TSTP Solution File: SYN119-1 by Twee---2.4.2
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% File : Twee---2.4.2
% Problem : SYN119-1 : TPTP v8.1.2. Released v1.1.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n027.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 03:33:14 EDT 2023
% Result : Unsatisfiable 12.11s 1.92s
% Output : Proof 12.11s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN119-1 : TPTP v8.1.2. Released v1.1.0.
% 0.13/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.34 % Computer : n027.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Sat Aug 26 19:21:05 EDT 2023
% 0.14/0.35 % CPUTime :
% 12.11/1.92 Command-line arguments: --no-flatten-goal
% 12.11/1.92
% 12.11/1.92 % SZS status Unsatisfiable
% 12.11/1.92
% 12.11/1.92 % SZS output start Proof
% 12.11/1.92 Take the following subset of the input axioms:
% 12.11/1.92 fof(axiom_24, axiom, l0(c)).
% 12.11/1.92 fof(prove_this, negated_conjecture, ~l0(c)).
% 12.11/1.92
% 12.11/1.92 Now clausify the problem and encode Horn clauses using encoding 3 of
% 12.11/1.92 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 12.11/1.92 We repeatedly replace C & s=t => u=v by the two clauses:
% 12.11/1.92 fresh(y, y, x1...xn) = u
% 12.11/1.92 C => fresh(s, t, x1...xn) = v
% 12.11/1.92 where fresh is a fresh function symbol and x1..xn are the free
% 12.11/1.92 variables of u and v.
% 12.11/1.92 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 12.11/1.92 input problem has no model of domain size 1).
% 12.11/1.92
% 12.11/1.92 The encoding turns the above axioms into the following unit equations and goals:
% 12.11/1.92
% 12.11/1.92 Axiom 1 (axiom_24): l0(c) = true.
% 12.11/1.92
% 12.11/1.92 Goal 1 (prove_this): l0(c) = true.
% 12.11/1.92 Proof:
% 12.11/1.92 l0(c)
% 12.11/1.92 = { by axiom 1 (axiom_24) }
% 12.11/1.92 true
% 12.11/1.92 % SZS output end Proof
% 12.11/1.92
% 12.11/1.92 RESULT: Unsatisfiable (the axioms are contradictory).
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