TSTP Solution File: SYN303-10 by Bliksem---1.12
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%------------------------------------------------------------------------------
% File : Bliksem---1.12
% Problem : SYN303-10 : TPTP v8.1.0. Released v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : bliksem %s
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Thu Jul 21 02:49:23 EDT 2022
% Result : Satisfiable 0.68s 1.10s
% Output : Saturation 0.68s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13 % Problem : SYN303-10 : TPTP v8.1.0. Released v7.5.0.
% 0.13/0.13 % Command : bliksem %s
% 0.13/0.35 % Computer : n011.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % DateTime : Tue Jul 12 08:55:58 EDT 2022
% 0.20/0.35 % CPUTime :
% 0.68/1.10 *** allocated 10000 integers for termspace/termends
% 0.68/1.10 *** allocated 10000 integers for clauses
% 0.68/1.10 *** allocated 10000 integers for justifications
% 0.68/1.10 Bliksem 1.12
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 Automatic Strategy Selection
% 0.68/1.10
% 0.68/1.10 Clauses:
% 0.68/1.10 [
% 0.68/1.10 [ =( ifeq( X, X, Y, Z ), Y ) ],
% 0.68/1.10 [ =( p( X, X ), true ) ],
% 0.68/1.10 [ =( ifeq( p( X, Y ), true, p( Y, X ), true ), true ) ],
% 0.68/1.10 [ =( ifeq( p( f( X ), f( Y ) ), true, p( X, Y ), true ), true ) ],
% 0.68/1.10 [ =( ifeq( p( X, Y ), true, p( f( X ), f( Y ) ), true ), true ) ],
% 0.68/1.10 [ ~( =( p( a, f( X ) ), true ) ) ]
% 0.68/1.10 ] .
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 percentage equality = 1.000000, percentage horn = 1.000000
% 0.68/1.10 This is a pure equality problem
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 Options Used:
% 0.68/1.10
% 0.68/1.10 useres = 1
% 0.68/1.10 useparamod = 1
% 0.68/1.10 useeqrefl = 1
% 0.68/1.10 useeqfact = 1
% 0.68/1.10 usefactor = 1
% 0.68/1.10 usesimpsplitting = 0
% 0.68/1.10 usesimpdemod = 5
% 0.68/1.10 usesimpres = 3
% 0.68/1.10
% 0.68/1.10 resimpinuse = 1000
% 0.68/1.10 resimpclauses = 20000
% 0.68/1.10 substype = eqrewr
% 0.68/1.10 backwardsubs = 1
% 0.68/1.10 selectoldest = 5
% 0.68/1.10
% 0.68/1.10 litorderings [0] = split
% 0.68/1.10 litorderings [1] = extend the termordering, first sorting on arguments
% 0.68/1.10
% 0.68/1.10 termordering = kbo
% 0.68/1.10
% 0.68/1.10 litapriori = 0
% 0.68/1.10 termapriori = 1
% 0.68/1.10 litaposteriori = 0
% 0.68/1.10 termaposteriori = 0
% 0.68/1.10 demodaposteriori = 0
% 0.68/1.10 ordereqreflfact = 0
% 0.68/1.10
% 0.68/1.10 litselect = negord
% 0.68/1.10
% 0.68/1.10 maxweight = 15
% 0.68/1.10 maxdepth = 30000
% 0.68/1.10 maxlength = 115
% 0.68/1.10 maxnrvars = 195
% 0.68/1.10 excuselevel = 1
% 0.68/1.10 increasemaxweight = 1
% 0.68/1.10
% 0.68/1.10 maxselected = 10000000
% 0.68/1.10 maxnrclauses = 10000000
% 0.68/1.10
% 0.68/1.10 showgenerated = 0
% 0.68/1.10 showkept = 0
% 0.68/1.10 showselected = 0
% 0.68/1.10 showdeleted = 0
% 0.68/1.10 showresimp = 1
% 0.68/1.10 showstatus = 2000
% 0.68/1.10
% 0.68/1.10 prologoutput = 1
% 0.68/1.10 nrgoals = 5000000
% 0.68/1.10 totalproof = 1
% 0.68/1.10
% 0.68/1.10 Symbols occurring in the translation:
% 0.68/1.10
% 0.68/1.10 {} [0, 0] (w:1, o:2, a:1, s:1, b:0),
% 0.68/1.10 . [1, 2] (w:1, o:22, a:1, s:1, b:0),
% 0.68/1.10 ! [4, 1] (w:0, o:16, a:1, s:1, b:0),
% 0.68/1.10 = [13, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.68/1.10 ==> [14, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.68/1.10 ifeq [42, 4] (w:1, o:48, a:1, s:1, b:0),
% 0.68/1.10 p [44, 2] (w:1, o:47, a:1, s:1, b:0),
% 0.68/1.10 true [45, 0] (w:1, o:13, a:1, s:1, b:0),
% 0.68/1.10 f [47, 1] (w:1, o:21, a:1, s:1, b:0),
% 0.68/1.10 a [48, 0] (w:1, o:15, a:1, s:1, b:0).
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 Starting Search:
% 0.68/1.10
% 0.68/1.10 Resimplifying inuse:
% 0.68/1.10 Done
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 found a saturation!
% 0.68/1.10 % SZS status Satisfiable
% 0.68/1.10 % SZS output start Saturation
% 0.68/1.10
% 0.68/1.10 clause( 3, [ =( ifeq( p( f( X ), f( Y ) ), true, p( X, Y ), true ), true )
% 0.68/1.10 ] )
% 0.68/1.10 .
% 0.68/1.10 clause( 4, [ =( ifeq( p( X, Y ), true, p( f( X ), f( Y ) ), true ), true )
% 0.68/1.10 ] )
% 0.68/1.10 .
% 0.68/1.10 clause( 2, [ =( ifeq( p( X, Y ), true, p( Y, X ), true ), true ) ] )
% 0.68/1.10 .
% 0.68/1.10 clause( 0, [ =( ifeq( X, X, Y, Z ), Y ) ] )
% 0.68/1.10 .
% 0.68/1.10 clause( 5, [ ~( =( p( a, f( X ) ), true ) ) ] )
% 0.68/1.10 .
% 0.68/1.10 clause( 1, [ =( p( X, X ), true ) ] )
% 0.68/1.10 .
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 % SZS output end Saturation
% 0.68/1.10 end of saturation!
% 0.68/1.10
% 0.68/1.10 Memory use:
% 0.68/1.10
% 0.68/1.10 space for terms: 199
% 0.68/1.10 space for clauses: 703
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 clauses generated: 22
% 0.68/1.10 clauses kept: 6
% 0.68/1.10 clauses selected: 6
% 0.68/1.10 clauses deleted: 0
% 0.68/1.10 clauses inuse deleted: 0
% 0.68/1.10
% 0.68/1.10 subsentry: 0
% 0.68/1.10 literals s-matched: 0
% 0.68/1.10 literals matched: 0
% 0.68/1.10 full subsumption: 0
% 0.68/1.10
% 0.68/1.10 checksum: 778051814
% 0.68/1.10
% 0.68/1.10
% 0.68/1.10 Bliksem ended
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