%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN264-1 : TPTP v8.1.0. Released v1.1.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:19:50 EDT 2022

% Result   : Unsatisfiable 0.18s 0.48s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :   10
% Syntax   : Number of clauses     :   17 (  11 unt;   0 nHn;  17 RR)
%            Number of literals    :   27 (   0 equ;  14 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    8 (   7 usr;   1 prp; 0-3 aty)
%            Number of functors    :    9 (   9 usr;   9 con; 0-0 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ~ p1(e,c,e),
    file('SYN264-1.p',unknown),
    [] ).

cnf(4,axiom,
    n0(d,e),
    file('SYN264-1.p',unknown),
    [] ).

cnf(6,axiom,
    s0(b),
    file('SYN264-1.p',unknown),
    [] ).

cnf(14,axiom,
    r0(e),
    file('SYN264-1.p',unknown),
    [] ).

cnf(21,axiom,
    l0(a),
    file('SYN264-1.p',unknown),
    [] ).

cnf(27,axiom,
    n0(d,c),
    file('SYN264-1.p',unknown),
    [] ).

cnf(29,axiom,
    k0(e),
    file('SYN264-1.p',unknown),
    [] ).

cnf(40,axiom,
    ( ~ n0(u,v)
    | k1(v) ),
    file('SYN264-1.p',unknown),
    [] ).

cnf(102,axiom,
    ( ~ k0(u)
    | ~ n0(d,v)
    | p1(v,v,u) ),
    file('SYN264-1.p',unknown),
    [] ).

cnf(110,axiom,
    ( ~ l0(u)
    | ~ p1(v,w,x)
    | ~ s0(b)
    | p1(x,v,x) ),
    file('SYN264-1.p',unknown),
    [] ).

cnf(407,plain,
    ( ~ l0(u)
    | ~ p1(v,w,x)
    | p1(x,v,x) ),
    inference(mrr,[status(thm)],[110,6]),
    [iquote('0:MRR:110.2,6.0')] ).

cnf(420,plain,
    ( ~ l0(u)
    | ~ p1(c,v,e) ),
    inference(res,[status(thm),theory(equality)],[407,1]),
    [iquote('0:Res:407.2,1.0')] ).

cnf(460,plain,
    k1(e),
    inference(res,[status(thm),theory(equality)],[4,40]),
    [iquote('0:Res:4.0,40.0')] ).

cnf(493,plain,
    ~ p1(c,u,e),
    inference(ems,[status(thm)],[420,21]),
    [iquote('0:EmS:420.0,21.0')] ).

cnf(694,plain,
    ( ~ k0(u)
    | p1(c,c,u) ),
    inference(res,[status(thm),theory(equality)],[27,102]),
    [iquote('0:Res:27.0,102.1')] ).

cnf(697,plain,
    ~ k0(e),
    inference(res,[status(thm),theory(equality)],[694,493]),
    [iquote('0:Res:694.1,493.0')] ).

cnf(699,plain,
    $false,
    inference(ssi,[status(thm)],[697,29,14,460]),
    [iquote('0:SSi:697.0,29.0,14.0,460.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SYN264-1 : TPTP v8.1.0. Released v1.1.0.
% 0.07/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n018.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jul 11 20:06:59 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.48  
% 0.18/0.48  SPASS V 3.9 
% 0.18/0.48  SPASS beiseite: Proof found.
% 0.18/0.48  % SZS status Theorem
% 0.18/0.48  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.18/0.48  SPASS derived 243 clauses, backtracked 0 clauses, performed 0 splits and kept 472 clauses.
% 0.18/0.48  SPASS allocated 76199 KBytes.
% 0.18/0.48  SPASS spent	0:00:00.13 on the problem.
% 0.18/0.48  		0:00:00.04 for the input.
% 0.18/0.48  		0:00:00.00 for the FLOTTER CNF translation.
% 0.18/0.48  		0:00:00.00 for inferences.
% 0.18/0.48  		0:00:00.00 for the backtracking.
% 0.18/0.48  		0:00:00.04 for the reduction.
% 0.18/0.48  
% 0.18/0.48  
% 0.18/0.48  Here is a proof with depth 3, length 17 :
% 0.18/0.48  % SZS output start Refutation
% See solution above
% 0.18/0.48  Formulae used in the proof : prove_this axiom_3 axiom_5 axiom_13 axiom_20 axiom_26 axiom_28 rule_001 rule_063 rule_071
% 0.18/0.48  
%------------------------------------------------------------------------------