TSTP Solution File: SYN339+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYN339+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:16 EDT 2023

% Result   : Theorem 3.37s 3.60s
% Output   : Proof 3.37s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13  % Problem    : SYN339+1 : TPTP v8.1.2. Released v2.0.0.
% 0.12/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n027.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 17:52:20 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.37/3.60  SZS status Theorem for theBenchmark.p
% 3.37/3.60  SZS output start Proof for theBenchmark.p
% 3.37/3.60  Clause #0 (by assumption #[]): Eq (Not (Exists fun X => ∀ (Y : Iota), Exists fun Z => big_f X Y Z → big_f Y Z Z)) True
% 3.37/3.60  Clause #1 (by clausification #[0]): Eq (Exists fun X => ∀ (Y : Iota), Exists fun Z => big_f X Y Z → big_f Y Z Z) False
% 3.37/3.60  Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (Y : Iota), Exists fun Z => big_f a Y Z → big_f Y Z Z) False
% 3.37/3.60  Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota), Eq (Not (Exists fun Z => big_f a (skS.0 0 a a_1) Z → big_f (skS.0 0 a a_1) Z Z)) True
% 3.37/3.60  Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Exists fun Z => big_f a (skS.0 0 a a_1) Z → big_f (skS.0 0 a a_1) Z Z) False
% 3.37/3.60  Clause #5 (by clausification #[4]): ∀ (a a_1 a_2 : Iota), Eq (big_f a (skS.0 0 a a_1) a_2 → big_f (skS.0 0 a a_1) a_2 a_2) False
% 3.37/3.60  Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (big_f a (skS.0 0 a a_1) a_2) True
% 3.37/3.60  Clause #7 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (big_f (skS.0 0 a a_1) a_2 a_2) False
% 3.37/3.60  Clause #8 (by superposition #[7, 6]): Eq False True
% 3.37/3.60  Clause #9 (by clausification #[8]): False
% 3.37/3.60  SZS output end Proof for theBenchmark.p
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