TSTP Solution File: SYN310-1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN310-1 : TPTP v8.1.0. Released v1.2.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:20:08 EDT 2022
% Result : Unsatisfiable 0.18s 0.40s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 13
% Number of leaves : 6
% Syntax : Number of clauses : 19 ( 15 unt; 0 nHn; 19 RR)
% Number of literals : 23 ( 0 equ; 5 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-3 aty)
% Number of functors : 8 ( 8 usr; 6 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
( ~ p(u,v,w)
| p(w,v,u) ),
file('SYN310-1.p',unknown),
[] ).
cnf(2,axiom,
( ~ p(u,v,w)
| p(v,u,w) ),
file('SYN310-1.p',unknown),
[] ).
cnf(3,axiom,
( ~ p(u,v,g(w))
| p(u,v,w) ),
file('SYN310-1.p',unknown),
[] ).
cnf(4,axiom,
( ~ p(f(u),v,w)
| p(u,v,w) ),
file('SYN310-1.p',unknown),
[] ).
cnf(5,axiom,
~ p(a,b,c),
file('SYN310-1.p',unknown),
[] ).
cnf(6,axiom,
p(f(g(a)),f(g(b)),f(g(c))),
file('SYN310-1.p',unknown),
[] ).
cnf(9,plain,
p(g(a),f(g(b)),f(g(c))),
inference(res,[status(thm),theory(equality)],[6,4]),
[iquote('0:Res:6.0,4.0')] ).
cnf(10,plain,
p(f(g(c)),f(g(b)),g(a)),
inference(res,[status(thm),theory(equality)],[9,1]),
[iquote('0:Res:9.0,1.0')] ).
cnf(14,plain,
p(g(c),f(g(b)),g(a)),
inference(res,[status(thm),theory(equality)],[10,4]),
[iquote('0:Res:10.0,4.0')] ).
cnf(20,plain,
p(g(c),f(g(b)),a),
inference(res,[status(thm),theory(equality)],[14,3]),
[iquote('0:Res:14.0,3.0')] ).
cnf(22,plain,
p(a,f(g(b)),g(c)),
inference(res,[status(thm),theory(equality)],[20,1]),
[iquote('0:Res:20.0,1.0')] ).
cnf(28,plain,
p(a,f(g(b)),c),
inference(res,[status(thm),theory(equality)],[22,3]),
[iquote('0:Res:22.0,3.0')] ).
cnf(30,plain,
p(f(g(b)),a,c),
inference(res,[status(thm),theory(equality)],[28,2]),
[iquote('0:Res:28.0,2.0')] ).
cnf(38,plain,
p(g(b),a,c),
inference(res,[status(thm),theory(equality)],[30,4]),
[iquote('0:Res:30.0,4.0')] ).
cnf(39,plain,
p(c,a,g(b)),
inference(res,[status(thm),theory(equality)],[38,1]),
[iquote('0:Res:38.0,1.0')] ).
cnf(43,plain,
p(c,a,b),
inference(res,[status(thm),theory(equality)],[39,3]),
[iquote('0:Res:39.0,3.0')] ).
cnf(47,plain,
p(b,a,c),
inference(res,[status(thm),theory(equality)],[43,1]),
[iquote('0:Res:43.0,1.0')] ).
cnf(50,plain,
p(a,b,c),
inference(res,[status(thm),theory(equality)],[47,2]),
[iquote('0:Res:47.0,2.0')] ).
cnf(51,plain,
$false,
inference(mrr,[status(thm)],[50,5]),
[iquote('0:MRR:50.0,5.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.09/0.11 % Problem : SYN310-1 : TPTP v8.1.0. Released v1.2.0.
% 0.09/0.11 % Command : run_spass %d %s
% 0.11/0.32 % Computer : n011.cluster.edu
% 0.11/0.32 % Model : x86_64 x86_64
% 0.11/0.32 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.32 % Memory : 8042.1875MB
% 0.11/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.32 % CPULimit : 300
% 0.11/0.32 % WCLimit : 600
% 0.11/0.32 % DateTime : Tue Jul 12 02:51:43 EDT 2022
% 0.11/0.33 % CPUTime :
% 0.18/0.40
% 0.18/0.40 SPASS V 3.9
% 0.18/0.40 SPASS beiseite: Proof found.
% 0.18/0.40 % SZS status Theorem
% 0.18/0.40 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.18/0.40 SPASS derived 44 clauses, backtracked 0 clauses, performed 0 splits and kept 41 clauses.
% 0.18/0.40 SPASS allocated 63113 KBytes.
% 0.18/0.40 SPASS spent 0:00:00.06 on the problem.
% 0.18/0.40 0:00:00.04 for the input.
% 0.18/0.40 0:00:00.00 for the FLOTTER CNF translation.
% 0.18/0.40 0:00:00.00 for inferences.
% 0.18/0.40 0:00:00.00 for the backtracking.
% 0.18/0.40 0:00:00.00 for the reduction.
% 0.18/0.40
% 0.18/0.40
% 0.18/0.40 Here is a proof with depth 12, length 19 :
% 0.18/0.40 % SZS output start Refutation
% See solution above
% 0.18/0.40 Formulae used in the proof : clause1 clause2 clause3 clause4 clause5 clause6
% 0.18/0.40
%------------------------------------------------------------------------------