TSTP Solution File: SYN184-1 by Twee---2.4.2
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% File : Twee---2.4.2
% Problem : SYN184-1 : TPTP v8.1.2. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n013.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 03:33:30 EDT 2023
% Result : Unsatisfiable 11.24s 1.87s
% Output : Proof 11.24s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SYN184-1 : TPTP v8.1.2. Released v1.1.0.
% 0.00/0.14 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.15/0.36 % Computer : n013.cluster.edu
% 0.15/0.36 % Model : x86_64 x86_64
% 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36 % Memory : 8042.1875MB
% 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36 % CPULimit : 300
% 0.15/0.36 % WCLimit : 300
% 0.15/0.36 % DateTime : Sat Aug 26 20:26:32 EDT 2023
% 0.15/0.36 % CPUTime :
% 11.24/1.87 Command-line arguments: --no-flatten-goal
% 11.24/1.87
% 11.24/1.87 % SZS status Unsatisfiable
% 11.24/1.87
% 11.24/1.87 % SZS output start Proof
% 11.24/1.87 Take the following subset of the input axioms:
% 11.24/1.87 fof(axiom_9, axiom, r0(b)).
% 11.24/1.87 fof(prove_this, negated_conjecture, ~r0(b)).
% 11.24/1.87
% 11.24/1.87 Now clausify the problem and encode Horn clauses using encoding 3 of
% 11.24/1.87 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 11.24/1.87 We repeatedly replace C & s=t => u=v by the two clauses:
% 11.24/1.87 fresh(y, y, x1...xn) = u
% 11.24/1.87 C => fresh(s, t, x1...xn) = v
% 11.24/1.87 where fresh is a fresh function symbol and x1..xn are the free
% 11.24/1.87 variables of u and v.
% 11.24/1.87 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 11.24/1.87 input problem has no model of domain size 1).
% 11.24/1.87
% 11.24/1.87 The encoding turns the above axioms into the following unit equations and goals:
% 11.24/1.87
% 11.24/1.87 Axiom 1 (axiom_9): r0(b) = true.
% 11.24/1.87
% 11.24/1.87 Goal 1 (prove_this): r0(b) = true.
% 11.24/1.87 Proof:
% 11.24/1.87 r0(b)
% 11.24/1.87 = { by axiom 1 (axiom_9) }
% 11.24/1.87 true
% 11.24/1.87 % SZS output end Proof
% 11.24/1.87
% 11.24/1.87 RESULT: Unsatisfiable (the axioms are contradictory).
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