TSTP Solution File: SYN078+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN078+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:23:31 EDT 2022

% Result   : Theorem 1.67s 1.86s
% Output   : Refutation 1.67s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   10
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   21 (   8 unt;   7 nHn;  20 RR)
%            Number of literals    :   40 (   9 equ;  13 neg)
%            Maximal clause size   :    5 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-1 aty)
%            Number of variables   :    7 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ big_p(A)
    | B != f(A)
    | big_p(B)
    | ~ big_p(C)
    | big_p(f(C)) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( big_p(dollar_c1)
    | ~ big_p(f(dollar_c3)) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( dollar_c2 = f(dollar_c1)
    | ~ big_p(f(dollar_c3)) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(4,plain,
    ( f(dollar_c1) = dollar_c2
    | ~ big_p(f(dollar_c3)) ),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[3])]),
    [iquote('copy,3,flip.1')] ).

cnf(5,axiom,
    ( ~ big_p(dollar_c2)
    | big_p(dollar_c3) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ big_p(dollar_c2)
    | ~ big_p(f(dollar_c3)) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(7,plain,
    ( ~ big_p(A)
    | B != f(A)
    | big_p(B)
    | big_p(f(A)) ),
    inference(factor,[status(thm)],[1]),
    [iquote('factor,1.1.4')] ).

cnf(9,plain,
    ( ~ big_p(A)
    | f(A) != f(A)
    | big_p(f(A)) ),
    inference(factor,[status(thm)],[7]),
    [iquote('factor,7.3.4')] ).

cnf(10,axiom,
    A = A,
    file('SYN078+1.p',unknown),
    [] ).

cnf(11,axiom,
    ( big_p(dollar_c1)
    | big_p(dollar_c3) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(12,axiom,
    ( dollar_c2 = f(dollar_c1)
    | big_p(dollar_c3) ),
    file('SYN078+1.p',unknown),
    [] ).

cnf(13,plain,
    ( f(dollar_c1) = dollar_c2
    | big_p(dollar_c3) ),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[12])]),
    [iquote('copy,12,flip.1')] ).

cnf(15,plain,
    ( big_p(dollar_c1)
    | big_p(f(dollar_c3)) ),
    inference(hyper,[status(thm)],[11,9,10]),
    [iquote('hyper,11,9,10')] ).

cnf(21,plain,
    big_p(dollar_c1),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[15,2])]),
    [iquote('hyper,15,2,factor_simp')] ).

cnf(22,plain,
    big_p(f(dollar_c1)),
    inference(hyper,[status(thm)],[21,9,10]),
    [iquote('hyper,21,9,10')] ).

cnf(26,plain,
    ( big_p(dollar_c2)
    | big_p(dollar_c3) ),
    inference(unit_del,[status(thm)],[inference(para_from,[status(thm),theory(equality)],[13,9]),21,10]),
    [iquote('para_from,13.1.1,9.3.1,unit_del,21,10')] ).

cnf(30,plain,
    big_p(dollar_c3),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[26,5])]),
    [iquote('hyper,26,5,factor_simp')] ).

cnf(32,plain,
    big_p(f(dollar_c3)),
    inference(hyper,[status(thm)],[30,9,10]),
    [iquote('hyper,30,9,10')] ).

cnf(35,plain,
    f(dollar_c1) = dollar_c2,
    inference(hyper,[status(thm)],[32,4]),
    [iquote('hyper,32,4')] ).

cnf(37,plain,
    big_p(dollar_c2),
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[22]),35]),
    [iquote('back_demod,22,demod,35')] ).

cnf(39,plain,
    $false,
    inference(hyper,[status(thm)],[37,6,32]),
    [iquote('hyper,37,6,32')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem  : SYN078+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n018.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 10:59:31 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.67/1.86  ----- Otter 3.3f, August 2004 -----
% 1.67/1.86  The process was started by sandbox2 on n018.cluster.edu,
% 1.67/1.86  Wed Jul 27 10:59:31 2022
% 1.67/1.86  The command was "./otter".  The process ID is 28527.
% 1.67/1.86  
% 1.67/1.86  set(prolog_style_variables).
% 1.67/1.86  set(auto).
% 1.67/1.86     dependent: set(auto1).
% 1.67/1.86     dependent: set(process_input).
% 1.67/1.86     dependent: clear(print_kept).
% 1.67/1.86     dependent: clear(print_new_demod).
% 1.67/1.86     dependent: clear(print_back_demod).
% 1.67/1.86     dependent: clear(print_back_sub).
% 1.67/1.86     dependent: set(control_memory).
% 1.67/1.86     dependent: assign(max_mem, 12000).
% 1.67/1.86     dependent: assign(pick_given_ratio, 4).
% 1.67/1.86     dependent: assign(stats_level, 1).
% 1.67/1.86     dependent: assign(max_seconds, 10800).
% 1.67/1.86  clear(print_given).
% 1.67/1.86  
% 1.67/1.86  formula_list(usable).
% 1.67/1.86  all A (A=A).
% 1.67/1.86  -((all X ((exists Y (big_p(Y)&X=f(Y)))->big_p(X)))<-> (all U (big_p(U)->big_p(f(U))))).
% 1.67/1.86  end_of_list.
% 1.67/1.86  
% 1.67/1.86  -------> usable clausifies to:
% 1.67/1.86  
% 1.67/1.86  list(usable).
% 1.67/1.86  0 [] A=A.
% 1.67/1.86  0 [] -big_p(Y)|X!=f(Y)|big_p(X)| -big_p(U)|big_p(f(U)).
% 1.67/1.86  0 [] big_p($c1)|big_p($c3).
% 1.67/1.86  0 [] big_p($c1)| -big_p(f($c3)).
% 1.67/1.86  0 [] $c2=f($c1)|big_p($c3).
% 1.67/1.86  0 [] $c2=f($c1)| -big_p(f($c3)).
% 1.67/1.86  0 [] -big_p($c2)|big_p($c3).
% 1.67/1.86  0 [] -big_p($c2)| -big_p(f($c3)).
% 1.67/1.86  end_of_list.
% 1.67/1.86  
% 1.67/1.86  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=5.
% 1.67/1.86  
% 1.67/1.86  This ia a non-Horn set with equality.  The strategy will be
% 1.67/1.86  Knuth-Bendix, ordered hyper_res, factoring, and unit
% 1.67/1.86  deletion, with positive clauses in sos and nonpositive
% 1.67/1.86  clauses in usable.
% 1.67/1.86  
% 1.67/1.86     dependent: set(knuth_bendix).
% 1.67/1.86     dependent: set(anl_eq).
% 1.67/1.86     dependent: set(para_from).
% 1.67/1.86     dependent: set(para_into).
% 1.67/1.86     dependent: clear(para_from_right).
% 1.67/1.86     dependent: clear(para_into_right).
% 1.67/1.86     dependent: set(para_from_vars).
% 1.67/1.86     dependent: set(eq_units_both_ways).
% 1.67/1.86     dependent: set(dynamic_demod_all).
% 1.67/1.86     dependent: set(dynamic_demod).
% 1.67/1.86     dependent: set(order_eq).
% 1.67/1.86     dependent: set(back_demod).
% 1.67/1.86     dependent: set(lrpo).
% 1.67/1.86     dependent: set(hyper_res).
% 1.67/1.86     dependent: set(unit_deletion).
% 1.67/1.86     dependent: set(factor).
% 1.67/1.86  
% 1.67/1.86  ------------> process usable:
% 1.67/1.86  ** KEPT (pick-wt=13): 1 [] -big_p(A)|B!=f(A)|big_p(B)| -big_p(C)|big_p(f(C)).
% 1.67/1.86  ** KEPT (pick-wt=5): 2 [] big_p($c1)| -big_p(f($c3)).
% 1.67/1.86  ** KEPT (pick-wt=7): 4 [copy,3,flip.1] f($c1)=$c2| -big_p(f($c3)).
% 1.67/1.86  ** KEPT (pick-wt=4): 5 [] -big_p($c2)|big_p($c3).
% 1.67/1.86  ** KEPT (pick-wt=5): 6 [] -big_p($c2)| -big_p(f($c3)).
% 1.67/1.86  
% 1.67/1.86  ------------> process sos:
% 1.67/1.86  ** KEPT (pick-wt=3): 10 [] A=A.
% 1.67/1.86  ** KEPT (pick-wt=4): 11 [] big_p($c1)|big_p($c3).
% 1.67/1.86  ** KEPT (pick-wt=6): 13 [copy,12,flip.1] f($c1)=$c2|big_p($c3).
% 1.67/1.86    Following clause subsumed by 10 during input processing: 0 [copy,10,flip.1] A=A.
% 1.67/1.86  
% 1.67/1.86  ======= end of input processing =======
% 1.67/1.86  
% 1.67/1.86  =========== start of search ===========
% 1.67/1.86  
% 1.67/1.86  -------- PROOF -------- 
% 1.67/1.86  
% 1.67/1.86  -----> EMPTY CLAUSE at   0.00 sec ----> 39 [hyper,37,6,32] $F.
% 1.67/1.86  
% 1.67/1.86  Length of proof is 12.  Level of proof is 9.
% 1.67/1.86  
% 1.67/1.86  ---------------- PROOF ----------------
% 1.67/1.86  % SZS status Theorem
% 1.67/1.86  % SZS output start Refutation
% See solution above
% 1.67/1.86  ------------ end of proof -------------
% 1.67/1.86  
% 1.67/1.86  
% 1.67/1.86  Search stopped by max_proofs option.
% 1.67/1.86  
% 1.67/1.86  
% 1.67/1.86  Search stopped by max_proofs option.
% 1.67/1.86  
% 1.67/1.86  ============ end of search ============
% 1.67/1.86  
% 1.67/1.86  -------------- statistics -------------
% 1.67/1.86  clauses given                 12
% 1.67/1.86  clauses generated            195
% 1.67/1.86  clauses kept                  35
% 1.67/1.86  clauses forward subsumed     171
% 1.67/1.86  clauses back subsumed         18
% 1.67/1.86  Kbytes malloced              976
% 1.67/1.86  
% 1.67/1.86  ----------- times (seconds) -----------
% 1.67/1.86  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.86  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.86  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.67/1.86  
% 1.67/1.86  That finishes the proof of the theorem.
% 1.67/1.86  
% 1.67/1.86  Process 28527 finished Wed Jul 27 10:59:33 2022
% 1.67/1.86  Otter interrupted
% 1.67/1.86  PROOF FOUND
%------------------------------------------------------------------------------