TSTP Solution File: SYN319+1 by Otter---3.3
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- Process Solution
%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SYN319+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n005.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:24:13 EDT 2022
% Result : Theorem 1.62s 1.80s
% Output : Refutation 1.62s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 4
% Syntax : Number of clauses : 8 ( 4 unt; 2 nHn; 4 RR)
% Number of literals : 12 ( 0 equ; 3 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-1 aty)
% Number of functors : 1 ( 1 usr; 0 con; 2-2 aty)
% Number of variables : 10 ( 8 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(4,axiom,
( ~ big_f(A)
| big_h(A) ),
file('SYN319+1.p',unknown),
[] ).
cnf(5,axiom,
( ~ big_g(A)
| big_h(A) ),
file('SYN319+1.p',unknown),
[] ).
cnf(6,axiom,
~ big_h(dollar_f1(A,B)),
file('SYN319+1.p',unknown),
[] ).
cnf(7,axiom,
( big_f(A)
| big_g(B) ),
file('SYN319+1.p',unknown),
[] ).
cnf(8,plain,
( big_f(A)
| big_h(B) ),
inference(hyper,[status(thm)],[7,5]),
[iquote('hyper,7,5')] ).
cnf(9,plain,
big_f(A),
inference(hyper,[status(thm)],[8,6]),
[iquote('hyper,8,6')] ).
cnf(10,plain,
big_h(A),
inference(hyper,[status(thm)],[9,4]),
[iquote('hyper,9,4')] ).
cnf(11,plain,
$false,
inference(binary,[status(thm)],[10,6]),
[iquote('binary,10.1,6.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYN319+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.13 % Command : otter-tptp-script %s
% 0.13/0.34 % Computer : n005.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Wed Jul 27 11:12:05 EDT 2022
% 0.13/0.34 % CPUTime :
% 1.62/1.80 ----- Otter 3.3f, August 2004 -----
% 1.62/1.80 The process was started by sandbox on n005.cluster.edu,
% 1.62/1.80 Wed Jul 27 11:12:05 2022
% 1.62/1.80 The command was "./otter". The process ID is 2071.
% 1.62/1.80
% 1.62/1.80 set(prolog_style_variables).
% 1.62/1.80 set(auto).
% 1.62/1.80 dependent: set(auto1).
% 1.62/1.80 dependent: set(process_input).
% 1.62/1.80 dependent: clear(print_kept).
% 1.62/1.80 dependent: clear(print_new_demod).
% 1.62/1.80 dependent: clear(print_back_demod).
% 1.62/1.80 dependent: clear(print_back_sub).
% 1.62/1.80 dependent: set(control_memory).
% 1.62/1.80 dependent: assign(max_mem, 12000).
% 1.62/1.80 dependent: assign(pick_given_ratio, 4).
% 1.62/1.80 dependent: assign(stats_level, 1).
% 1.62/1.80 dependent: assign(max_seconds, 10800).
% 1.62/1.80 clear(print_given).
% 1.62/1.80
% 1.62/1.80 formula_list(usable).
% 1.62/1.80 -(exists X Y all Z1 Z2 (((big_f(Y)->big_g(Z1))->big_g(X)& -big_f(Z1))-> ((big_f(X)|big_g(X)->big_h(X))->big_h(Z2)& (big_h(Y)-> (big_f(Z2)|big_g(Z2)->big_h(Z2)))))).
% 1.62/1.80 end_of_list.
% 1.62/1.80
% 1.62/1.80 -------> usable clausifies to:
% 1.62/1.80
% 1.62/1.80 list(usable).
% 1.62/1.80 0 [] big_f(Y)|big_g(X).
% 1.62/1.80 0 [] big_f(Y)| -big_f($f2(X,Y)).
% 1.62/1.80 0 [] -big_g($f2(X,Y))|big_g(X).
% 1.62/1.80 0 [] -big_g($f2(X,Y))| -big_f($f2(X,Y)).
% 1.62/1.80 0 [] -big_f(X)|big_h(X).
% 1.62/1.80 0 [] -big_g(X)|big_h(X).
% 1.62/1.80 0 [] -big_h($f1(X,Y)).
% 1.62/1.80 end_of_list.
% 1.62/1.80
% 1.62/1.80 SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=2.
% 1.62/1.80
% 1.62/1.80 This is a non-Horn set without equality. The strategy will
% 1.62/1.80 be ordered hyper_res, unit deletion, and factoring, with
% 1.62/1.80 satellites in sos and with nuclei in usable.
% 1.62/1.80
% 1.62/1.80 dependent: set(hyper_res).
% 1.62/1.80 dependent: set(factor).
% 1.62/1.80 dependent: set(unit_deletion).
% 1.62/1.80
% 1.62/1.80 ------------> process usable:
% 1.62/1.80 ** KEPT (pick-wt=6): 1 [] big_f(A)| -big_f($f2(B,A)).
% 1.62/1.80 ** KEPT (pick-wt=6): 2 [] -big_g($f2(A,B))|big_g(A).
% 1.62/1.80 ** KEPT (pick-wt=8): 3 [] -big_g($f2(A,B))| -big_f($f2(A,B)).
% 1.62/1.80 ** KEPT (pick-wt=4): 4 [] -big_f(A)|big_h(A).
% 1.62/1.80 ** KEPT (pick-wt=4): 5 [] -big_g(A)|big_h(A).
% 1.62/1.80 ** KEPT (pick-wt=4): 6 [] -big_h($f1(A,B)).
% 1.62/1.80
% 1.62/1.80 ------------> process sos:
% 1.62/1.80 ** KEPT (pick-wt=4): 7 [] big_f(A)|big_g(B).
% 1.62/1.80
% 1.62/1.80 ======= end of input processing =======
% 1.62/1.80
% 1.62/1.80 =========== start of search ===========
% 1.62/1.80
% 1.62/1.80 -------- PROOF --------
% 1.62/1.80
% 1.62/1.80 ----> UNIT CONFLICT at 0.00 sec ----> 11 [binary,10.1,6.1] $F.
% 1.62/1.80
% 1.62/1.80 Length of proof is 3. Level of proof is 3.
% 1.62/1.80
% 1.62/1.80 ---------------- PROOF ----------------
% 1.62/1.80 % SZS status Theorem
% 1.62/1.80 % SZS output start Refutation
% See solution above
% 1.62/1.80 ------------ end of proof -------------
% 1.62/1.80
% 1.62/1.80
% 1.62/1.80 Search stopped by max_proofs option.
% 1.62/1.80
% 1.62/1.80
% 1.62/1.80 Search stopped by max_proofs option.
% 1.62/1.80
% 1.62/1.80 ============ end of search ============
% 1.62/1.80
% 1.62/1.80 -------------- statistics -------------
% 1.62/1.80 clauses given 3
% 1.62/1.80 clauses generated 4
% 1.62/1.80 clauses kept 10
% 1.62/1.80 clauses forward subsumed 1
% 1.62/1.80 clauses back subsumed 3
% 1.62/1.80 Kbytes malloced 976
% 1.62/1.80
% 1.62/1.80 ----------- times (seconds) -----------
% 1.62/1.80 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.62/1.80 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.62/1.80 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.62/1.80
% 1.62/1.80 That finishes the proof of the theorem.
% 1.62/1.80
% 1.62/1.80 Process 2071 finished Wed Jul 27 11:12:07 2022
% 1.62/1.80 Otter interrupted
% 1.62/1.80 PROOF FOUND
%------------------------------------------------------------------------------