TSTP Solution File: SYN063+1 by SPASS---3.9
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- Process Solution
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% File : SPASS---3.9
% Problem : SYN063+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n012.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:17:49 EDT 2022
% Result : Theorem 0.18s 0.44s
% Output : Refutation 0.18s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : SYN063+1 : TPTP v8.1.0. Released v2.0.0.
% 0.06/0.13 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n012.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Tue Jul 12 03:16:12 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.44
% 0.18/0.44 SPASS V 3.9
% 0.18/0.44 SPASS beiseite: Proof found.
% 0.18/0.44 % SZS status Theorem
% 0.18/0.44 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.18/0.44 SPASS derived 8 clauses, backtracked 20 clauses, performed 2 splits and kept 34 clauses.
% 0.18/0.44 SPASS allocated 97574 KBytes.
% 0.18/0.44 SPASS spent 0:00:00.09 on the problem.
% 0.18/0.44 0:00:00.04 for the input.
% 0.18/0.44 0:00:00.03 for the FLOTTER CNF translation.
% 0.18/0.44 0:00:00.00 for inferences.
% 0.18/0.44 0:00:00.00 for the backtracking.
% 0.18/0.44 0:00:00.00 for the reduction.
% 0.18/0.44
% 0.18/0.44
% 0.18/0.44 Here is a proof with depth 1, length 33 :
% 0.18/0.44 % SZS output start Refutation
% 0.18/0.44 1[0:Inp] || -> SkC0 SkP0(u)*.
% 0.18/0.44 2[0:Inp] || -> big_p(a)* SkC0.
% 0.18/0.44 3[0:Inp] || big_p(c)* -> SkC0.
% 0.18/0.44 4[0:Inp] || -> big_p(a) SkP0(u)*.
% 0.18/0.44 6[0:Inp] || big_p(c) -> SkP0(u)*.
% 0.18/0.44 7[0:Inp] || big_p(skc3) -> big_p(b)* SkC0.
% 0.18/0.44 8[0:Inp] || SkC0 SkP0(skc2)* -> big_p(a).
% 0.18/0.44 10[0:Inp] || SkC0 big_p(a)* -> big_p(c).
% 0.18/0.44 11[0:Inp] || big_p(c) SkC0 SkP0(skc2)* -> .
% 0.18/0.44 12[0:Inp] || big_p(a)* big_p(b) -> big_p(c) SkC0.
% 0.18/0.44 13[0:Inp] SkP0(u) || big_p(a)* -> big_p(u)* big_p(c).
% 0.18/0.44 14[0:MRR:8.0,8.1,2.1,4.1] || -> big_p(a)*.
% 0.18/0.44 15[0:MRR:10.1,14.0] || SkC0 -> big_p(c)*.
% 0.18/0.44 16[0:MRR:11.0,15.1] || SkC0 SkP0(skc2)* -> .
% 0.18/0.44 17[0:MRR:12.0,12.2,14.0,3.0] || big_p(b)* -> SkC0.
% 0.18/0.44 18[0:MRR:7.1,17.0] || big_p(skc3)* -> SkC0.
% 0.18/0.44 19[0:MRR:13.1,14.0] SkP0(u) || -> big_p(u)* big_p(c)*.
% 0.18/0.44 27[1:Spt:19.0,19.1] SkP0(u) || -> big_p(u)*.
% 0.18/0.44 28[2:Spt:1.0] || -> SkC0*.
% 0.18/0.44 29[2:MRR:15.0,28.0] || -> big_p(c)*.
% 0.18/0.44 30[2:MRR:16.0,28.0] || SkP0(skc2)* -> .
% 0.18/0.44 31[2:MRR:6.0,29.0] || -> SkP0(u)*.
% 0.18/0.44 33[2:MRR:30.0,31.0] || -> .
% 0.18/0.44 34[2:Spt:33.0,1.0,28.0] || SkC0* -> .
% 0.18/0.44 35[2:Spt:33.0,1.1] || -> SkP0(u)*.
% 0.18/0.44 38[2:MRR:18.1,34.0] || big_p(skc3)* -> .
% 0.18/0.44 39[2:MRR:27.0,35.0] || -> big_p(u)*.
% 0.18/0.44 40[2:UnC:39.0,38.0] || -> .
% 0.18/0.44 41[1:Spt:40.0,19.2] || -> big_p(c)*.
% 0.18/0.44 42[1:MRR:3.0,41.0] || -> SkC0*.
% 0.18/0.44 43[1:MRR:16.0,42.0] || SkP0(skc2)* -> .
% 0.18/0.44 44[1:MRR:6.0,41.0] || -> SkP0(u)*.
% 0.18/0.44 45[1:UnC:44.0,43.0] || -> .
% 0.18/0.44 % SZS output end Refutation
% 0.18/0.44 Formulae used in the proof : pel33
% 0.18/0.44
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