TSTP Solution File: SYN081+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN081+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:10:31 EDT 2023

% Result   : Theorem 5.56s 5.73s
% Output   : Proof 5.56s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.11  % Problem    : SYN081+1 : TPTP v8.1.2. Released v2.0.0.
% 0.11/0.12  % Command    : duper %s
% 0.11/0.33  % Computer : n024.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit   : 300
% 0.11/0.33  % WCLimit    : 300
% 0.11/0.33  % DateTime   : Sat Aug 26 17:59:24 EDT 2023
% 0.11/0.33  % CPUTime    : 
% 5.56/5.73  SZS status Theorem for theBenchmark.p
% 5.56/5.73  SZS output start Proof for theBenchmark.p
% 5.56/5.73  Clause #0 (by assumption #[]): Eq (∀ (X : Iota), Iff (big_f X) (Not (big_f (f X)))) True
% 5.56/5.73  Clause #1 (by assumption #[]): Eq (Not (Exists fun X => And (big_f X) (Not (big_f (f X))))) True
% 5.56/5.73  Clause #2 (by clausification #[0]): ∀ (a : Iota), Eq (Iff (big_f a) (Not (big_f (f a)))) True
% 5.56/5.73  Clause #3 (by clausification #[2]): ∀ (a : Iota), Or (Eq (big_f a) True) (Eq (Not (big_f (f a))) False)
% 5.56/5.73  Clause #4 (by clausification #[2]): ∀ (a : Iota), Or (Eq (big_f a) False) (Eq (Not (big_f (f a))) True)
% 5.56/5.73  Clause #5 (by clausification #[3]): ∀ (a : Iota), Or (Eq (big_f a) True) (Eq (big_f (f a)) True)
% 5.56/5.73  Clause #6 (by clausification #[4]): ∀ (a : Iota), Or (Eq (big_f a) False) (Eq (big_f (f a)) False)
% 5.56/5.73  Clause #7 (by superposition #[6, 5]): ∀ (a : Iota), Or (Eq (big_f (f (f a))) False) (Or (Eq (big_f a) True) (Eq False True))
% 5.56/5.73  Clause #8 (by clausification #[7]): ∀ (a : Iota), Or (Eq (big_f (f (f a))) False) (Eq (big_f a) True)
% 5.56/5.73  Clause #10 (by clausification #[1]): Eq (Exists fun X => And (big_f X) (Not (big_f (f X)))) False
% 5.56/5.73  Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (And (big_f a) (Not (big_f (f a)))) False
% 5.56/5.73  Clause #12 (by clausification #[11]): ∀ (a : Iota), Or (Eq (big_f a) False) (Eq (Not (big_f (f a))) False)
% 5.56/5.73  Clause #13 (by clausification #[12]): ∀ (a : Iota), Or (Eq (big_f a) False) (Eq (big_f (f a)) True)
% 5.56/5.73  Clause #14 (by superposition #[13, 5]): ∀ (a : Iota), Or (Eq (big_f (f (f a))) True) (Or (Eq (big_f a) True) (Eq False True))
% 5.56/5.73  Clause #15 (by clausification #[14]): ∀ (a : Iota), Or (Eq (big_f (f (f a))) True) (Eq (big_f a) True)
% 5.56/5.73  Clause #16 (by superposition #[15, 8]): ∀ (a : Iota), Or (Eq (big_f a) True) (Or (Eq True False) (Eq (big_f a) True))
% 5.56/5.73  Clause #19 (by clausification #[16]): ∀ (a : Iota), Or (Eq (big_f a) True) (Eq (big_f a) True)
% 5.56/5.73  Clause #20 (by eliminate duplicate literals #[19]): ∀ (a : Iota), Eq (big_f a) True
% 5.56/5.73  Clause #22 (by backward demodulation #[20, 6]): ∀ (a : Iota), Or (Eq True False) (Eq (big_f (f a)) False)
% 5.56/5.73  Clause #27 (by clausification #[22]): ∀ (a : Iota), Eq (big_f (f a)) False
% 5.56/5.73  Clause #28 (by superposition #[27, 20]): Eq False True
% 5.56/5.73  Clause #29 (by clausification #[28]): False
% 5.56/5.73  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------