TSTP Solution File: SYN044+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : SYN044+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 06:07:28 EDT 2022
% Result : Theorem 0.19s 0.36s
% Output : CNFRefutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 7
% Number of leaves : 4
% Syntax : Number of formulae : 19 ( 4 unt; 0 def)
% Number of atoms : 42 ( 0 equ)
% Maximal formula atoms : 4 ( 2 avg)
% Number of connectives : 37 ( 14 ~; 15 |; 3 &)
% ( 2 <=>; 3 =>; 0 <=; 0 <~>)
% Maximal formula depth : 4 ( 3 avg)
% Maximal term depth : 0 ( 0 avg)
% Number of predicates : 4 ( 3 usr; 4 prp; 0-0 aty)
% Number of functors : 0 ( 0 usr; 0 con; --- aty)
% Number of variables : 0 ( 0 sgn 0 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(pel10,conjecture,
( p
<=> q ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',pel10) ).
fof(pel10_3,axiom,
( p
=> ( q
| r ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',pel10_3) ).
fof(pel10_1,axiom,
( q
=> r ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',pel10_1) ).
fof(pel10_2,axiom,
( r
=> ( p
& q ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',pel10_2) ).
fof(c_0_4,negated_conjecture,
~ ( p
<=> q ),
inference(assume_negation,[status(cth)],[pel10]) ).
fof(c_0_5,plain,
( ~ p
| q
| r ),
inference(fof_nnf,[status(thm)],[pel10_3]) ).
fof(c_0_6,negated_conjecture,
( ( ~ p
| ~ q )
& ( p
| q ) ),
inference(fof_nnf,[status(thm)],[c_0_4]) ).
fof(c_0_7,plain,
( ~ q
| r ),
inference(fof_nnf,[status(thm)],[pel10_1]) ).
fof(c_0_8,plain,
( ( p
| ~ r )
& ( q
| ~ r ) ),
inference(distribute,[status(thm)],[inference(fof_nnf,[status(thm)],[pel10_2])]) ).
cnf(c_0_9,plain,
( q
| r
| ~ p ),
inference(split_conjunct,[status(thm)],[c_0_5]) ).
cnf(c_0_10,negated_conjecture,
( p
| q ),
inference(split_conjunct,[status(thm)],[c_0_6]) ).
cnf(c_0_11,plain,
( r
| ~ q ),
inference(split_conjunct,[status(thm)],[c_0_7]) ).
cnf(c_0_12,plain,
( p
| ~ r ),
inference(split_conjunct,[status(thm)],[c_0_8]) ).
cnf(c_0_13,plain,
r,
inference(csr,[status(thm)],[inference(csr,[status(thm)],[c_0_9,c_0_10]),c_0_11]) ).
cnf(c_0_14,negated_conjecture,
( ~ p
| ~ q ),
inference(split_conjunct,[status(thm)],[c_0_6]) ).
cnf(c_0_15,plain,
p,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_12,c_0_13])]) ).
cnf(c_0_16,plain,
( q
| ~ r ),
inference(split_conjunct,[status(thm)],[c_0_8]) ).
cnf(c_0_17,negated_conjecture,
~ q,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_14,c_0_15])]) ).
cnf(c_0_18,plain,
$false,
inference(sr,[status(thm)],[inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_16,c_0_13])]),c_0_17]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : SYN044+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.33 % Computer : n018.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jul 11 23:37:44 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.19/0.36 # No SInE strategy applied
% 0.19/0.36 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.19/0.36 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.19/0.36 #
% 0.19/0.36 # Presaturation interreduction done
% 0.19/0.36
% 0.19/0.36 # Proof found!
% 0.19/0.36 # SZS status Theorem
% 0.19/0.36 # SZS output start CNFRefutation
% See solution above
% 0.19/0.36 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------