TSTP Solution File: SWW478+1 by Twee---2.5.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Twee---2.5.0
% Problem  : SWW478+1 : TPTP v8.2.0. Released v5.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee /export/starexec/sandbox2/benchmark/theBenchmark.p --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Mon Jun 24 18:27:16 EDT 2024

% Result   : Theorem 3.72s 0.82s
% Output   : Proof 3.72s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SWW478+1 : TPTP v8.2.0. Released v5.3.0.
% 0.04/0.12  % Command  : parallel-twee /export/starexec/sandbox2/benchmark/theBenchmark.p --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding
% 0.12/0.33  % Computer : n003.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jun 19 08:29:54 EDT 2024
% 0.12/0.33  % CPUTime  : 
% 3.72/0.82  Command-line arguments: --random-mode --random-mode-goal-directed --no-flatten-goal --no-connectedness --no-ground-joining
% 3.72/0.82  
% 3.72/0.82  % SZS status Theorem
% 3.72/0.82  
% 3.72/0.83  % SZS output start Proof
% 3.72/0.83  Take the following subset of the input axioms:
% 3.72/0.83    fof(conj_0, conjecture, hBOOL(member773094996on_val(hAPP_P1886180715on_val(hAPP_P1870962205on_val(produc1441475159on_val, hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, ea), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, ha), fun_up1149430426on_val(la, v_1, some_val(v))))), hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, e_a), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, h_a), l_a))), red(p)))).
% 3.72/0.83    fof(fact_1_InitBlockRed_I1_J, axiom, hBOOL(member773094996on_val(hAPP_P1886180715on_val(hAPP_P1870962205on_val(produc1441475159on_val, hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, ea), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, ha), fun_up1149430426on_val(la, v_1, some_val(v))))), hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, e_a), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, h_a), l_a))), red(p)))).
% 3.72/0.83  
% 3.72/0.83  Now clausify the problem and encode Horn clauses using encoding 3 of
% 3.72/0.83  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 3.72/0.83  We repeatedly replace C & s=t => u=v by the two clauses:
% 3.72/0.83    fresh(y, y, x1...xn) = u
% 3.72/0.83    C => fresh(s, t, x1...xn) = v
% 3.72/0.83  where fresh is a fresh function symbol and x1..xn are the free
% 3.72/0.83  variables of u and v.
% 3.72/0.83  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 3.72/0.83  input problem has no model of domain size 1).
% 3.72/0.83  
% 3.72/0.83  The encoding turns the above axioms into the following unit equations and goals:
% 3.72/0.83  
% 3.72/0.83  Axiom 1 (fact_1_InitBlockRed_I1_J): hBOOL(member773094996on_val(hAPP_P1886180715on_val(hAPP_P1870962205on_val(produc1441475159on_val, hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, ea), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, ha), fun_up1149430426on_val(la, v_1, some_val(v))))), hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, e_a), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, h_a), l_a))), red(p))) = true2.
% 3.72/0.83  
% 3.72/0.83  Goal 1 (conj_0): hBOOL(member773094996on_val(hAPP_P1886180715on_val(hAPP_P1870962205on_val(produc1441475159on_val, hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, ea), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, ha), fun_up1149430426on_val(la, v_1, some_val(v))))), hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, e_a), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, h_a), l_a))), red(p))) = true2.
% 3.72/0.83  Proof:
% 3.72/0.83    hBOOL(member773094996on_val(hAPP_P1886180715on_val(hAPP_P1870962205on_val(produc1441475159on_val, hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, ea), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, ha), fun_up1149430426on_val(la, v_1, some_val(v))))), hAPP_P604205461on_val(hAPP_e1659493427on_val(produc1259058957on_val, e_a), hAPP_f1727192346on_val(hAPP_f1849790461on_val(produc899768717on_val, h_a), l_a))), red(p)))
% 3.72/0.83  = { by axiom 1 (fact_1_InitBlockRed_I1_J) }
% 3.72/0.83    true2
% 3.72/0.83  % SZS output end Proof
% 3.72/0.83  
% 3.72/0.83  RESULT: Theorem (the conjecture is true).
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