TSTP Solution File: SYN053+1 by Otter---3.3
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- Process Solution
%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SYN053+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:23:25 EDT 2022
% Result : Theorem 1.73s 1.93s
% Output : Refutation 1.73s
% Verified :
% SZS Type : Refutation
% Derivation depth : 2
% Number of leaves : 3
% Syntax : Number of clauses : 5 ( 3 unt; 1 nHn; 3 RR)
% Number of literals : 8 ( 0 equ; 3 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 2 prp; 0-1 aty)
% Number of functors : 2 ( 2 usr; 2 con; 0-0 aty)
% Number of variables : 3 ( 3 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
~ p,
file('SYN053+1.p',unknown),
[] ).
cnf(2,axiom,
( ~ big_f(dollar_c1)
| ~ big_f(dollar_c2) ),
file('SYN053+1.p',unknown),
[] ).
cnf(3,axiom,
( p
| big_f(A)
| big_f(B) ),
file('SYN053+1.p',unknown),
[] ).
cnf(4,plain,
big_f(A),
inference(factor_simp,[status(thm)],[inference(unit_del,[status(thm)],[inference(copy,[status(thm)],[3]),1])]),
[iquote('copy,3,unit_del,1,factor_simp')] ).
cnf(5,plain,
$false,
inference(hyper,[status(thm)],[4,2,4]),
[iquote('hyper,4,2,4')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : SYN053+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12 % Command : otter-tptp-script %s
% 0.12/0.34 % Computer : n007.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 300
% 0.12/0.34 % DateTime : Wed Jul 27 10:41:46 EDT 2022
% 0.12/0.34 % CPUTime :
% 1.73/1.93 ----- Otter 3.3f, August 2004 -----
% 1.73/1.93 The process was started by sandbox2 on n007.cluster.edu,
% 1.73/1.93 Wed Jul 27 10:41:46 2022
% 1.73/1.93 The command was "./otter". The process ID is 20259.
% 1.73/1.93
% 1.73/1.93 set(prolog_style_variables).
% 1.73/1.93 set(auto).
% 1.73/1.93 dependent: set(auto1).
% 1.73/1.93 dependent: set(process_input).
% 1.73/1.93 dependent: clear(print_kept).
% 1.73/1.93 dependent: clear(print_new_demod).
% 1.73/1.93 dependent: clear(print_back_demod).
% 1.73/1.93 dependent: clear(print_back_sub).
% 1.73/1.93 dependent: set(control_memory).
% 1.73/1.93 dependent: assign(max_mem, 12000).
% 1.73/1.93 dependent: assign(pick_given_ratio, 4).
% 1.73/1.93 dependent: assign(stats_level, 1).
% 1.73/1.93 dependent: assign(max_seconds, 10800).
% 1.73/1.93 clear(print_given).
% 1.73/1.93
% 1.73/1.93 formula_list(usable).
% 1.73/1.93 -((all X (p|big_f(X)))<->p| (all X1 big_f(X1))).
% 1.73/1.93 end_of_list.
% 1.73/1.93
% 1.73/1.93 -------> usable clausifies to:
% 1.73/1.93
% 1.73/1.93 list(usable).
% 1.73/1.93 0 [] p|big_f(X)|big_f(X1).
% 1.73/1.93 0 [] -p.
% 1.73/1.93 0 [] -big_f($c1)| -big_f($c2).
% 1.73/1.93 end_of_list.
% 1.73/1.93
% 1.73/1.93 SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=3.
% 1.73/1.93
% 1.73/1.93 This is a non-Horn set without equality. The strategy will
% 1.73/1.93 be ordered hyper_res, unit deletion, and factoring, with
% 1.73/1.93 satellites in sos and with nuclei in usable.
% 1.73/1.93
% 1.73/1.93 dependent: set(hyper_res).
% 1.73/1.93 dependent: set(factor).
% 1.73/1.93 dependent: set(unit_deletion).
% 1.73/1.93
% 1.73/1.93 ------------> process usable:
% 1.73/1.93 ** KEPT (pick-wt=1): 1 [] -p.
% 1.73/1.93 ** KEPT (pick-wt=4): 2 [] -big_f($c1)| -big_f($c2).
% 1.73/1.93
% 1.73/1.93 ------------> process sos:
% 1.73/1.93 ** KEPT (pick-wt=2): 4 [copy,3,unit_del,1,factor_simp] big_f(A).
% 1.73/1.93
% 1.73/1.93 ======= end of input processing =======
% 1.73/1.93
% 1.73/1.93 =========== start of search ===========
% 1.73/1.93
% 1.73/1.93 -------- PROOF --------
% 1.73/1.93
% 1.73/1.93 -----> EMPTY CLAUSE at 0.00 sec ----> 5 [hyper,4,2,4] $F.
% 1.73/1.93
% 1.73/1.93 Length of proof is 1. Level of proof is 1.
% 1.73/1.93
% 1.73/1.93 ---------------- PROOF ----------------
% 1.73/1.93 % SZS status Theorem
% 1.73/1.93 % SZS output start Refutation
% See solution above
% 1.73/1.93 ------------ end of proof -------------
% 1.73/1.93
% 1.73/1.93
% 1.73/1.93 Search stopped by max_proofs option.
% 1.73/1.93
% 1.73/1.93
% 1.73/1.93 Search stopped by max_proofs option.
% 1.73/1.93
% 1.73/1.93 ============ end of search ============
% 1.73/1.93
% 1.73/1.93 -------------- statistics -------------
% 1.73/1.93 clauses given 1
% 1.73/1.93 clauses generated 1
% 1.73/1.93 clauses kept 3
% 1.73/1.93 clauses forward subsumed 0
% 1.73/1.93 clauses back subsumed 0
% 1.73/1.93 Kbytes malloced 976
% 1.73/1.93
% 1.73/1.93 ----------- times (seconds) -----------
% 1.73/1.93 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.73/1.93 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.73/1.93 wall-clock time 1 (0 hr, 0 min, 1 sec)
% 1.73/1.93
% 1.73/1.93 That finishes the proof of the theorem.
% 1.73/1.93
% 1.73/1.93 Process 20259 finished Wed Jul 27 10:41:47 2022
% 1.73/1.93 Otter interrupted
% 1.73/1.93 PROOF FOUND
%------------------------------------------------------------------------------