TSTP Solution File: SYN339+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN339+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n027.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:11:16 EDT 2023
% Result : Theorem 3.37s 3.60s
% Output : Proof 3.37s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13 % Problem : SYN339+1 : TPTP v8.1.2. Released v2.0.0.
% 0.12/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n027.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 17:52:20 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.37/3.60 SZS status Theorem for theBenchmark.p
% 3.37/3.60 SZS output start Proof for theBenchmark.p
% 3.37/3.60 Clause #0 (by assumption #[]): Eq (Not (Exists fun X => ∀ (Y : Iota), Exists fun Z => big_f X Y Z → big_f Y Z Z)) True
% 3.37/3.60 Clause #1 (by clausification #[0]): Eq (Exists fun X => ∀ (Y : Iota), Exists fun Z => big_f X Y Z → big_f Y Z Z) False
% 3.37/3.60 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (Y : Iota), Exists fun Z => big_f a Y Z → big_f Y Z Z) False
% 3.37/3.60 Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota), Eq (Not (Exists fun Z => big_f a (skS.0 0 a a_1) Z → big_f (skS.0 0 a a_1) Z Z)) True
% 3.37/3.60 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota), Eq (Exists fun Z => big_f a (skS.0 0 a a_1) Z → big_f (skS.0 0 a a_1) Z Z) False
% 3.37/3.60 Clause #5 (by clausification #[4]): ∀ (a a_1 a_2 : Iota), Eq (big_f a (skS.0 0 a a_1) a_2 → big_f (skS.0 0 a a_1) a_2 a_2) False
% 3.37/3.60 Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (big_f a (skS.0 0 a a_1) a_2) True
% 3.37/3.60 Clause #7 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (big_f (skS.0 0 a a_1) a_2 a_2) False
% 3.37/3.60 Clause #8 (by superposition #[7, 6]): Eq False True
% 3.37/3.60 Clause #9 (by clausification #[8]): False
% 3.37/3.60 SZS output end Proof for theBenchmark.p
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