TSTP Solution File: SYN337-10 by Otter---3.3
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SYN337-10 : TPTP v8.1.0. Released v7.3.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:24:17 EDT 2022
% Result : Unknown 1.90s 2.09s
% Output : None
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11 % Problem : SYN337-10 : TPTP v8.1.0. Released v7.3.0.
% 0.07/0.12 % Command : otter-tptp-script %s
% 0.12/0.33 % Computer : n020.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Wed Jul 27 11:27:08 EDT 2022
% 0.12/0.33 % CPUTime :
% 1.90/2.09 ----- Otter 3.3f, August 2004 -----
% 1.90/2.09 The process was started by sandbox on n020.cluster.edu,
% 1.90/2.09 Wed Jul 27 11:27:08 2022
% 1.90/2.09 The command was "./otter". The process ID is 24503.
% 1.90/2.09
% 1.90/2.09 set(prolog_style_variables).
% 1.90/2.09 set(auto).
% 1.90/2.09 dependent: set(auto1).
% 1.90/2.09 dependent: set(process_input).
% 1.90/2.09 dependent: clear(print_kept).
% 1.90/2.09 dependent: clear(print_new_demod).
% 1.90/2.09 dependent: clear(print_back_demod).
% 1.90/2.09 dependent: clear(print_back_sub).
% 1.90/2.09 dependent: set(control_memory).
% 1.90/2.09 dependent: assign(max_mem, 12000).
% 1.90/2.09 dependent: assign(pick_given_ratio, 4).
% 1.90/2.09 dependent: assign(stats_level, 1).
% 1.90/2.09 dependent: assign(max_seconds, 10800).
% 1.90/2.09 clear(print_given).
% 1.90/2.09
% 1.90/2.09 list(usable).
% 1.90/2.09 0 [] A=A.
% 1.90/2.09 0 [] ife_q(A,A,B,C)=B.
% 1.90/2.09 0 [] f(a,Y)=true.
% 1.90/2.09 0 [] f(z(Y),a)=true.
% 1.90/2.09 0 [] f(z(Y),Y)=true.
% 1.90/2.09 0 [] ife_q(f(b,Y),true,a2,b2)=b2.
% 1.90/2.09 0 [] ife_q(f(b,z(Y)),true,a2,b2)=b2.
% 1.90/2.09 0 [] a2!=b2.
% 1.90/2.09 end_of_list.
% 1.90/2.09
% 1.90/2.09 SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.90/2.09
% 1.90/2.09 All clauses are units, and equality is present; the
% 1.90/2.09 strategy will be Knuth-Bendix with positive clauses in sos.
% 1.90/2.09
% 1.90/2.09 dependent: set(knuth_bendix).
% 1.90/2.09 dependent: set(anl_eq).
% 1.90/2.09 dependent: set(para_from).
% 1.90/2.09 dependent: set(para_into).
% 1.90/2.09 dependent: clear(para_from_right).
% 1.90/2.09 dependent: clear(para_into_right).
% 1.90/2.09 dependent: set(para_from_vars).
% 1.90/2.09 dependent: set(eq_units_both_ways).
% 1.90/2.09 dependent: set(dynamic_demod_all).
% 1.90/2.09 dependent: set(dynamic_demod).
% 1.90/2.09 dependent: set(order_eq).
% 1.90/2.09 dependent: set(back_demod).
% 1.90/2.09 dependent: set(lrpo).
% 1.90/2.09
% 1.90/2.09 ------------> process usable:
% 1.90/2.09 ** KEPT (pick-wt=3): 2 [copy,1,flip.1] b2!=a2.
% 1.90/2.09
% 1.90/2.09 ------------> process sos:
% 1.90/2.09 ** KEPT (pick-wt=3): 3 [] A=A.
% 1.90/2.09 ** KEPT (pick-wt=7): 4 [] ife_q(A,A,B,C)=B.
% 1.90/2.09 ---> New Demodulator: 5 [new_demod,4] ife_q(A,A,B,C)=B.
% 1.90/2.09 ** KEPT (pick-wt=5): 6 [] f(a,A)=true.
% 1.90/2.09 ---> New Demodulator: 7 [new_demod,6] f(a,A)=true.
% 1.90/2.09 ** KEPT (pick-wt=6): 8 [] f(z(A),a)=true.
% 1.90/2.09 ---> New Demodulator: 9 [new_demod,8] f(z(A),a)=true.
% 1.90/2.09 ** KEPT (pick-wt=6): 10 [] f(z(A),A)=true.
% 1.90/2.09 ---> New Demodulator: 11 [new_demod,10] f(z(A),A)=true.
% 1.90/2.09 ** KEPT (pick-wt=9): 12 [] ife_q(f(b,A),true,a2,b2)=b2.
% 1.90/2.09 ---> New Demodulator: 13 [new_demod,12] ife_q(f(b,A),true,a2,b2)=b2.
% 1.90/2.09 Following clause subsumed by 3 during input processing: 0 [demod,13] b2=b2.
% 1.90/2.09 Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.90/2.09 >>>> Starting back demodulation with 5.
% 1.90/2.09 >>>> Starting back demodulation with 7.
% 1.90/2.09 >>>> Starting back demodulation with 9.
% 1.90/2.09 >>>> Starting back demodulation with 11.
% 1.90/2.09 >>>> Starting back demodulation with 13.
% 1.90/2.09
% 1.90/2.09 ======= end of input processing =======
% 1.90/2.09
% 1.90/2.09 =========== start of search ===========
% 1.90/2.09
% 1.90/2.09 Search stopped because sos empty.
% 1.90/2.09
% 1.90/2.09
% 1.90/2.09 Search stopped because sos empty.
% 1.90/2.09
% 1.90/2.09 ============ end of search ============
% 1.90/2.09
% 1.90/2.09 -------------- statistics -------------
% 1.90/2.09 clauses given 6
% 1.90/2.09 clauses generated 12
% 1.90/2.09 clauses kept 7
% 1.90/2.09 clauses forward subsumed 14
% 1.90/2.09 clauses back subsumed 0
% 1.90/2.09 Kbytes malloced 976
% 1.90/2.09
% 1.90/2.09 ----------- times (seconds) -----------
% 1.90/2.09 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.90/2.09 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.90/2.09 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.90/2.09
% 1.90/2.09 Process 24503 finished Wed Jul 27 11:27:10 2022
% 1.90/2.09 Otter interrupted
% 1.90/2.09 PROOF NOT FOUND
%------------------------------------------------------------------------------