TSTP Solution File: SYN317+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN317+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:24:13 EDT 2022

% Result   : Theorem 1.68s 1.92s
% Output   : Refutation 1.68s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    2
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    6 (   3 unt;   2 nHn;   4 RR)
%            Number of literals    :   11 (   0 equ;   5 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-1 aty)
%            Number of functors    :    3 (   3 usr;   3 con; 0-0 aty)
%            Number of variables   :    6 (   6 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ big_f(dollar_c1)
    | big_g(dollar_c1)
    | ~ big_f(dollar_c3)
    | big_g(dollar_c2) ),
    file('SYN317+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ big_g(A)
    | ~ big_g(B) ),
    file('SYN317+1.p',unknown),
    [] ).

cnf(4,plain,
    ~ big_g(A),
    inference(factor_simp,[status(thm)],[inference(copy,[status(thm)],[3])]),
    [iquote('copy,3,factor_simp')] ).

cnf(5,axiom,
    ( big_f(A)
    | big_f(B) ),
    file('SYN317+1.p',unknown),
    [] ).

cnf(6,plain,
    big_f(A),
    inference(factor_simp,[status(thm)],[inference(copy,[status(thm)],[5])]),
    [iquote('copy,5,factor_simp')] ).

cnf(7,plain,
    $false,
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[6,1,6]),4,4]),
    [iquote('hyper,6,1,6,unit_del,4,4')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : SYN317+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.14  % Command  : otter-tptp-script %s
% 0.13/0.35  % Computer : n022.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 300
% 0.13/0.35  % DateTime : Wed Jul 27 11:22:50 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 1.68/1.92  ----- Otter 3.3f, August 2004 -----
% 1.68/1.92  The process was started by sandbox2 on n022.cluster.edu,
% 1.68/1.92  Wed Jul 27 11:22:50 2022
% 1.68/1.92  The command was "./otter".  The process ID is 20598.
% 1.68/1.92  
% 1.68/1.92  set(prolog_style_variables).
% 1.68/1.92  set(auto).
% 1.68/1.92     dependent: set(auto1).
% 1.68/1.92     dependent: set(process_input).
% 1.68/1.92     dependent: clear(print_kept).
% 1.68/1.92     dependent: clear(print_new_demod).
% 1.68/1.92     dependent: clear(print_back_demod).
% 1.68/1.92     dependent: clear(print_back_sub).
% 1.68/1.92     dependent: set(control_memory).
% 1.68/1.92     dependent: assign(max_mem, 12000).
% 1.68/1.92     dependent: assign(pick_given_ratio, 4).
% 1.68/1.92     dependent: assign(stats_level, 1).
% 1.68/1.92     dependent: assign(max_seconds, 10800).
% 1.68/1.92  clear(print_given).
% 1.68/1.92  
% 1.68/1.92  formula_list(usable).
% 1.68/1.92  -((exists X (big_f(X)->big_g(X)))<-> (exists X Y (big_f(X)->big_g(Y)))).
% 1.68/1.92  end_of_list.
% 1.68/1.92  
% 1.68/1.92  -------> usable clausifies to:
% 1.68/1.92  
% 1.68/1.92  list(usable).
% 1.68/1.92  0 [] -big_f($c1)|big_g($c1)| -big_f($c3)|big_g($c2).
% 1.68/1.92  0 [] big_f(X)|big_f(X1).
% 1.68/1.92  0 [] big_f(X)| -big_g(Y).
% 1.68/1.92  0 [] -big_g(X)|big_f(X1).
% 1.68/1.92  0 [] -big_g(X)| -big_g(Y).
% 1.68/1.92  end_of_list.
% 1.68/1.92  
% 1.68/1.92  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=4.
% 1.68/1.92  
% 1.68/1.92  This is a non-Horn set without equality.  The strategy will
% 1.68/1.92  be ordered hyper_res, unit deletion, and factoring, with
% 1.68/1.92  satellites in sos and with nuclei in usable.
% 1.68/1.92  
% 1.68/1.92     dependent: set(hyper_res).
% 1.68/1.92     dependent: set(factor).
% 1.68/1.92     dependent: set(unit_deletion).
% 1.68/1.92  
% 1.68/1.92  ------------> process usable:
% 1.68/1.92  ** KEPT (pick-wt=8): 1 [] -big_f($c1)|big_g($c1)| -big_f($c3)|big_g($c2).
% 1.68/1.92  ** KEPT (pick-wt=4): 2 [] big_f(A)| -big_g(B).
% 1.68/1.92    Following clause subsumed by 2 during input processing: 0 [] -big_g(A)|big_f(B).
% 1.68/1.92  ** KEPT (pick-wt=2): 4 [copy,3,factor_simp] -big_g(A).
% 1.68/1.92  4 back subsumes 2.
% 1.68/1.92  
% 1.68/1.92  ------------> process sos:
% 1.68/1.92  ** KEPT (pick-wt=2): 6 [copy,5,factor_simp] big_f(A).
% 1.68/1.92  
% 1.68/1.92  ======= end of input processing =======
% 1.68/1.92  
% 1.68/1.92  =========== start of search ===========
% 1.68/1.92  
% 1.68/1.92  -------- PROOF -------- 
% 1.68/1.92  
% 1.68/1.92  -----> EMPTY CLAUSE at   0.00 sec ----> 7 [hyper,6,1,6,unit_del,4,4] $F.
% 1.68/1.92  
% 1.68/1.92  Length of proof is 2.  Level of proof is 1.
% 1.68/1.92  
% 1.68/1.92  ---------------- PROOF ----------------
% 1.68/1.92  % SZS status Theorem
% 1.68/1.92  % SZS output start Refutation
% See solution above
% 1.68/1.92  ------------ end of proof -------------
% 1.68/1.92  
% 1.68/1.92  
% 1.68/1.92  Search stopped by max_proofs option.
% 1.68/1.92  
% 1.68/1.92  
% 1.68/1.92  Search stopped by max_proofs option.
% 1.68/1.92  
% 1.68/1.92  ============ end of search ============
% 1.68/1.92  
% 1.68/1.92  -------------- statistics -------------
% 1.68/1.92  clauses given                  1
% 1.68/1.92  clauses generated              1
% 1.68/1.92  clauses kept                   4
% 1.68/1.92  clauses forward subsumed       1
% 1.68/1.92  clauses back subsumed          1
% 1.68/1.92  Kbytes malloced              976
% 1.68/1.92  
% 1.68/1.92  ----------- times (seconds) -----------
% 1.68/1.92  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.92  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.92  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.68/1.92  
% 1.68/1.92  That finishes the proof of the theorem.
% 1.68/1.92  
% 1.68/1.92  Process 20598 finished Wed Jul 27 11:22:52 2022
% 1.68/1.92  Otter interrupted
% 1.68/1.92  PROOF FOUND
%------------------------------------------------------------------------------