f(skc2,skc3,skc3)* -> big_f(skc3,u,v)*.
% 0.20/0.45  11[1:MRR:6.2,9.0] || big_f(u,skf1(v,u),skf1(v,u))* big_f(skc2,skc3,skc3) -> .
% 0.20/0.45  12[2:Spt:7.1] ||  -> big_f(skc2,skc3,skc3)*.
% 0.20/0.45  13[2:MRR:10.0,12.0] ||  -> big_f(skc3,u,v)*.
% 0.20/0.45  14[2:MRR:11.1,12.0] || big_f(u,skf1(v,u),skf1(v,u))* -> .
% 0.20/0.45  15[2:UnC:14.0,13.0] ||  -> .
% 0.20/0.45  16[2:Spt:15.0,7.1,12.0] || big_f(skc2,skc3,skc3)* -> .
% 0.20/0.45  17[2:Spt:15.0,7.0] || big_f(skc3,skc3,u)* -> .
% 0.20/0.45  18[2:UnC:17.0,1.0] ||  -> .
% 0.20/0.45  19[1:Spt:18.0,2.0,9.0] ||  -> big_f(skc2,skc2,skc3)*.
% 0.20/0.45  20[1:Spt:18.0,2.1] ||  -> big_f(skc2,skc3,skc3)*.
% 0.20/0.45  21[1:MRR:8.1,19.0] || big_f(skc3,skc3,u)* -> .
% 0.20/0.45  22[1:UnC:21.0,1.0] ||  -> .
% 0.20/0.45  % SZS output end Refutation
% 0.20/0.45  Formulae used in the proof : church_46_16_4
% 0.20/0.45  
%------------------------------------------------------------------------------