TSTP Solution File: SYN336+1 by Otter---3.3
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- Process Solution
%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SYN336+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:24:17 EDT 2022
% Result : Theorem 1.68s 1.87s
% Output : Refutation 1.68s
% Verified :
% SZS Type : Refutation
% Derivation depth : 1
% Number of leaves : 2
% Syntax : Number of clauses : 3 ( 3 unt; 0 nHn; 2 RR)
% Number of literals : 3 ( 0 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 2 ( 2 usr; 1 con; 0-2 aty)
% Number of variables : 3 ( 2 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
~ big_f(dollar_f1(A,B),B),
file('SYN336+1.p',unknown),
[] ).
cnf(5,axiom,
big_f(A,dollar_c1),
file('SYN336+1.p',unknown),
[] ).
cnf(6,plain,
$false,
inference(binary,[status(thm)],[5,1]),
[iquote('binary,5.1,1.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12 % Problem : SYN336+1 : TPTP v8.1.0. Released v2.0.0.
% 0.11/0.12 % Command : otter-tptp-script %s
% 0.12/0.33 % Computer : n003.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Wed Jul 27 11:13:56 EDT 2022
% 0.12/0.33 % CPUTime :
% 1.68/1.87
% 1.68/1.87 -------- PROOF --------
% 1.68/1.87 ----- Otter 3.3f, August 2004 -----
% 1.68/1.87 The process was started by sandbox on n003.cluster.edu,
% 1.68/1.87 Wed Jul 27 11:13:56 2022
% 1.68/1.87 The command was "./otter". The process ID is 27184.
% 1.68/1.87
% 1.68/1.87 set(prolog_style_variables).
% 1.68/1.87 set(auto).
% 1.68/1.87 dependent: set(auto1).
% 1.68/1.87 dependent: set(process_input).
% 1.68/1.87 dependent: clear(print_kept).
% 1.68/1.87 dependent: clear(print_new_demod).
% 1.68/1.87 dependent: clear(print_back_demod).
% 1.68/1.87 dependent: clear(print_back_sub).
% 1.68/1.87 dependent: set(control_memory).
% 1.68/1.87 dependent: assign(max_mem, 12000).
% 1.68/1.87 dependent: assign(pick_given_ratio, 4).
% 1.68/1.87 dependent: assign(stats_level, 1).
% 1.68/1.87 dependent: assign(max_seconds, 10800).
% 1.68/1.87 clear(print_given).
% 1.68/1.87
% 1.68/1.87 formula_list(usable).
% 1.68/1.87 -(all X exists Y1 Y2 all Z (big_f(X,Z)-> (big_f(Y1,Z)-> (big_f(Y2,Z)-> (big_f(Y1,X)->big_f(Z,Y2)))))).
% 1.68/1.87 end_of_list.
% 1.68/1.87
% 1.68/1.87 -------> usable clausifies to:
% 1.68/1.87
% 1.68/1.87 list(usable).
% 1.68/1.87 0 [] big_f($c1,$f1(Y1,Y2)).
% 1.68/1.87 0 [] big_f(Y1,$f1(Y1,Y2)).
% 1.68/1.87 0 [] big_f(Y2,$f1(Y1,Y2)).
% 1.68/1.87 0 [] big_f(Y1,$c1).
% 1.68/1.87 0 [] -big_f($f1(Y1,Y2),Y2).
% 1.68/1.87 end_of_list.
% 1.68/1.87
% 1.68/1.87 SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=1.
% 1.68/1.87
% 1.68/1.87 This is a Horn set without equality. The strategy will
% 1.68/1.87 be hyperresolution, with satellites in sos and nuclei
% 1.68/1.87 in usable.
% 1.68/1.87
% 1.68/1.87 dependent: set(hyper_res).
% 1.68/1.87 dependent: clear(order_hyper).
% 1.68/1.87
% 1.68/1.87 ------------> process usable:
% 1.68/1.87 ** KEPT (pick-wt=5): 1 [] -big_f($f1(A,B),B).
% 1.68/1.87
% 1.68/1.87 ------------> process sos:
% 1.68/1.87 ** KEPT (pick-wt=5): 2 [] big_f($c1,$f1(A,B)).
% 1.68/1.87 ** KEPT (pick-wt=5): 3 [] big_f(A,$f1(A,B)).
% 1.68/1.87 ** KEPT (pick-wt=5): 4 [] big_f(A,$f1(B,A)).
% 1.68/1.87 ** KEPT (pick-wt=3): 5 [] big_f(A,$c1).
% 1.68/1.87
% 1.68/1.87 ----> UNIT CONFLICT at 0.00 sec ----> 6 [binary,5.1,1.1] $F.
% 1.68/1.87
% 1.68/1.87 Length of proof is 0. Level of proof is 0.
% 1.68/1.87
% 1.68/1.87 ---------------- PROOF ----------------
% 1.68/1.87 % SZS status Theorem
% 1.68/1.87 % SZS output start Refutation
% See solution above
% 1.68/1.87 ------------ end of proof -------------
% 1.68/1.87
% 1.68/1.87
% 1.68/1.87 Search stopped by max_proofs option.
% 1.68/1.87
% 1.68/1.87
% 1.68/1.87 Search stopped by max_proofs option.
% 1.68/1.87
% 1.68/1.87 ============ end of search ============
% 1.68/1.87
% 1.68/1.87 -------------- statistics -------------
% 1.68/1.87 clauses given 0
% 1.68/1.87 clauses generated 0
% 1.68/1.87 clauses kept 5
% 1.68/1.87 clauses forward subsumed 0
% 1.68/1.87 clauses back subsumed 0
% 1.68/1.87 Kbytes malloced 976
% 1.68/1.87
% 1.68/1.87 ----------- times (seconds) -----------
% 1.68/1.87 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.68/1.87 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.68/1.87 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.68/1.87
% 1.68/1.87 That finishes the proof of the theorem.
% 1.68/1.87
% 1.68/1.87 Process 27184 finished Wed Jul 27 11:13:58 2022
% 1.68/1.87 Otter interrupted
% 1.68/1.87 PROOF FOUND
%------------------------------------------------------------------------------