TSTP Solution File: SYN170-10 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : SYN170-10 : TPTP v8.1.2. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 03:33:27 EDT 2023

% Result   : Unsatisfiable 0.21s 0.82s
% Output   : Proof 3.11s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : SYN170-10 : TPTP v8.1.2. Released v7.5.0.
% 0.00/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.35  % Computer : n018.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 300
% 0.13/0.35  % DateTime : Sat Aug 26 18:40:45 EDT 2023
% 0.13/0.35  % CPUTime  : 
% 0.21/0.82  Command-line arguments: --no-flatten-goal
% 0.21/0.82  
% 0.21/0.82  % SZS status Unsatisfiable
% 0.21/0.82  
% 0.21/0.82  % SZS output start Proof
% 0.21/0.82  Axiom 1 (axiom_19): m0(X, d, Y) = true.
% 0.21/0.82  Axiom 2 (ifeq_axiom): ifeq(X, X, Y, Z) = Y.
% 0.21/0.82  Axiom 3 (rule_194): ifeq(k2(X, Y), true, k3(Y, Y, X), true) = true.
% 0.21/0.82  Axiom 4 (rule_129): ifeq(q1(X, Y, Y), true, k2(Y, Y), true) = true.
% 0.21/0.82  Axiom 5 (rule_287): ifeq(k3(X, X, Y), true, p4(X, Y, X), true) = true.
% 0.21/0.82  Axiom 6 (rule_107): ifeq(m0(e, d, X), true, ifeq(m0(X, d, X), true, q1(e, X, X), true), true) = true.
% 0.21/0.82  
% 0.21/0.82  Goal 1 (prove_this): p4(X, c, Y) = true.
% 0.21/0.82  The goal is true when:
% 0.21/0.82    X = c
% 0.21/0.82    Y = c
% 0.21/0.82  
% 0.21/0.82  Proof:
% 0.21/0.82    p4(c, c, c)
% 0.21/0.82  = { by axiom 2 (ifeq_axiom) R->L }
% 0.21/0.82    ifeq(true, true, p4(c, c, c), true)
% 0.21/0.82  = { by axiom 3 (rule_194) R->L }
% 0.21/0.82    ifeq(ifeq(k2(c, c), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 0.21/0.82  = { by axiom 2 (ifeq_axiom) R->L }
% 0.21/0.82    ifeq(ifeq(ifeq(true, true, k2(c, c), true), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 0.21/0.82  = { by axiom 6 (rule_107) R->L }
% 0.21/0.82    ifeq(ifeq(ifeq(ifeq(m0(e, d, c), true, ifeq(m0(c, d, c), true, q1(e, c, c), true), true), true, k2(c, c), true), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 0.21/0.82  = { by axiom 1 (axiom_19) }
% 0.21/0.82    ifeq(ifeq(ifeq(ifeq(true, true, ifeq(m0(c, d, c), true, q1(e, c, c), true), true), true, k2(c, c), true), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 0.21/0.82  = { by axiom 2 (ifeq_axiom) }
% 0.21/0.82    ifeq(ifeq(ifeq(ifeq(m0(c, d, c), true, q1(e, c, c), true), true, k2(c, c), true), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 3.11/0.82  = { by axiom 1 (axiom_19) }
% 3.11/0.82    ifeq(ifeq(ifeq(ifeq(true, true, q1(e, c, c), true), true, k2(c, c), true), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 3.11/0.82  = { by axiom 2 (ifeq_axiom) }
% 3.11/0.82    ifeq(ifeq(ifeq(q1(e, c, c), true, k2(c, c), true), true, k3(c, c, c), true), true, p4(c, c, c), true)
% 3.11/0.82  = { by axiom 4 (rule_129) }
% 3.11/0.82    ifeq(ifeq(true, true, k3(c, c, c), true), true, p4(c, c, c), true)
% 3.11/0.82  = { by axiom 2 (ifeq_axiom) }
% 3.11/0.82    ifeq(k3(c, c, c), true, p4(c, c, c), true)
% 3.11/0.82  = { by axiom 5 (rule_287) }
% 3.11/0.82    true
% 3.11/0.82  % SZS output end Proof
% 3.11/0.82  
% 3.11/0.82  RESULT: Unsatisfiable (the axioms are contradictory).
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