TSTP Solution File: SYN040+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN040+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:10:14 EDT 2023
% Result : Theorem 3.65s 3.84s
% Output : Proof 3.65s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SYN040+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.15 % Command : duper %s
% 0.13/0.36 % Computer : n029.cluster.edu
% 0.13/0.36 % Model : x86_64 x86_64
% 0.13/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.36 % Memory : 8042.1875MB
% 0.13/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.36 % CPULimit : 300
% 0.13/0.36 % WCLimit : 300
% 0.13/0.36 % DateTime : Sat Aug 26 18:10:25 EDT 2023
% 0.13/0.37 % CPUTime :
% 3.65/3.84 SZS status Theorem for theBenchmark.p
% 3.65/3.84 SZS output start Proof for theBenchmark.p
% 3.65/3.84 Clause #0 (by assumption #[]): Eq (Not (Iff (p → q) (Not q → Not p))) True
% 3.65/3.84 Clause #1 (by clausification #[0]): Eq (Iff (p → q) (Not q → Not p)) False
% 3.65/3.84 Clause #2 (by clausification #[1]): Or (Eq (p → q) False) (Eq (Not q → Not p) False)
% 3.65/3.84 Clause #3 (by clausification #[1]): Or (Eq (p → q) True) (Eq (Not q → Not p) True)
% 3.65/3.84 Clause #4 (by clausification #[2]): Or (Eq (Not q → Not p) False) (Eq p True)
% 3.65/3.84 Clause #5 (by clausification #[2]): Or (Eq (Not q → Not p) False) (Eq q False)
% 3.65/3.84 Clause #7 (by clausification #[4]): Or (Eq p True) (Eq (Not p) False)
% 3.65/3.84 Clause #9 (by clausification #[7]): Or (Eq p True) (Eq p True)
% 3.65/3.84 Clause #10 (by eliminate duplicate literals #[9]): Eq p True
% 3.65/3.84 Clause #11 (by clausification #[5]): Or (Eq q False) (Eq (Not q) True)
% 3.65/3.84 Clause #13 (by clausification #[11]): Or (Eq q False) (Eq q False)
% 3.65/3.84 Clause #14 (by eliminate duplicate literals #[13]): Eq q False
% 3.65/3.84 Clause #17 (by clausification #[3]): Or (Eq (Not q → Not p) True) (Or (Eq p False) (Eq q True))
% 3.65/3.84 Clause #18 (by clausification #[17]): Or (Eq p False) (Or (Eq q True) (Or (Eq (Not q) False) (Eq (Not p) True)))
% 3.65/3.84 Clause #19 (by clausification #[18]): Or (Eq p False) (Or (Eq q True) (Or (Eq (Not p) True) (Eq q True)))
% 3.65/3.84 Clause #20 (by clausification #[19]): Or (Eq p False) (Or (Eq q True) (Or (Eq q True) (Eq p False)))
% 3.65/3.84 Clause #21 (by eliminate duplicate literals #[20]): Or (Eq p False) (Eq q True)
% 3.65/3.84 Clause #22 (by forward demodulation #[21, 14]): Or (Eq p False) (Eq False True)
% 3.65/3.84 Clause #23 (by clausification #[22]): Eq p False
% 3.65/3.84 Clause #24 (by superposition #[23, 10]): Eq False True
% 3.65/3.84 Clause #25 (by clausification #[24]): False
% 3.65/3.84 SZS output end Proof for theBenchmark.p
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