TSTP Solution File: SYN045+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN045+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:17:32 EDT 2022

% Result   : Theorem 0.19s 0.42s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   17 (   5 unt;   8 nHn;  17 RR)
%            Number of literals    :   35 (   0 equ;  11 neg)
%            Maximal clause size   :    3 (   2 avg)
%            Maximal term depth    :    0 (   0 avg)
%            Number of predicates  :    5 (   4 usr;   5 prp; 0-0 aty)
%            Number of functors    :    0 (   0 usr;   0 con; --- aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( p
    | q
    | skC0 ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( p
    | r
    | skC0 ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ p
    | skC0 ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ p
    | ~ skC0 ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ skC0
    | q
    | p ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(6,axiom,
    ( ~ skC0
    | r
    | p ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ q
    | ~ r
    | skC0 ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(8,axiom,
    ( ~ r
    | ~ q
    | ~ skC0 ),
    file('SYN045+1.p',unknown),
    [] ).

cnf(9,plain,
    ( r
    | skC0 ),
    inference(mrr,[status(thm)],[2,3]),
    [iquote('0:MRR:2.0,3.0')] ).

cnf(10,plain,
    ( q
    | skC0 ),
    inference(mrr,[status(thm)],[1,3]),
    [iquote('0:MRR:1.0,3.0')] ).

cnf(11,plain,
    ( r
    | p ),
    inference(mrr,[status(thm)],[6,9]),
    [iquote('0:MRR:6.0,9.1')] ).

cnf(12,plain,
    ( q
    | p ),
    inference(mrr,[status(thm)],[5,10]),
    [iquote('0:MRR:5.0,10.1')] ).

cnf(13,plain,
    ~ p,
    inference(mrr,[status(thm)],[4,3]),
    [iquote('0:MRR:4.1,3.1')] ).

cnf(14,plain,
    r,
    inference(mrr,[status(thm)],[11,13]),
    [iquote('0:MRR:11.1,13.0')] ).

cnf(15,plain,
    q,
    inference(mrr,[status(thm)],[12,13]),
    [iquote('0:MRR:12.1,13.0')] ).

cnf(16,plain,
    skC0,
    inference(mrr,[status(thm)],[7,15,14]),
    [iquote('0:MRR:7.0,7.1,15.0,14.0')] ).

cnf(17,plain,
    $false,
    inference(mrr,[status(thm)],[8,14,15,16]),
    [iquote('0:MRR:8.0,8.1,8.2,14.0,15.0,16.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYN045+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n017.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jul 11 19:47:34 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.19/0.42  
% 0.19/0.42  SPASS V 3.9 
% 0.19/0.42  SPASS beiseite: Proof found.
% 0.19/0.42  % SZS status Theorem
% 0.19/0.42  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.19/0.42  SPASS derived 2 clauses, backtracked 0 clauses, performed 0 splits and kept 10 clauses.
% 0.19/0.42  SPASS allocated 85056 KBytes.
% 0.19/0.42  SPASS spent	0:00:00.08 on the problem.
% 0.19/0.42  		0:00:00.03 for the input.
% 0.19/0.42  		0:00:00.02 for the FLOTTER CNF translation.
% 0.19/0.42  		0:00:00.00 for inferences.
% 0.19/0.42  		0:00:00.00 for the backtracking.
% 0.19/0.42  		0:00:00.00 for the reduction.
% 0.19/0.42  
% 0.19/0.42  
% 0.19/0.42  Here is a proof with depth 0, length 17 :
% 0.19/0.42  % SZS output start Refutation
% See solution above
% 0.19/0.42  Formulae used in the proof : pel13
% 0.19/0.42  
%------------------------------------------------------------------------------