TSTP Solution File: SYN002-1.007.008 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN002-1.007.008 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:23:17 EDT 2022

% Result   : Unsatisfiable 1.60s 1.83s
% Output   : Refutation 1.60s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    7
%            Number of leaves      :    2
% Syntax   : Number of clauses     :    9 (   2 unt;   6 nHn;   2 RR)
%            Number of literals    :   16 (   0 equ;   2 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :   10 (   4 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   0 con; 1-1 aty)
%            Number of variables   :    8 (   1 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ p(A)
    | ~ p(f(f(f(f(f(f(f(f(A))))))))) ),
    file('SYN002-1.007.008.p',unknown),
    [] ).

cnf(2,axiom,
    ( p(A)
    | p(f(f(f(f(f(f(f(A)))))))) ),
    file('SYN002-1.007.008.p',unknown),
    [] ).

cnf(5,plain,
    ( p(f(f(f(f(f(f(f(A))))))))
    | p(f(A)) ),
    inference(hyper,[status(thm)],[2,1,2]),
    [iquote('hyper,2,1,2')] ).

cnf(8,plain,
    ( p(f(f(f(f(f(f(f(f(f(A))))))))))
    | p(A) ),
    inference(hyper,[status(thm)],[5,1,2]),
    [iquote('hyper,5,1,2')] ).

cnf(17,plain,
    ( p(f(f(f(f(f(f(A)))))))
    | p(A) ),
    inference(hyper,[status(thm)],[8,1,2]),
    [iquote('hyper,8,1,2')] ).

cnf(23,plain,
    ( p(A)
    | p(f(f(f(f(f(A)))))) ),
    inference(hyper,[status(thm)],[17,1,8]),
    [iquote('hyper,17,1,8')] ).

cnf(37,plain,
    ( p(A)
    | p(f(f(f(f(A))))) ),
    inference(hyper,[status(thm)],[23,1,8]),
    [iquote('hyper,23,1,8')] ).

cnf(41,plain,
    p(f(f(f(f(A))))),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[37,1,37])]),
    [iquote('hyper,37,1,37,factor_simp')] ).

cnf(43,plain,
    $false,
    inference(hyper,[status(thm)],[41,1,41]),
    [iquote('hyper,41,1,41')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem  : SYN002-1.007.008 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n010.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 11:06:54 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.60/1.83  ----- Otter 3.3f, August 2004 -----
% 1.60/1.83  The process was started by sandbox2 on n010.cluster.edu,
% 1.60/1.83  Wed Jul 27 11:06:54 2022
% 1.60/1.83  The command was "./otter".  The process ID is 24495.
% 1.60/1.83  
% 1.60/1.83  set(prolog_style_variables).
% 1.60/1.83  set(auto).
% 1.60/1.83     dependent: set(auto1).
% 1.60/1.83     dependent: set(process_input).
% 1.60/1.83     dependent: clear(print_kept).
% 1.60/1.83     dependent: clear(print_new_demod).
% 1.60/1.83     dependent: clear(print_back_demod).
% 1.60/1.83     dependent: clear(print_back_sub).
% 1.60/1.83     dependent: set(control_memory).
% 1.60/1.83     dependent: assign(max_mem, 12000).
% 1.60/1.83     dependent: assign(pick_given_ratio, 4).
% 1.60/1.83     dependent: assign(stats_level, 1).
% 1.60/1.83     dependent: assign(max_seconds, 10800).
% 1.60/1.83  clear(print_given).
% 1.60/1.83  
% 1.60/1.83  list(usable).
% 1.60/1.83  0 [] p(X)|p(f(f(f(f(f(f(f(X)))))))).
% 1.60/1.83  0 [] -p(X)| -p(f(f(f(f(f(f(f(f(X))))))))).
% 1.60/1.83  end_of_list.
% 1.60/1.83  
% 1.60/1.83  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=2.
% 1.60/1.83  
% 1.60/1.83  This is a non-Horn set without equality.  The strategy will
% 1.60/1.83  be ordered hyper_res, unit deletion, and factoring, with
% 1.60/1.83  satellites in sos and with nuclei in usable.
% 1.60/1.83  
% 1.60/1.83     dependent: set(hyper_res).
% 1.60/1.83     dependent: set(factor).
% 1.60/1.83     dependent: set(unit_deletion).
% 1.60/1.83  
% 1.60/1.83  ------------> process usable:
% 1.60/1.83  ** KEPT (pick-wt=12): 1 [] -p(A)| -p(f(f(f(f(f(f(f(f(A))))))))).
% 1.60/1.83  
% 1.60/1.83  ------------> process sos:
% 1.60/1.83  ** KEPT (pick-wt=11): 2 [] p(A)|p(f(f(f(f(f(f(f(A)))))))).
% 1.60/1.83  
% 1.60/1.83  ======= end of input processing =======
% 1.60/1.83  
% 1.60/1.83  =========== start of search ===========
% 1.60/1.83  
% 1.60/1.83  -------- PROOF -------- 
% 1.60/1.83  
% 1.60/1.83  -----> EMPTY CLAUSE at   0.01 sec ----> 43 [hyper,41,1,41] $F.
% 1.60/1.83  
% 1.60/1.83  Length of proof is 6.  Level of proof is 6.
% 1.60/1.83  
% 1.60/1.83  ---------------- PROOF ----------------
% 1.60/1.83  % SZS status Unsatisfiable
% 1.60/1.83  % SZS output start Refutation
% See solution above
% 1.60/1.83  ------------ end of proof -------------
% 1.60/1.83  
% 1.60/1.83  
% 1.60/1.83  Search stopped by max_proofs option.
% 1.60/1.83  
% 1.60/1.83  
% 1.60/1.83  Search stopped by max_proofs option.
% 1.60/1.83  
% 1.60/1.83  ============ end of search ============
% 1.60/1.83  
% 1.60/1.83  -------------- statistics -------------
% 1.60/1.83  clauses given                  9
% 1.60/1.83  clauses generated            257
% 1.60/1.83  clauses kept                  42
% 1.60/1.83  clauses forward subsumed     216
% 1.60/1.83  clauses back subsumed         39
% 1.60/1.83  Kbytes malloced              976
% 1.60/1.83  
% 1.60/1.83  ----------- times (seconds) -----------
% 1.60/1.83  user CPU time          0.01          (0 hr, 0 min, 0 sec)
% 1.60/1.83  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.60/1.83  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.60/1.83  
% 1.60/1.83  That finishes the proof of the theorem.
% 1.60/1.83  
% 1.60/1.83  Process 24495 finished Wed Jul 27 11:06:56 2022
% 1.60/1.83  Otter interrupted
% 1.60/1.83  PROOF FOUND
%------------------------------------------------------------------------------