TSTP Solution File: SYN044+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN044+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:10:15 EDT 2023

% Result   : Theorem 3.43s 3.64s
% Output   : Proof 3.43s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.09  % Problem    : SYN044+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.10  % Command    : duper %s
% 0.10/0.29  % Computer : n032.cluster.edu
% 0.10/0.29  % Model    : x86_64 x86_64
% 0.10/0.29  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.29  % Memory   : 8042.1875MB
% 0.10/0.29  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.10/0.29  % CPULimit   : 300
% 0.10/0.29  % WCLimit    : 300
% 0.10/0.29  % DateTime   : Sat Aug 26 19:42:29 EDT 2023
% 0.10/0.29  % CPUTime    : 
% 3.43/3.64  SZS status Theorem for theBenchmark.p
% 3.43/3.64  SZS output start Proof for theBenchmark.p
% 3.43/3.64  Clause #0 (by assumption #[]): Eq (q → r) True
% 3.43/3.64  Clause #1 (by assumption #[]): Eq (r → And p q) True
% 3.43/3.64  Clause #2 (by assumption #[]): Eq (p → Or q r) True
% 3.43/3.64  Clause #3 (by assumption #[]): Eq (Not (Iff p q)) True
% 3.43/3.64  Clause #4 (by clausification #[0]): Or (Eq q False) (Eq r True)
% 3.43/3.64  Clause #5 (by clausification #[1]): Or (Eq r False) (Eq (And p q) True)
% 3.43/3.64  Clause #6 (by clausification #[5]): Or (Eq r False) (Eq q True)
% 3.43/3.64  Clause #7 (by clausification #[5]): Or (Eq r False) (Eq p True)
% 3.43/3.64  Clause #8 (by clausification #[3]): Eq (Iff p q) False
% 3.43/3.64  Clause #9 (by clausification #[8]): Or (Eq p False) (Eq q False)
% 3.43/3.64  Clause #10 (by clausification #[8]): Or (Eq p True) (Eq q True)
% 3.43/3.64  Clause #12 (by clausification #[2]): Or (Eq p False) (Eq (Or q r) True)
% 3.43/3.64  Clause #13 (by clausification #[12]): Or (Eq p False) (Or (Eq q True) (Eq r True))
% 3.43/3.64  Clause #14 (by superposition #[13, 10]): Or (Eq q True) (Or (Eq r True) (Or (Eq False True) (Eq q True)))
% 3.43/3.64  Clause #16 (by clausification #[14]): Or (Eq q True) (Or (Eq r True) (Eq q True))
% 3.43/3.64  Clause #17 (by eliminate duplicate literals #[16]): Or (Eq q True) (Eq r True)
% 3.43/3.64  Clause #18 (by superposition #[17, 6]): Or (Eq q True) (Or (Eq True False) (Eq q True))
% 3.43/3.64  Clause #21 (by clausification #[18]): Or (Eq q True) (Eq q True)
% 3.43/3.64  Clause #22 (by eliminate duplicate literals #[21]): Eq q True
% 3.43/3.64  Clause #23 (by backward demodulation #[22, 4]): Or (Eq True False) (Eq r True)
% 3.43/3.64  Clause #25 (by backward demodulation #[22, 9]): Or (Eq p False) (Eq True False)
% 3.43/3.64  Clause #28 (by clausification #[23]): Eq r True
% 3.43/3.64  Clause #29 (by backward demodulation #[28, 7]): Or (Eq True False) (Eq p True)
% 3.43/3.64  Clause #30 (by clausification #[29]): Eq p True
% 3.43/3.64  Clause #31 (by clausification #[25]): Eq p False
% 3.43/3.64  Clause #32 (by superposition #[31, 30]): Eq False True
% 3.43/3.64  Clause #33 (by clausification #[32]): False
% 3.43/3.64  SZS output end Proof for theBenchmark.p
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