TSTP Solution File: SYN329+1 by Crossbow---0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : SYN329+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 03:01:21 EDT 2022

% Result   : CounterSatisfiable 0.18s 0.37s
% Output   : FiniteModel 0.18s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem    : SYN329+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12  % Command    : do_Crossbow---0.1 %s
% 0.11/0.33  % Computer : n016.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit   : 300
% 0.11/0.33  % WCLimit    : 600
% 0.11/0.33  % DateTime   : Tue Jul 12 04:09:29 EDT 2022
% 0.11/0.33  % CPUTime    : 
% 0.11/0.33  /export/starexec/sandbox2/solver/bin
% 0.11/0.34  crossbow.opt
% 0.11/0.34  do_Crossbow---0.1
% 0.11/0.34  eprover
% 0.11/0.34  runsolver
% 0.11/0.34  starexec_run_Crossbow---0.1
% 0.18/0.37  % SZS status CounterSatisfiable for theBenchmark.p
% 0.18/0.37  % SZS output start FiniteModel for theBenchmark.p
% 0.18/0.37  % domain size: 6
% 0.18/0.37  fof(interp, fi_domain, ![X] : (X = 0 | X = 1 | X = 2 | X = 3 | X = 4 | X = 5)).
% 0.18/0.37  fof(interp, fi_predicates, big_f(0, 0) & big_f(0, 1) & big_f(0, 2) &
% 0.18/0.37    ~big_f(0, 3) &
% 0.18/0.37    ~big_f(0, 4) &
% 0.18/0.37    big_f(0, 5) &
% 0.18/0.37    ~big_f(1, 0) &
% 0.18/0.37    big_f(1, 1) &
% 0.18/0.37    big_f(1, 2) &
% 0.18/0.37    ~big_f(1, 3) &
% 0.18/0.37    ~big_f(1, 4) &
% 0.18/0.37    big_f(1, 5) &
% 0.18/0.37    big_f(2, 0) &
% 0.18/0.37    ~big_f(2, 1) &
% 0.18/0.37    big_f(2, 2) &
% 0.18/0.37    big_f(2, 3) &
% 0.18/0.37    ~big_f(2, 4) &
% 0.18/0.37    ~big_f(2, 5) &
% 0.18/0.37    ~big_f(3, 0) &
% 0.18/0.37    big_f(3, 1) &
% 0.18/0.37    ~big_f(3, 2) &
% 0.18/0.37    big_f(3, 3) &
% 0.18/0.37    big_f(3, 4) &
% 0.18/0.37    ~big_f(3, 5) &
% 0.18/0.37    ~big_f(4, 0) &
% 0.18/0.37    ~big_f(4, 1) &
% 0.18/0.37    big_f(4, 2) &
% 0.18/0.37    ~big_f(4, 3) &
% 0.18/0.37    big_f(4, 4) &
% 0.18/0.37    big_f(4, 5) &
% 0.18/0.37    ~big_f(5, 0) &
% 0.18/0.37    big_f(5, 1) &
% 0.18/0.37    ~big_f(5, 2) &
% 0.18/0.37    big_f(5, 3) &
% 0.18/0.37    big_f(5, 4) &
% 0.18/0.37    big_f(5, 5)).
% 0.18/0.37  fof(interp, fi_functors, esk1_2(0, 0) = 1 & esk1_2(0, 1) = 2 & esk1_2(0, 2) = 5 &
% 0.18/0.37    esk1_2(0, 3) = 1 &
% 0.18/0.37    esk1_2(0, 4) = 0 &
% 0.18/0.37    esk1_2(0, 5) = 2 &
% 0.18/0.37    esk1_2(1, 0) = 1 &
% 0.18/0.37    esk1_2(1, 1) = 2 &
% 0.18/0.37    esk1_2(1, 2) = 5 &
% 0.18/0.37    esk1_2(1, 3) = 1 &
% 0.18/0.37    esk1_2(1, 4) = 2 &
% 0.18/0.37    esk1_2(1, 5) = 2 &
% 0.18/0.37    esk1_2(2, 0) = 3 &
% 0.18/0.37    esk1_2(2, 1) = 2 &
% 0.18/0.37    esk1_2(2, 2) = 3 &
% 0.18/0.37    esk1_2(2, 3) = 0 &
% 0.18/0.37    esk1_2(2, 4) = 0 &
% 0.18/0.37    esk1_2(2, 5) = 3 &
% 0.18/0.37    esk1_2(3, 0) = 1 &
% 0.18/0.37    esk1_2(3, 1) = 4 &
% 0.18/0.37    esk1_2(3, 2) = 3 &
% 0.18/0.37    esk1_2(3, 3) = 4 &
% 0.18/0.37    esk1_2(3, 4) = 1 &
% 0.18/0.37    esk1_2(3, 5) = 3 &
% 0.18/0.37    esk1_2(4, 0) = 5 &
% 0.18/0.37    esk1_2(4, 1) = 2 &
% 0.18/0.37    esk1_2(4, 2) = 5 &
% 0.18/0.37    esk1_2(4, 3) = 4 &
% 0.18/0.37    esk1_2(4, 4) = 2 &
% 0.18/0.37    esk1_2(4, 5) = 2 &
% 0.18/0.37    esk1_2(5, 0) = 5 &
% 0.18/0.37    esk1_2(5, 1) = 4 &
% 0.18/0.37    esk1_2(5, 2) = 5 &
% 0.18/0.37    esk1_2(5, 3) = 1 &
% 0.18/0.37    esk1_2(5, 4) = 1 &
% 0.18/0.37    esk1_2(5, 5) = 3).
% 0.18/0.37  % SZS output end FiniteModel for theBenchmark.p
% 0.18/0.38  % 0 lemma(s) from E
% 0.18/0.38  % 1 pred(s)
% 0.18/0.38  % 1 func(s)
% 0.18/0.38  % 1 sort(s)
% 0.18/0.38  % 4 clause(s)
% 0.18/0.38  % Instantiating 1 (13 ms)
% 0.18/0.38  % Solving (13 ms)
% 0.18/0.38  % Instantiating 2 (13 ms)
% 0.18/0.38  % Solving (13 ms)
% 0.18/0.38  % Instantiating 3 (13 ms)
% 0.18/0.38  % Solving (13 ms)
% 0.18/0.38  % Instantiating 4 (13 ms)
% 0.18/0.38  % Solving (13 ms)
% 0.18/0.38  % Instantiating 5 (13 ms)
% 0.18/0.38  % Solving (14 ms)
% 0.18/0.38  % Instantiating 6 (14 ms)
% 0.18/0.38  % Solving (14 ms)
% 0.18/0.38  % 
% 0.18/0.38  % 1 model found (15 ms)
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