TSTP Solution File: SWW883+1 by Crossbow---0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : SWW883+1 : TPTP v8.1.0. Released v7.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Wed Jul 20 23:27:14 EDT 2022

% Result   : CounterSatisfiable 5.24s 5.42s
% Output   : FiniteModel 5.24s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : SWW883+1 : TPTP v8.1.0. Released v7.3.0.
% 0.03/0.12  % Command    : do_Crossbow---0.1 %s
% 0.12/0.33  % Computer : n029.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit   : 300
% 0.12/0.33  % WCLimit    : 600
% 0.12/0.33  % DateTime   : Sun Jun  5 01:27:03 EDT 2022
% 0.12/0.33  % CPUTime    : 
% 0.12/0.33  /export/starexec/sandbox/solver/bin
% 0.12/0.34  crossbow.opt
% 0.12/0.34  do_Crossbow---0.1
% 0.12/0.34  eprover
% 0.12/0.34  runsolver
% 0.12/0.34  starexec_run_Crossbow---0.1
% 5.24/5.42  % SZS status CounterSatisfiable for theBenchmark.p
% 5.24/5.42  % SZS output start FiniteModel for theBenchmark.p
% 5.24/5.42  % domain size: 2
% 5.24/5.42  fof(interp, fi_domain, ![X] : (X = 0 | X = 1)).
% 5.24/5.42  fof(interp, fi_functors, cF__00 = 1).
% 5.24/5.42  fof(interp, fi_functors, cT__00 = 0).
% 5.24/5.42  fof(interp, fi_functors, c_24exists__01(0) = 0 & c_24exists__01(1) = 0).
% 5.24/5.42  fof(interp, fi_functors, c_27const_2ecfHeapsBase_2eExn_27__01(0) = 0 &
% 5.24/5.42    c_27const_2ecfHeapsBase_2eExn_27__01(1) = 0).
% 5.24/5.42  fof(interp, fi_functors, c_27const_2ecfHeapsBase_2eSEP__IMPPOST_27__02(0, 0) = 1 &
% 5.24/5.42    c_27const_2ecfHeapsBase_2eSEP__IMPPOST_27__02(0, 1) = 1 &
% 5.24/5.42    c_27const_2ecfHeapsBase_2eSEP__IMPPOST_27__02(1, 0) = 1 &
% 5.24/5.42    c_27const_2ecfHeapsBase_2eSEP__IMPPOST_27__02(1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, c_27const_2ecfHeapsBase_2eVal_27__01(0) = 0 &
% 5.24/5.42    c_27const_2ecfHeapsBase_2eVal_27__01(1) = 0).
% 5.24/5.42  fof(interp, fi_functors, c_27const_2eset__sep_2eSEP__IMP_27__02(0, 0) = 0 &
% 5.24/5.42    c_27const_2eset__sep_2eSEP__IMP_27__02(0, 1) = 1 &
% 5.24/5.42    c_27const_2eset__sep_2eSEP__IMP_27__02(1, 0) = 1 &
% 5.24/5.42    c_27const_2eset__sep_2eSEP__IMP_27__02(1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, c_27type_2ecfHeapsBase_2eheap__part_27__00 = 1).
% 5.24/5.42  fof(interp, fi_functors, c_27type_2ecfHeapsBase_2eres_27__00 = 1).
% 5.24/5.42  fof(interp, fi_functors, c_27type_2esemanticPrimitives_2ev_27__00 = 0).
% 5.24/5.42  fof(interp, fi_functors, cbool__00 = 0).
% 5.24/5.42  fof(interp, fi_functors, cfun__02(0, 0) = 1 & cfun__02(0, 1) = 0 &
% 5.24/5.42    cfun__02(1, 0) = 0 &
% 5.24/5.42    cfun__02(1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, chapp__02(0, 0) = 0 & chapp__02(0, 1) = 0 &
% 5.24/5.42    chapp__02(1, 0) = 0 &
% 5.24/5.42    chapp__02(1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, esk1_4(0, 0, 0, 0) = 1 & esk1_4(0, 0, 0, 1) = 1 &
% 5.24/5.42    esk1_4(0, 0, 1, 0) = 1 &
% 5.24/5.42    esk1_4(0, 0, 1, 1) = 0 &
% 5.24/5.42    esk1_4(0, 1, 0, 0) = 0 &
% 5.24/5.42    esk1_4(0, 1, 0, 1) = 1 &
% 5.24/5.42    esk1_4(0, 1, 1, 0) = 1 &
% 5.24/5.42    esk1_4(0, 1, 1, 1) = 0 &
% 5.24/5.42    esk1_4(1, 0, 0, 0) = 1 &
% 5.24/5.42    esk1_4(1, 0, 0, 1) = 0 &
% 5.24/5.42    esk1_4(1, 0, 1, 0) = 0 &
% 5.24/5.42    esk1_4(1, 0, 1, 1) = 1 &
% 5.24/5.42    esk1_4(1, 1, 0, 0) = 1 &
% 5.24/5.42    esk1_4(1, 1, 0, 1) = 0 &
% 5.24/5.42    esk1_4(1, 1, 1, 0) = 0 &
% 5.24/5.42    esk1_4(1, 1, 1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, esk2_3(0, 0, 0) = 0 & esk2_3(0, 0, 1) = 0 &
% 5.24/5.42    esk2_3(0, 1, 0) = 0 &
% 5.24/5.42    esk2_3(0, 1, 1) = 0 &
% 5.24/5.42    esk2_3(1, 0, 0) = 1 &
% 5.24/5.42    esk2_3(1, 0, 1) = 1 &
% 5.24/5.42    esk2_3(1, 1, 0) = 1 &
% 5.24/5.42    esk2_3(1, 1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, esk3_2(0, 0) = 1 & esk3_2(0, 1) = 0 & esk3_2(1, 0) = 1 &
% 5.24/5.42    esk3_2(1, 1) = 1).
% 5.24/5.42  fof(interp, fi_functors, esk4_0 = 0).
% 5.24/5.42  fof(interp, fi_functors, esk5_0 = 0).
% 5.24/5.42  fof(interp, fi_functors, esk6_0 = 1).
% 5.24/5.42  fof(interp, fi_functors, esk7_0 = 0).
% 5.24/5.42  fof(interp, fi_predicates, p__01(0) & ~p__01(1)).
% 5.24/5.42  fof(interp, fi_functors, s__02(0, 0) = 0 & s__02(0, 1) = 1 & s__02(1, 0) = 1 &
% 5.24/5.42    s__02(1, 1) = 0).
% 5.24/5.42  % SZS output end FiniteModel for theBenchmark.p
% 5.24/5.42  % 0 lemma(s) from E
% 5.24/5.42  % 65 pred(s)
% 5.24/5.42  % 48 func(s)
% 5.24/5.42  % 3 sort(s)
% 5.24/5.42  % 113 clause(s)
% 5.24/5.42  % Instantiating 1 (5054 ms)
% 5.24/5.42  % Solving (5054 ms)
% 5.24/5.42  % Instantiating 2 (5054 ms)
% 5.24/5.42  % Solving (5058 ms)
% 5.24/5.42  % 
% 5.24/5.42  % 1 model found (5060 ms)
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