TSTP Solution File: SYN052+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYN052+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n006.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:10:19 EDT 2023

% Result   : Theorem 3.38s 3.60s
% Output   : Proof 3.38s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : SYN052+1 : TPTP v8.1.2. Released v2.0.0.
% 0.07/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n006.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Sat Aug 26 17:41:52 EDT 2023
% 0.14/0.34  % CPUTime    : 
% 3.38/3.60  SZS status Theorem for theBenchmark.p
% 3.38/3.60  SZS output start Proof for theBenchmark.p
% 3.38/3.60  Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), Iff p (big_f X)) → Iff p (∀ (X1 : Iota), big_f X1))) True
% 3.38/3.60  Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), Iff p (big_f X)) → Iff p (∀ (X1 : Iota), big_f X1)) False
% 3.38/3.60  Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), Iff p (big_f X)) True
% 3.38/3.60  Clause #3 (by clausification #[1]): Eq (Iff p (∀ (X1 : Iota), big_f X1)) False
% 3.38/3.60  Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (Iff p (big_f a)) True
% 3.38/3.60  Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq p True) (Eq (big_f a) False)
% 3.38/3.60  Clause #6 (by clausification #[4]): ∀ (a : Iota), Or (Eq p False) (Eq (big_f a) True)
% 3.38/3.60  Clause #7 (by clausification #[3]): Or (Eq p False) (Eq (∀ (X1 : Iota), big_f X1) False)
% 3.38/3.60  Clause #8 (by clausification #[3]): Or (Eq p True) (Eq (∀ (X1 : Iota), big_f X1) True)
% 3.38/3.60  Clause #9 (by clausification #[7]): ∀ (a : Iota), Or (Eq p False) (Eq (Not (big_f (skS.0 0 a))) True)
% 3.38/3.60  Clause #10 (by clausification #[9]): ∀ (a : Iota), Or (Eq p False) (Eq (big_f (skS.0 0 a)) False)
% 3.38/3.60  Clause #11 (by clausification #[8]): ∀ (a : Iota), Or (Eq p True) (Eq (big_f a) True)
% 3.38/3.60  Clause #12 (by superposition #[11, 5]): Or (Eq p True) (Or (Eq p True) (Eq True False))
% 3.38/3.60  Clause #13 (by clausification #[12]): Or (Eq p True) (Eq p True)
% 3.38/3.60  Clause #14 (by eliminate duplicate literals #[13]): Eq p True
% 3.38/3.60  Clause #16 (by backward demodulation #[14, 6]): ∀ (a : Iota), Or (Eq True False) (Eq (big_f a) True)
% 3.38/3.60  Clause #17 (by backward demodulation #[14, 10]): ∀ (a : Iota), Or (Eq True False) (Eq (big_f (skS.0 0 a)) False)
% 3.38/3.60  Clause #19 (by clausification #[16]): ∀ (a : Iota), Eq (big_f a) True
% 3.38/3.60  Clause #20 (by clausification #[17]): ∀ (a : Iota), Eq (big_f (skS.0 0 a)) False
% 3.38/3.60  Clause #21 (by superposition #[20, 19]): Eq False True
% 3.38/3.60  Clause #22 (by clausification #[21]): False
% 3.38/3.60  SZS output end Proof for theBenchmark.p
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