TSTP Solution File: SYN309-1 by Bliksem---1.12
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%------------------------------------------------------------------------------
% File : Bliksem---1.12
% Problem : SYN309-1 : TPTP v8.1.0. Released v1.2.0.
% Transfm : none
% Format : tptp:raw
% Command : bliksem %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Thu Jul 21 02:49:26 EDT 2022
% Result : Satisfiable 0.62s 1.02s
% Output : Saturation 0.62s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.09 % Problem : SYN309-1 : TPTP v8.1.0. Released v1.2.0.
% 0.07/0.09 % Command : bliksem %s
% 0.09/0.29 % Computer : n008.cluster.edu
% 0.09/0.29 % Model : x86_64 x86_64
% 0.09/0.29 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.09/0.29 % Memory : 8042.1875MB
% 0.09/0.29 % OS : Linux 3.10.0-693.el7.x86_64
% 0.09/0.29 % CPULimit : 300
% 0.09/0.29 % DateTime : Mon Jul 11 22:49:08 EDT 2022
% 0.09/0.29 % CPUTime :
% 0.62/1.02 *** allocated 10000 integers for termspace/termends
% 0.62/1.02 *** allocated 10000 integers for clauses
% 0.62/1.02 *** allocated 10000 integers for justifications
% 0.62/1.02 Bliksem 1.12
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 Automatic Strategy Selection
% 0.62/1.02
% 0.62/1.02 Clauses:
% 0.62/1.02 [
% 0.62/1.02 [ p( f( X ), a, g( X ) ), ~( s( h( X, Y, Z ), a, h( X, Y, Z ) ) ) ],
% 0.62/1.02 [ r( f( a ), a, b ), s( h( a, X, Y ), b, h( a, X, Y ) ) ],
% 0.62/1.02 [ s( f( X ), X, X ), ~( p( k( X, Y ), k( X, Y ), b ) ), p( f( X ), g( X
% 0.62/1.02 ), g( X ) ) ],
% 0.62/1.02 [ s( f( X ), X, X ), p( f( Y ), Y, f( Y ) ) ],
% 0.62/1.02 [ p( X, X, X ) ],
% 0.62/1.02 [ p( a, b, c ) ]
% 0.62/1.02 ] .
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 percentage equality = 0.000000, percentage horn = 0.500000
% 0.62/1.02 This a non-horn, non-equality problem
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 Options Used:
% 0.62/1.02
% 0.62/1.02 useres = 1
% 0.62/1.02 useparamod = 0
% 0.62/1.02 useeqrefl = 0
% 0.62/1.02 useeqfact = 0
% 0.62/1.02 usefactor = 1
% 0.62/1.02 usesimpsplitting = 0
% 0.62/1.02 usesimpdemod = 0
% 0.62/1.02 usesimpres = 3
% 0.62/1.02
% 0.62/1.02 resimpinuse = 1000
% 0.62/1.02 resimpclauses = 20000
% 0.62/1.02 substype = standard
% 0.62/1.02 backwardsubs = 1
% 0.62/1.02 selectoldest = 5
% 0.62/1.02
% 0.62/1.02 litorderings [0] = split
% 0.62/1.02 litorderings [1] = liftord
% 0.62/1.02
% 0.62/1.02 termordering = none
% 0.62/1.02
% 0.62/1.02 litapriori = 1
% 0.62/1.02 termapriori = 0
% 0.62/1.02 litaposteriori = 0
% 0.62/1.02 termaposteriori = 0
% 0.62/1.02 demodaposteriori = 0
% 0.62/1.02 ordereqreflfact = 0
% 0.62/1.02
% 0.62/1.02 litselect = none
% 0.62/1.02
% 0.62/1.02 maxweight = 15
% 0.62/1.02 maxdepth = 30000
% 0.62/1.02 maxlength = 115
% 0.62/1.02 maxnrvars = 195
% 0.62/1.02 excuselevel = 1
% 0.62/1.02 increasemaxweight = 1
% 0.62/1.02
% 0.62/1.02 maxselected = 10000000
% 0.62/1.02 maxnrclauses = 10000000
% 0.62/1.02
% 0.62/1.02 showgenerated = 0
% 0.62/1.02 showkept = 0
% 0.62/1.02 showselected = 0
% 0.62/1.02 showdeleted = 0
% 0.62/1.02 showresimp = 1
% 0.62/1.02 showstatus = 2000
% 0.62/1.02
% 0.62/1.02 prologoutput = 1
% 0.62/1.02 nrgoals = 5000000
% 0.62/1.02 totalproof = 1
% 0.62/1.02
% 0.62/1.02 Symbols occurring in the translation:
% 0.62/1.02
% 0.62/1.02 {} [0, 0] (w:1, o:2, a:1, s:1, b:0),
% 0.62/1.02 . [1, 2] (w:1, o:22, a:1, s:1, b:0),
% 0.62/1.02 ! [4, 1] (w:0, o:15, a:1, s:1, b:0),
% 0.62/1.02 = [13, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.62/1.02 ==> [14, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.62/1.02 f [40, 1] (w:1, o:20, a:1, s:1, b:0),
% 0.62/1.02 a [41, 0] (w:1, o:10, a:1, s:1, b:0),
% 0.62/1.02 g [42, 1] (w:1, o:21, a:1, s:1, b:0),
% 0.62/1.02 p [43, 3] (w:1, o:48, a:1, s:1, b:0),
% 0.62/1.02 h [46, 3] (w:1, o:49, a:1, s:1, b:0),
% 0.62/1.02 s [47, 3] (w:1, o:51, a:1, s:1, b:0),
% 0.62/1.02 b [48, 0] (w:1, o:13, a:1, s:1, b:0),
% 0.62/1.02 r [49, 3] (w:1, o:50, a:1, s:1, b:0),
% 0.62/1.02 k [50, 2] (w:1, o:47, a:1, s:1, b:0),
% 0.62/1.02 c [51, 0] (w:1, o:14, a:1, s:1, b:0).
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 Starting Search:
% 0.62/1.02
% 0.62/1.02 Resimplifying inuse:
% 0.62/1.02 Done
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 found a saturation!
% 0.62/1.02 % SZS status Satisfiable
% 0.62/1.02 % SZS output start Saturation
% 0.62/1.02
% 0.62/1.02 clause( 2, [ ~( p( k( X, Y ), k( X, Y ), b ) ), p( f( X ), g( X ), g( X ) )
% 0.62/1.02 , s( f( X ), X, X ) ] )
% 0.62/1.02 .
% 0.62/1.02 clause( 0, [ p( f( X ), a, g( X ) ), ~( s( h( X, Y, Z ), a, h( X, Y, Z ) )
% 0.62/1.02 ) ] )
% 0.62/1.02 .
% 0.62/1.02 clause( 1, [ r( f( a ), a, b ), s( h( a, X, Y ), b, h( a, X, Y ) ) ] )
% 0.62/1.02 .
% 0.62/1.02 clause( 3, [ p( f( Y ), Y, f( Y ) ), s( f( X ), X, X ) ] )
% 0.62/1.02 .
% 0.62/1.02 clause( 5, [ p( a, b, c ) ] )
% 0.62/1.02 .
% 0.62/1.02 clause( 4, [ p( X, X, X ) ] )
% 0.62/1.02 .
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 % SZS output end Saturation
% 0.62/1.02 end of saturation!
% 0.62/1.02
% 0.62/1.02 Memory use:
% 0.62/1.02
% 0.62/1.02 space for terms: 257
% 0.62/1.02 space for clauses: 507
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 clauses generated: 6
% 0.62/1.02 clauses kept: 6
% 0.62/1.02 clauses selected: 6
% 0.62/1.02 clauses deleted: 0
% 0.62/1.02 clauses inuse deleted: 0
% 0.62/1.02
% 0.62/1.02 subsentry: 0
% 0.62/1.02 literals s-matched: 0
% 0.62/1.02 literals matched: 0
% 0.62/1.02 full subsumption: 0
% 0.62/1.02
% 0.62/1.02 checksum: -43911293
% 0.62/1.02
% 0.62/1.02
% 0.62/1.02 Bliksem ended
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