TSTP Solution File: SYN040+1 by Metis---2.4

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Metis---2.4
% Problem  : SYN040+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : metis --show proof --show saturation %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 08:58:48 EDT 2022

% Result   : Theorem 0.13s 0.34s
% Output   : CNFRefutation 0.13s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    1
% Syntax   : Number of formulae    :   17 (   8 unt;   0 def)
%            Number of atoms       :   40 (   0 equ)
%            Maximal formula atoms :    4 (   2 avg)
%            Number of connectives :   43 (  20   ~;   4   |;   8   &)
%                                         (   1 <=>;  10  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   3 avg)
%            Maximal term depth    :    0 (   0 avg)
%            Number of predicates  :    3 (   2 usr;   3 prp; 0-0 aty)
%            Number of functors    :    0 (   0 usr;   0 con; --- aty)
%            Number of variables   :    0 (   0 sgn   0   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(pel1,conjecture,
    ( ( p
     => q )
  <=> ( ~ q
     => ~ p ) ) ).

fof(subgoal_0,plain,
    ( ( ( p
       => q )
      & ~ q )
   => ~ p ),
    inference(strip,[],[pel1]) ).

fof(subgoal_1,plain,
    ( ( ( ~ q
       => ~ p )
      & p )
   => q ),
    inference(strip,[],[pel1]) ).

fof(negate_0_0,plain,
    ~ ( ( ( p
         => q )
        & ~ q )
     => ~ p ),
    inference(negate,[],[subgoal_0]) ).

fof(normalize_0_0,plain,
    ( ~ q
    & p
    & ( ~ p
      | q ) ),
    inference(canonicalize,[],[negate_0_0]) ).

fof(normalize_0_1,plain,
    ( ~ p
    | q ),
    inference(conjunct,[],[normalize_0_0]) ).

fof(normalize_0_2,plain,
    p,
    inference(conjunct,[],[normalize_0_0]) ).

fof(normalize_0_3,plain,
    ~ q,
    inference(conjunct,[],[normalize_0_0]) ).

fof(normalize_0_4,plain,
    $false,
    inference(simplify,[],[normalize_0_1,normalize_0_2,normalize_0_3]) ).

cnf(refute_0_0,plain,
    $false,
    inference(canonicalize,[],[normalize_0_4]) ).

fof(negate_1_0,plain,
    ~ ( ( ( ~ q
         => ~ p )
        & p )
     => q ),
    inference(negate,[],[subgoal_1]) ).

fof(normalize_1_0,plain,
    ( ~ q
    & p
    & ( ~ p
      | q ) ),
    inference(canonicalize,[],[negate_1_0]) ).

fof(normalize_1_1,plain,
    ( ~ p
    | q ),
    inference(conjunct,[],[normalize_1_0]) ).

fof(normalize_1_2,plain,
    p,
    inference(conjunct,[],[normalize_1_0]) ).

fof(normalize_1_3,plain,
    ~ q,
    inference(conjunct,[],[normalize_1_0]) ).

fof(normalize_1_4,plain,
    $false,
    inference(simplify,[],[normalize_1_1,normalize_1_2,normalize_1_3]) ).

cnf(refute_1_0,plain,
    $false,
    inference(canonicalize,[],[normalize_1_4]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SYN040+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.13  % Command  : metis --show proof --show saturation %s
% 0.13/0.34  % Computer : n027.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Mon Jul 11 16:16:19 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.34  %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.13/0.34  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.13/0.34  
% 0.13/0.34  % SZS output start CNFRefutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
% 0.13/0.34  
%------------------------------------------------------------------------------