TSTP Solution File: SYN000-1 by Twee---2.5.0

View Problem - Process Solution

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% File     : Twee---2.5.0
% Problem  : SYN000-1 : TPTP v8.2.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee /export/starexec/sandbox2/benchmark/theBenchmark.p --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Mon Jun 24 19:56:56 EDT 2024

% Result   : Unsatisfiable 0.11s 0.38s
% Output   : Proof 0.11s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SYN000-1 : TPTP v8.2.0. Released v4.0.0.
% 0.11/0.12  % Command  : parallel-twee /export/starexec/sandbox2/benchmark/theBenchmark.p --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding
% 0.11/0.33  % Computer : n027.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit : 300
% 0.11/0.33  % WCLimit  : 300
% 0.11/0.33  % DateTime : Sun Jun 23 19:40:54 EDT 2024
% 0.11/0.33  % CPUTime  : 
% 0.11/0.38  Command-line arguments: --lhs-weight 1 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10
% 0.11/0.38  
% 0.11/0.38  % SZS status Unsatisfiable
% 0.11/0.38  
% 0.11/0.38  % SZS output start Proof
% 0.11/0.38  Take the following subset of the input axioms:
% 0.11/0.38    fof(role_hypothesis, hypothesis, p(h)).
% 0.11/0.38    fof(role_negated_conjecture, negated_conjecture, ![X]: ~p(X)).
% 0.11/0.38  
% 0.11/0.38  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.11/0.38  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.11/0.38  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.11/0.38    fresh(y, y, x1...xn) = u
% 0.11/0.38    C => fresh(s, t, x1...xn) = v
% 0.11/0.38  where fresh is a fresh function symbol and x1..xn are the free
% 0.11/0.38  variables of u and v.
% 0.11/0.38  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.11/0.38  input problem has no model of domain size 1).
% 0.11/0.38  
% 0.11/0.38  The encoding turns the above axioms into the following unit equations and goals:
% 0.11/0.38  
% 0.11/0.38  Axiom 1 (role_hypothesis): p(h) = true2.
% 0.11/0.38  
% 0.11/0.38  Goal 1 (role_negated_conjecture): p(X) = true2.
% 0.11/0.38  The goal is true when:
% 0.11/0.38    X = h
% 0.11/0.38  
% 0.11/0.38  Proof:
% 0.11/0.38    p(h)
% 0.11/0.38  = { by axiom 1 (role_hypothesis) }
% 0.11/0.38    true2
% 0.11/0.38  % SZS output end Proof
% 0.11/0.38  
% 0.11/0.38  RESULT: Unsatisfiable (the axioms are contradictory).
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