TSTP Solution File: SYN009-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN009-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:23:18 EDT 2022

% Result   : Unsatisfiable 1.69s 1.89s
% Output   : Refutation 1.69s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    8 (   5 unt;   3 nHn;   8 RR)
%            Number of literals    :   20 (   0 equ;   9 neg)
%            Maximal clause size   :    6 (   2 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-3 aty)
%            Number of functors    :    1 (   1 usr;   1 con; 0-0 aty)
%            Number of variables   :   12 (   6 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ~ p(c,A,B),
    file('SYN009-1.p',unknown),
    [] ).

cnf(2,axiom,
    ~ q(A,c,B),
    file('SYN009-1.p',unknown),
    [] ).

cnf(3,axiom,
    ~ r(A,B,c),
    file('SYN009-1.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ s(A)
    | ~ s(B)
    | ~ s(C)
    | p(A,B,C)
    | q(A,B,C)
    | r(A,B,C) ),
    file('SYN009-1.p',unknown),
    [] ).

cnf(5,plain,
    ( ~ s(A)
    | ~ s(B)
    | p(A,A,B)
    | q(A,A,B)
    | r(A,A,B) ),
    inference(factor,[status(thm)],[4]),
    [iquote('factor,4.1.2')] ).

cnf(8,plain,
    ( ~ s(A)
    | p(A,A,A)
    | q(A,A,A)
    | r(A,A,A) ),
    inference(factor,[status(thm)],[5]),
    [iquote('factor,5.1.2')] ).

cnf(11,axiom,
    s(c),
    file('SYN009-1.p',unknown),
    [] ).

cnf(20,plain,
    $false,
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[11,8]),1,2,3]),
    [iquote('hyper,11,8,unit_del,1,2,3')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SYN009-1 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n009.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 11:15:06 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.69/1.89  ----- Otter 3.3f, August 2004 -----
% 1.69/1.89  The process was started by sandbox2 on n009.cluster.edu,
% 1.69/1.89  Wed Jul 27 11:15:06 2022
% 1.69/1.89  The command was "./otter".  The process ID is 28317.
% 1.69/1.89  
% 1.69/1.89  set(prolog_style_variables).
% 1.69/1.89  set(auto).
% 1.69/1.89     dependent: set(auto1).
% 1.69/1.89     dependent: set(process_input).
% 1.69/1.89     dependent: clear(print_kept).
% 1.69/1.89     dependent: clear(print_new_demod).
% 1.69/1.89     dependent: clear(print_back_demod).
% 1.69/1.89     dependent: clear(print_back_sub).
% 1.69/1.89     dependent: set(control_memory).
% 1.69/1.89     dependent: assign(max_mem, 12000).
% 1.69/1.89     dependent: assign(pick_given_ratio, 4).
% 1.69/1.89     dependent: assign(stats_level, 1).
% 1.69/1.89     dependent: assign(max_seconds, 10800).
% 1.69/1.89  clear(print_given).
% 1.69/1.89  
% 1.69/1.89  list(usable).
% 1.69/1.89  0 [] -p(c,X,Y).
% 1.69/1.89  0 [] -q(X,c,Y).
% 1.69/1.89  0 [] -r(X,Y,c).
% 1.69/1.89  0 [] s(a).
% 1.69/1.89  0 [] s(b).
% 1.69/1.89  0 [] s(c).
% 1.69/1.89  0 [] -s(X)| -s(Y)| -s(Z)|p(X,Y,Z)|q(X,Y,Z)|r(X,Y,Z).
% 1.69/1.89  end_of_list.
% 1.69/1.89  
% 1.69/1.89  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=6.
% 1.69/1.89  
% 1.69/1.89  This is a non-Horn set without equality.  The strategy will
% 1.69/1.89  be ordered hyper_res, unit deletion, and factoring, with
% 1.69/1.89  satellites in sos and with nuclei in usable.
% 1.69/1.89  
% 1.69/1.89     dependent: set(hyper_res).
% 1.69/1.89     dependent: set(factor).
% 1.69/1.89     dependent: set(unit_deletion).
% 1.69/1.89  
% 1.69/1.89  ------------> process usable:
% 1.69/1.89  ** KEPT (pick-wt=4): 1 [] -p(c,A,B).
% 1.69/1.89  ** KEPT (pick-wt=4): 2 [] -q(A,c,B).
% 1.69/1.89  ** KEPT (pick-wt=4): 3 [] -r(A,B,c).
% 1.69/1.89  ** KEPT (pick-wt=18): 4 [] -s(A)| -s(B)| -s(C)|p(A,B,C)|q(A,B,C)|r(A,B,C).
% 1.69/1.89  
% 1.69/1.89  ------------> process sos:
% 1.69/1.89  ** KEPT (pick-wt=2): 9 [] s(a).
% 1.69/1.89  ** KEPT (pick-wt=2): 10 [] s(b).
% 1.69/1.89  ** KEPT (pick-wt=2): 11 [] s(c).
% 1.69/1.89  
% 1.69/1.89  ======= end of input processing =======
% 1.69/1.89  
% 1.69/1.89  =========== start of search ===========
% 1.69/1.89  
% 1.69/1.89  -------- PROOF -------- 
% 1.69/1.89  
% 1.69/1.89  -----> EMPTY CLAUSE at   0.00 sec ----> 20 [hyper,11,8,unit_del,1,2,3] $F.
% 1.69/1.89  
% 1.69/1.89  Length of proof is 2.  Level of proof is 2.
% 1.69/1.89  
% 1.69/1.89  ---------------- PROOF ----------------
% 1.69/1.89  % SZS status Unsatisfiable
% 1.69/1.89  % SZS output start Refutation
% See solution above
% 1.69/1.89  ------------ end of proof -------------
% 1.69/1.89  
% 1.69/1.89  
% 1.69/1.89  Search stopped by max_proofs option.
% 1.69/1.89  
% 1.69/1.89  
% 1.69/1.89  Search stopped by max_proofs option.
% 1.69/1.89  
% 1.69/1.89  ============ end of search ============
% 1.69/1.89  
% 1.69/1.89  -------------- statistics -------------
% 1.69/1.89  clauses given                  3
% 1.69/1.89  clauses generated             42
% 1.69/1.89  clauses kept                  19
% 1.69/1.89  clauses forward subsumed      29
% 1.69/1.89  clauses back subsumed          0
% 1.69/1.89  Kbytes malloced              976
% 1.69/1.89  
% 1.69/1.89  ----------- times (seconds) -----------
% 1.69/1.89  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.69/1.89  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.69/1.89  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.69/1.89  
% 1.69/1.89  That finishes the proof of the theorem.
% 1.69/1.89  
% 1.69/1.89  Process 28317 finished Wed Jul 27 11:15:07 2022
% 1.69/1.89  Otter interrupted
% 1.69/1.89  PROOF FOUND
%------------------------------------------------------------------------------