TSTP Solution File: SYN078+1 by ePrincess---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : ePrincess---1.0
% Problem  : SYN078+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : ePrincess-casc -timeout=%d %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 04:59:46 EDT 2022

% Result   : Theorem 2.16s 1.21s
% Output   : Proof 2.85s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SYN078+1 : TPTP v8.1.0. Released v2.0.0.
% 0.11/0.13  % Command  : ePrincess-casc -timeout=%d %s
% 0.13/0.34  % Computer : n015.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Mon Jul 11 12:24:09 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.55/0.60          ____       _                          
% 0.55/0.60    ___  / __ \_____(_)___  ________  __________
% 0.55/0.60   / _ \/ /_/ / ___/ / __ \/ ___/ _ \/ ___/ ___/
% 0.55/0.60  /  __/ ____/ /  / / / / / /__/  __(__  |__  ) 
% 0.55/0.60  \___/_/   /_/  /_/_/ /_/\___/\___/____/____/  
% 0.55/0.60  
% 0.55/0.60  A Theorem Prover for First-Order Logic
% 0.55/0.60  (ePrincess v.1.0)
% 0.55/0.60  
% 0.55/0.60  (c) Philipp Rümmer, 2009-2015
% 0.55/0.60  (c) Peter Backeman, 2014-2015
% 0.55/0.60  (contributions by Angelo Brillout, Peter Baumgartner)
% 0.55/0.60  Free software under GNU Lesser General Public License (LGPL).
% 0.55/0.60  Bug reports to peter@backeman.se
% 0.55/0.60  
% 0.55/0.60  For more information, visit http://user.uu.se/~petba168/breu/
% 0.55/0.60  
% 0.55/0.60  Loading /export/starexec/sandbox2/benchmark/theBenchmark.p ...
% 0.67/0.65  Prover 0: Options:  -triggersInConjecture -genTotalityAxioms -tightFunctionScopes -clausifier=simple -reverseFunctionalityPropagation +boolFunsAsPreds -triggerStrategy=allMaximal -resolutionMethod=nonUnifying +ignoreQuantifiers -generateTriggers=all
% 1.20/0.90  Prover 0: Preprocessing ...
% 1.29/0.98  Prover 0: Warning: ignoring some quantifiers
% 1.29/0.99  Prover 0: Constructing countermodel ...
% 1.68/1.11  Prover 0: gave up
% 1.68/1.11  Prover 1: Options:  +triggersInConjecture -genTotalityAxioms -tightFunctionScopes -clausifier=simple +reverseFunctionalityPropagation -boolFunsAsPreds -triggerStrategy=maximal -resolutionMethod=normal +ignoreQuantifiers -generateTriggers=all
% 1.68/1.12  Prover 1: Preprocessing ...
% 1.68/1.17  Prover 1: Constructing countermodel ...
% 2.16/1.21  Prover 1: proved (93ms)
% 2.16/1.21  
% 2.16/1.21  No countermodel exists, formula is valid
% 2.16/1.21  % SZS status Theorem for theBenchmark
% 2.16/1.21  
% 2.16/1.21  Generating proof ... found it (size 25)
% 2.46/1.38  
% 2.46/1.38  % SZS output start Proof for theBenchmark
% 2.46/1.38  Assumed formulas after preprocessing and simplification: 
% 2.46/1.38  | (0)  ? [v0] :  ? [v1] :  ? [v2] :  ? [v3] :  ? [v4] : ( ! [v5] :  ! [v6] :  ! [v7] : (v6 = v5 |  ~ (f(v7) = v6) |  ~ (f(v7) = v5)) &  ! [v5] :  ! [v6] :  ! [v7] : (v6 = v5 |  ~ (big_p(v7) = v6) |  ~ (big_p(v7) = v5)) & ((v4 = v0 & v3 = 0 &  ~ (v1 = 0) & f(v2) = v0 & big_p(v2) = 0 & big_p(v0) = v1 &  ! [v5] :  ! [v6] : ( ~ (f(v5) = v6) |  ? [v7] :  ? [v8] : (big_p(v6) = v8 & big_p(v5) = v7 & ( ~ (v7 = 0) | v8 = 0)))) | (v1 = 0 &  ~ (v3 = 0) & f(v0) = v2 & big_p(v2) = v3 & big_p(v0) = 0 &  ! [v5] :  ! [v6] :  ! [v7] : (v6 = 0 |  ~ (f(v7) = v5) |  ~ (big_p(v5) = v6) |  ? [v8] : ( ~ (v8 = 0) & big_p(v7) = v8)))))
% 2.61/1.42  | Instantiating (0) with all_0_0_0, all_0_1_1, all_0_2_2, all_0_3_3, all_0_4_4 yields:
% 2.61/1.42  | (1)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (f(v2) = v1) |  ~ (f(v2) = v0)) &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (big_p(v2) = v1) |  ~ (big_p(v2) = v0)) & ((all_0_0_0 = all_0_4_4 & all_0_1_1 = 0 &  ~ (all_0_3_3 = 0) & f(all_0_2_2) = all_0_4_4 & big_p(all_0_2_2) = 0 & big_p(all_0_4_4) = all_0_3_3 &  ! [v0] :  ! [v1] : ( ~ (f(v0) = v1) |  ? [v2] :  ? [v3] : (big_p(v1) = v3 & big_p(v0) = v2 & ( ~ (v2 = 0) | v3 = 0)))) | (all_0_3_3 = 0 &  ~ (all_0_1_1 = 0) & f(all_0_4_4) = all_0_2_2 & big_p(all_0_2_2) = all_0_1_1 & big_p(all_0_4_4) = 0 &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = 0 |  ~ (f(v2) = v0) |  ~ (big_p(v0) = v1) |  ? [v3] : ( ~ (v3 = 0) & big_p(v2) = v3))))
% 2.61/1.43  |
% 2.61/1.43  | Applying alpha-rule on (1) yields:
% 2.61/1.43  | (2)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (f(v2) = v1) |  ~ (f(v2) = v0))
% 2.61/1.43  | (3)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (big_p(v2) = v1) |  ~ (big_p(v2) = v0))
% 2.61/1.44  | (4) (all_0_0_0 = all_0_4_4 & all_0_1_1 = 0 &  ~ (all_0_3_3 = 0) & f(all_0_2_2) = all_0_4_4 & big_p(all_0_2_2) = 0 & big_p(all_0_4_4) = all_0_3_3 &  ! [v0] :  ! [v1] : ( ~ (f(v0) = v1) |  ? [v2] :  ? [v3] : (big_p(v1) = v3 & big_p(v0) = v2 & ( ~ (v2 = 0) | v3 = 0)))) | (all_0_3_3 = 0 &  ~ (all_0_1_1 = 0) & f(all_0_4_4) = all_0_2_2 & big_p(all_0_2_2) = all_0_1_1 & big_p(all_0_4_4) = 0 &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = 0 |  ~ (f(v2) = v0) |  ~ (big_p(v0) = v1) |  ? [v3] : ( ~ (v3 = 0) & big_p(v2) = v3)))
% 2.61/1.44  |
% 2.61/1.44  +-Applying beta-rule and splitting (4), into two cases.
% 2.61/1.44  |-Branch one:
% 2.61/1.44  | (5) all_0_0_0 = all_0_4_4 & all_0_1_1 = 0 &  ~ (all_0_3_3 = 0) & f(all_0_2_2) = all_0_4_4 & big_p(all_0_2_2) = 0 & big_p(all_0_4_4) = all_0_3_3 &  ! [v0] :  ! [v1] : ( ~ (f(v0) = v1) |  ? [v2] :  ? [v3] : (big_p(v1) = v3 & big_p(v0) = v2 & ( ~ (v2 = 0) | v3 = 0)))
% 2.61/1.44  |
% 2.61/1.44  	| Applying alpha-rule on (5) yields:
% 2.61/1.44  	| (6) all_0_1_1 = 0
% 2.61/1.44  	| (7) big_p(all_0_4_4) = all_0_3_3
% 2.61/1.44  	| (8) all_0_0_0 = all_0_4_4
% 2.61/1.45  	| (9)  ! [v0] :  ! [v1] : ( ~ (f(v0) = v1) |  ? [v2] :  ? [v3] : (big_p(v1) = v3 & big_p(v0) = v2 & ( ~ (v2 = 0) | v3 = 0)))
% 2.61/1.45  	| (10) big_p(all_0_2_2) = 0
% 2.61/1.45  	| (11) f(all_0_2_2) = all_0_4_4
% 2.61/1.45  	| (12)  ~ (all_0_3_3 = 0)
% 2.61/1.45  	|
% 2.61/1.45  	| Instantiating formula (9) with all_0_4_4, all_0_2_2 and discharging atoms f(all_0_2_2) = all_0_4_4, yields:
% 2.61/1.45  	| (13)  ? [v0] :  ? [v1] : (big_p(all_0_2_2) = v0 & big_p(all_0_4_4) = v1 & ( ~ (v0 = 0) | v1 = 0))
% 2.61/1.45  	|
% 2.61/1.45  	| Instantiating (13) with all_12_0_5, all_12_1_6 yields:
% 2.61/1.45  	| (14) big_p(all_0_2_2) = all_12_1_6 & big_p(all_0_4_4) = all_12_0_5 & ( ~ (all_12_1_6 = 0) | all_12_0_5 = 0)
% 2.61/1.46  	|
% 2.61/1.46  	| Applying alpha-rule on (14) yields:
% 2.61/1.46  	| (15) big_p(all_0_2_2) = all_12_1_6
% 2.61/1.46  	| (16) big_p(all_0_4_4) = all_12_0_5
% 2.61/1.46  	| (17)  ~ (all_12_1_6 = 0) | all_12_0_5 = 0
% 2.61/1.46  	|
% 2.61/1.46  	| Instantiating formula (3) with all_0_2_2, all_12_1_6, 0 and discharging atoms big_p(all_0_2_2) = all_12_1_6, big_p(all_0_2_2) = 0, yields:
% 2.61/1.46  	| (18) all_12_1_6 = 0
% 2.61/1.46  	|
% 2.61/1.46  	| Instantiating formula (3) with all_0_4_4, all_12_0_5, all_0_3_3 and discharging atoms big_p(all_0_4_4) = all_12_0_5, big_p(all_0_4_4) = all_0_3_3, yields:
% 2.61/1.46  	| (19) all_12_0_5 = all_0_3_3
% 2.61/1.46  	|
% 2.61/1.46  	+-Applying beta-rule and splitting (17), into two cases.
% 2.61/1.46  	|-Branch one:
% 2.61/1.46  	| (20)  ~ (all_12_1_6 = 0)
% 2.61/1.46  	|
% 2.61/1.46  		| Equations (18) can reduce 20 to:
% 2.61/1.46  		| (21) $false
% 2.61/1.46  		|
% 2.83/1.46  		|-The branch is then unsatisfiable
% 2.83/1.46  	|-Branch two:
% 2.83/1.46  	| (18) all_12_1_6 = 0
% 2.83/1.46  	| (23) all_12_0_5 = 0
% 2.83/1.46  	|
% 2.83/1.47  		| Combining equations (23,19) yields a new equation:
% 2.83/1.47  		| (24) all_0_3_3 = 0
% 2.83/1.47  		|
% 2.83/1.47  		| Equations (24) can reduce 12 to:
% 2.83/1.47  		| (21) $false
% 2.83/1.47  		|
% 2.83/1.47  		|-The branch is then unsatisfiable
% 2.83/1.47  |-Branch two:
% 2.83/1.47  | (26) all_0_3_3 = 0 &  ~ (all_0_1_1 = 0) & f(all_0_4_4) = all_0_2_2 & big_p(all_0_2_2) = all_0_1_1 & big_p(all_0_4_4) = 0 &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = 0 |  ~ (f(v2) = v0) |  ~ (big_p(v0) = v1) |  ? [v3] : ( ~ (v3 = 0) & big_p(v2) = v3))
% 2.83/1.47  |
% 2.83/1.47  	| Applying alpha-rule on (26) yields:
% 2.83/1.47  	| (27)  ~ (all_0_1_1 = 0)
% 2.83/1.47  	| (28)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = 0 |  ~ (f(v2) = v0) |  ~ (big_p(v0) = v1) |  ? [v3] : ( ~ (v3 = 0) & big_p(v2) = v3))
% 2.83/1.47  	| (29) big_p(all_0_2_2) = all_0_1_1
% 2.83/1.47  	| (30) f(all_0_4_4) = all_0_2_2
% 2.83/1.47  	| (24) all_0_3_3 = 0
% 2.83/1.47  	| (32) big_p(all_0_4_4) = 0
% 2.83/1.47  	|
% 2.83/1.47  	| Instantiating formula (28) with all_0_4_4, all_0_1_1, all_0_2_2 and discharging atoms f(all_0_4_4) = all_0_2_2, big_p(all_0_2_2) = all_0_1_1, yields:
% 2.83/1.47  	| (33) all_0_1_1 = 0 |  ? [v0] : ( ~ (v0 = 0) & big_p(all_0_4_4) = v0)
% 2.83/1.47  	|
% 2.83/1.47  	+-Applying beta-rule and splitting (33), into two cases.
% 2.83/1.47  	|-Branch one:
% 2.83/1.47  	| (6) all_0_1_1 = 0
% 2.83/1.47  	|
% 2.83/1.47  		| Equations (6) can reduce 27 to:
% 2.83/1.47  		| (21) $false
% 2.83/1.47  		|
% 2.83/1.47  		|-The branch is then unsatisfiable
% 2.83/1.47  	|-Branch two:
% 2.83/1.47  	| (27)  ~ (all_0_1_1 = 0)
% 2.83/1.47  	| (37)  ? [v0] : ( ~ (v0 = 0) & big_p(all_0_4_4) = v0)
% 2.83/1.47  	|
% 2.83/1.47  		| Instantiating (37) with all_18_0_7 yields:
% 2.83/1.47  		| (38)  ~ (all_18_0_7 = 0) & big_p(all_0_4_4) = all_18_0_7
% 2.83/1.47  		|
% 2.83/1.47  		| Applying alpha-rule on (38) yields:
% 2.83/1.47  		| (39)  ~ (all_18_0_7 = 0)
% 2.83/1.47  		| (40) big_p(all_0_4_4) = all_18_0_7
% 2.85/1.47  		|
% 2.85/1.47  		| Instantiating formula (3) with all_0_4_4, all_18_0_7, 0 and discharging atoms big_p(all_0_4_4) = all_18_0_7, big_p(all_0_4_4) = 0, yields:
% 2.85/1.47  		| (41) all_18_0_7 = 0
% 2.85/1.47  		|
% 2.85/1.47  		| Equations (41) can reduce 39 to:
% 2.85/1.47  		| (21) $false
% 2.85/1.47  		|
% 2.85/1.47  		|-The branch is then unsatisfiable
% 2.85/1.47  % SZS output end Proof for theBenchmark
% 2.85/1.47  
% 2.85/1.47  862ms
%------------------------------------------------------------------------------