TSTP Solution File: SYN084+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN084+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:18:29 EDT 2022
% Result : Theorem 0.19s 0.42s
% Output : Refutation 0.19s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : SYN084+1 : TPTP v8.1.0. Released v2.0.0.
% 0.06/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n011.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jul 11 12:48:57 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.19/0.42
% 0.19/0.42 SPASS V 3.9
% 0.19/0.42 SPASS beiseite: Proof found.
% 0.19/0.42 % SZS status Theorem
% 0.19/0.42 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.42 SPASS derived 14 clauses, backtracked 12 clauses, performed 2 splits and kept 37 clauses.
% 0.19/0.42 SPASS allocated 97600 KBytes.
% 0.19/0.42 SPASS spent 0:00:00.08 on the problem.
% 0.19/0.42 0:00:00.03 for the input.
% 0.19/0.42 0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.42 0:00:00.00 for inferences.
% 0.19/0.42 0:00:00.00 for the backtracking.
% 0.19/0.42 0:00:00.00 for the reduction.
% 0.19/0.42
% 0.19/0.42
% 0.19/0.42 Here is a proof with depth 2, length 38 :
% 0.19/0.42 % SZS output start Refutation
% 0.19/0.42 1[0:Inp] || -> SkC0 SkP0(u)*.
% 0.19/0.42 2[0:Inp] || -> big_p(a)* SkC0.
% 0.19/0.42 3[0:Inp] || -> big_p(a) SkP0(u)*.
% 0.19/0.42 4[0:Inp] || big_p(f(f(skc4)))* -> .
% 0.19/0.42 5[0:Inp] big_p(u) || -> SkP0(u)*.
% 0.19/0.42 6[0:Inp] || big_p(skc5) -> big_p(f(skc5))*.
% 0.19/0.42 7[0:Inp] || big_p(f(f(skc5)))* -> SkC0.
% 0.19/0.42 8[0:Inp] || SkC0 SkP0(skc3)* -> big_p(a).
% 0.19/0.42 9[0:Inp] || big_p(f(f(u)))* -> SkP0(u).
% 0.19/0.42 10[0:Inp] || SkC0 SkP0(skc3) -> big_p(f(skc4))*.
% 0.19/0.42 11[0:Inp] || SkC0 big_p(a) -> big_p(u) big_p(f(f(u)))*.
% 0.19/0.42 12[0:Inp] || big_p(f(u)) big_p(a) -> big_p(f(f(u)))* SkC0.
% 0.19/0.42 13[0:Inp] SkP0(u) || big_p(a) -> big_p(u) big_p(f(f(u)))*.
% 0.19/0.42 14[0:Inp] || big_p(f(u)) SkC0 big_p(a) -> big_p(f(f(u)))*.
% 0.19/0.42 15[0:MRR:8.0,8.1,2.1,3.1] || -> big_p(a)*.
% 0.19/0.42 16[0:MRR:11.1,15.0] || SkC0 -> big_p(u) big_p(f(f(u)))*.
% 0.19/0.42 17[0:MRR:13.1,15.0] SkP0(u) || -> big_p(u) big_p(f(f(u)))*.
% 0.19/0.42 18[0:MRR:12.1,15.0] || big_p(f(u)) -> big_p(f(f(u)))* SkC0.
% 0.19/0.42 19[0:MRR:14.1,14.2,18.2,15.0] || big_p(f(u)) -> big_p(f(f(u)))*.
% 0.19/0.42 31[1:Spt:1.1] || -> SkP0(u)*.
% 0.19/0.42 32[1:MRR:17.0,31.0] || -> big_p(u) big_p(f(f(u)))*.
% 0.19/0.42 33[1:MRR:10.1,31.0] || SkC0 -> big_p(f(skc4))*.
% 0.19/0.42 34[2:Spt:7.1] || -> SkC0*.
% 0.19/0.42 35[2:MRR:33.0,34.0] || -> big_p(f(skc4))*.
% 0.19/0.42 37[0:Res:19.1,4.0] || big_p(f(skc4))* -> .
% 0.19/0.42 38[2:MRR:37.0,35.0] || -> .
% 0.19/0.42 39[2:Spt:38.0,7.1,34.0] || SkC0* -> .
% 0.19/0.42 40[2:Spt:38.0,7.0] || big_p(f(f(skc5)))* -> .
% 0.19/0.42 41[2:Res:19.1,40.0] || big_p(f(skc5))* -> .
% 0.19/0.42 42[2:Res:32.1,40.0] || -> big_p(skc5)*.
% 0.19/0.42 43[2:MRR:6.0,42.0] || -> big_p(f(skc5))*.
% 0.19/0.42 44[2:MRR:41.0,43.0] || -> .
% 0.19/0.42 45[1:Spt:44.0,1.0] || -> SkC0*.
% 0.19/0.42 46[1:MRR:10.0,10.2,45.0,37.0] || SkP0(skc3)* -> .
% 0.19/0.42 47[1:MRR:16.0,45.0] || -> big_p(u) big_p(f(f(u)))*.
% 0.19/0.42 50[1:Res:47.1,9.0] || -> big_p(u) SkP0(u)*.
% 0.19/0.42 52[1:MRR:50.0,5.0] || -> SkP0(u)*.
% 0.19/0.42 53[1:UnC:52.0,46.0] || -> .
% 0.19/0.42 % SZS output end Refutation
% 0.19/0.42 Formulae used in the proof : pel62
% 0.19/0.42
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