TSTP Solution File: SWW469_1 by SPASS+T---2.2.22

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS+T---2.2.22
% Problem  : SWW469_1 : TPTP v8.1.0. Released v5.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : spasst-tptp-script %s %d

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 01:30:12 EDT 2022

% Result   : Theorem 0.52s 0.85s
% Output   : Refutation 0.52s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   11 (   9 unt;   0 nHn;  11 RR)
%            Number of literals    :   13 (   0 equ;   5 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   2 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   3 con; 0-0 aty)
%            Number of variables   :    1 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    hoare_1310879719gleton,
    file('SWW469_1.p',unknown),
    [] ).

cnf(5,axiom,
    state(skc7),
    file('SWW469_1.p',unknown),
    [] ).

cnf(8,axiom,
    ~ equal(skc7,skc6),
    file('SWW469_1.p',unknown),
    [] ).

cnf(9,axiom,
    ( ~ hoare_1310879719gleton
    | state(skc6) ),
    file('SWW469_1.p',unknown),
    [] ).

cnf(10,axiom,
    ( ~ state(U)
    | equal(U,skc4) ),
    file('SWW469_1.p',unknown),
    [] ).

cnf(12,plain,
    state(skc6),
    inference(mrr,[status(thm)],[9,1]),
    [iquote('0:MRR:9.0,1.0')] ).

cnf(16,plain,
    equal(skc7,skc4),
    inference(res,[status(thm),theory(equality)],[5,10]),
    [iquote('0:Res:5.0,10.0')] ).

cnf(17,plain,
    equal(skc6,skc4),
    inference(res,[status(thm),theory(equality)],[12,10]),
    [iquote('0:Res:12.0,10.0')] ).

cnf(20,plain,
    ~ equal(skc6,skc4),
    inference(rew,[status(thm),theory(equality)],[16,8]),
    [iquote('0:Rew:16.0,8.0')] ).

cnf(22,plain,
    ~ equal(skc4,skc4),
    inference(rew,[status(thm),theory(equality)],[17,20]),
    [iquote('0:Rew:17.0,20.0')] ).

cnf(23,plain,
    $false,
    inference(obv,[status(thm),theory(equality)],[22]),
    [iquote('0:Obv:22.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.08  % Problem  : SWW469_1 : TPTP v8.1.0. Released v5.3.0.
% 0.00/0.08  % Command  : spasst-tptp-script %s %d
% 0.08/0.27  % Computer : n032.cluster.edu
% 0.08/0.27  % Model    : x86_64 x86_64
% 0.08/0.27  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.27  % Memory   : 8042.1875MB
% 0.08/0.27  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.08/0.27  % CPULimit : 300
% 0.08/0.27  % WCLimit  : 600
% 0.08/0.27  % DateTime : Sun Jun  5 19:23:34 EDT 2022
% 0.12/0.27  % CPUTime  : 
% 0.12/0.37  % Using EUF theory
% 0.52/0.85  
% 0.52/0.85  
% 0.52/0.85  % SZS status Theorem for /tmp/SPASST_16788_n032.cluster.edu
% 0.52/0.85  
% 0.52/0.85  SPASS V 2.2.22  in combination with yices.
% 0.52/0.85  SPASS beiseite: Proof found by SPASS.
% 0.52/0.85  Problem: /tmp/SPASST_16788_n032.cluster.edu 
% 0.52/0.85  SPASS derived 9 clauses, backtracked 0 clauses and kept 13 clauses.
% 0.52/0.85  SPASS backtracked 0 times (0 times due to theory inconsistency).
% 0.52/0.85  SPASS allocated 6331 KBytes.
% 0.52/0.85  SPASS spent	0:00:00.01 on the problem.
% 0.52/0.85  		0:00:00.00 for the input.
% 0.52/0.85  		0:00:00.00 for the FLOTTER CNF translation.
% 0.52/0.85  		0:00:00.00 for inferences.
% 0.52/0.85  		0:00:00.00 for the backtracking.
% 0.52/0.85  		0:00:00.00 for the reduction.
% 0.52/0.85  		0:00:00.00 for interacting with the SMT procedure.
% 0.52/0.85  		
% 0.52/0.85  
% 0.52/0.85  % SZS output start CNFRefutation for /tmp/SPASST_16788_n032.cluster.edu
% See solution above
% 0.52/0.85  
% 0.52/0.85  Formulae used in the proof : fof_conj_0 fof_fact_0_state__not__singleton__def fof_conj_1
% 0.52/0.87  
% 0.52/0.87  SPASS+T ended
%------------------------------------------------------------------------------