TSTP Solution File: SYN003-1.006 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN003-1.006 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:17:07 EDT 2022
% Result : Unsatisfiable 0.20s 0.42s
% Output : Refutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 13
% Syntax : Number of clauses : 23 ( 13 unt; 0 nHn; 23 RR)
% Number of literals : 38 ( 0 equ; 20 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 0 ( 0 avg)
% Number of predicates : 13 ( 12 usr; 13 prp; 0-0 aty)
% Number of functors : 0 ( 0 usr; 0 con; --- aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(6,axiom,
( ~ p_1
| ~ r_1
| p_2 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(7,axiom,
( ~ p_2
| ~ r_2
| p_3 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(8,axiom,
( ~ p_3
| ~ r_3
| p_4 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(9,axiom,
( ~ p_4
| ~ r_4
| p_5 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(10,axiom,
( ~ p_5
| ~ r_5
| p_6 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(16,axiom,
( ~ r
| r_1 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(17,axiom,
( ~ r
| r_2 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(18,axiom,
( ~ r
| r_3 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(19,axiom,
( ~ r
| r_4 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(20,axiom,
( ~ r
| r_5 ),
file('SYN003-1.006.p',unknown),
[] ).
cnf(21,axiom,
p_1,
file('SYN003-1.006.p',unknown),
[] ).
cnf(22,axiom,
~ p_6,
file('SYN003-1.006.p',unknown),
[] ).
cnf(24,axiom,
r,
file('SYN003-1.006.p',unknown),
[] ).
cnf(25,plain,
r_5,
inference(mrr,[status(thm)],[20,24]),
[iquote('0:MRR:20.0,24.0')] ).
cnf(26,plain,
r_4,
inference(mrr,[status(thm)],[19,24]),
[iquote('0:MRR:19.0,24.0')] ).
cnf(27,plain,
r_3,
inference(mrr,[status(thm)],[18,24]),
[iquote('0:MRR:18.0,24.0')] ).
cnf(28,plain,
r_2,
inference(mrr,[status(thm)],[17,24]),
[iquote('0:MRR:17.0,24.0')] ).
cnf(29,plain,
r_1,
inference(mrr,[status(thm)],[16,24]),
[iquote('0:MRR:16.0,24.0')] ).
cnf(35,plain,
~ p_5,
inference(mrr,[status(thm)],[10,25,22]),
[iquote('0:MRR:10.1,10.2,25.0,22.0')] ).
cnf(36,plain,
~ p_4,
inference(mrr,[status(thm)],[9,26,35]),
[iquote('0:MRR:9.1,9.2,26.0,35.0')] ).
cnf(37,plain,
~ p_3,
inference(mrr,[status(thm)],[8,27,36]),
[iquote('0:MRR:8.1,8.2,27.0,36.0')] ).
cnf(38,plain,
~ p_2,
inference(mrr,[status(thm)],[7,28,37]),
[iquote('0:MRR:7.1,7.2,28.0,37.0')] ).
cnf(39,plain,
$false,
inference(mrr,[status(thm)],[6,21,29,38]),
[iquote('0:MRR:6.0,6.1,6.2,21.0,29.0,38.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : SYN003-1.006 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.13 % Command : run_spass %d %s
% 0.13/0.34 % Computer : n021.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Mon Jul 11 12:23:53 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.20/0.42
% 0.20/0.42 SPASS V 3.9
% 0.20/0.42 SPASS beiseite: Proof found.
% 0.20/0.42 % SZS status Theorem
% 0.20/0.42 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.20/0.42 SPASS derived 0 clauses, backtracked 0 clauses, performed 0 splits and kept 19 clauses.
% 0.20/0.42 SPASS allocated 63094 KBytes.
% 0.20/0.42 SPASS spent 0:00:00.06 on the problem.
% 0.20/0.42 0:00:00.04 for the input.
% 0.20/0.42 0:00:00.00 for the FLOTTER CNF translation.
% 0.20/0.42 0:00:00.00 for inferences.
% 0.20/0.42 0:00:00.00 for the backtracking.
% 0.20/0.42 0:00:00.00 for the reduction.
% 0.20/0.42
% 0.20/0.42
% 0.20/0.42 Here is a proof with depth 0, length 23 :
% 0.20/0.42 % SZS output start Refutation
% See solution above
% 0.20/0.42 Formulae used in the proof : prp_1 prp_2 prp_3 prp_4 prp_5 rr_1 rr_2 rr_3 rr_4 rr_5 base_1 base_2 base_4
% 0.20/0.42
%------------------------------------------------------------------------------